General Mathematics (General Mathematics) | 41+ MCQ Quizzes | Category (R/R/A) - SPPMMC

General Mathematics (General Mathematics) | MCQ Quizzes | Category (R/R/A)

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41 quizzes

1999 views

2026-03-22 17:19:10

General Mathematics aims to develop learners' understanding of concepts and techniques drawn from number and algebra, trigonometry and world geometry, sequences, finance, networks and decision mathematics and statistics, in order to solve applied pro
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Category UID: 14

Label UID: 38

Category Name: General Mathematics

Category Full Name: General Mathematics

Category Link/Slug: general-mathematics

Total Quizzes: 41

Total Views: 1999

Last Refreshed: 2026-03-22 17:19:10

Category Description: General Mathematics aims to develop learners' understanding of concepts and techniques drawn from number and algebra, trigonometry and world geometry, sequences, finance, networks and decision mathematics and statistics, in order to solve applied problems.

Q1. A number is as much greater than 22 as is less than 72. Then the number is
Q1. A number is as much greater than 22 as is less than 72. Then the number is

(A) 44
(A) 44
(B) 50
(B) 50
(C) 52
(C) 52
(D) 47
(D) 47
Answer: (D) 47
Answer: (D) 47
47
47

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@898

2024-03-03

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Q2. If 16℅ of 40℅ of a number is 8, then the number is
Q2. If 16℅ of 40℅ of a number is 8, then the number is

(A) 250
(A) 250
(B) 125
(B) 125
(C) 200
(C) 200
(D) 100
(D) 100
Answer: (B) 125
Answer: (B) 125
125
125

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@872

2024-03-03

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Q3. Find the value of the following expression
Q3. Find the value of the following expression

48÷12+4×25÷5

48÷12+4×25÷5
(A) 15
(A) 15
(B) 24
(B) 24
(C) 40
(C) 40
(D) 25
(D) 25
Answer: (B) 24
Answer: (B) 24
24
24

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@675

2024-03-03

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Q4. Find the least number by which 1250 must be multiplied to make it a perfect square.
Q4. Find the least number by which 1250 must be multiplied to make it a perfect square.

(A) 4
(A) 4
(B) 3
(B) 3
(C) 5
(C) 5
(D) 2
(D) 2
Answer: (D) 2
Answer: (D) 2
1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 2500 = 2*5*5 = 50
1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 2500 = 2*5*5 = 50

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@1700

2024-10-23

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Q5. The difference between the smallest 3-digit even natural number and the largest 2-digit even natural number is
Q5. The difference between the smallest 3-digit even natural number and the largest 2-digit even natural number is

(A) 1
(A) 1
(B) 2
(B) 2
(C) 3
(C) 3
(D) 4
(D) 4
Answer: (B) 2
Answer: (B) 2
100 - 98 = 2
100 - 98 = 2

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@1715

2024-10-23

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Q6. 100% of 100 when added to 200% of 200 would result
Q6. 100% of 100 when added to 200% of 200 would result

(A) 300
(A) 300
(B) 400
(B) 400
(C) 500
(C) 500
(D) 600
(D) 600
Answer: (C) 500
Answer: (C) 500
100 * 100% + 200 * 200% = 100×100100 + 200 ×200100 = 10000100 + 40000100 = 100 + 400 = 500
100 * 100% + 200 * 200% = 100×100100 + 200 ×200100 = 10000100 + 40000100 = 100 + 400 = 500

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@1704

2024-10-23

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Q7. Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest?
Q7. Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest?

I. 376 II. 629 III. 921 IV. 397

I. 376 II. 629 III. 921 IV. 397
(A) III
(A) III
(B) II
(B) II
(C) I
(C) I
(D) IV
(D) IV
Answer: (A) III
Answer: (A) III
376 -> 367 629 -> 269 921 -> 129 * 397 -> 379
376 -> 367 629 -> 269 921 -> 129 * 397 -> 379

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@1669

2024-10-23

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Q8. The smallest among 12, 13, 14 and 23 is
Q8. The smallest among 12, 13, 14 and 23 is

(A) 12
(A) 12
(B) 13
(B) 13
(C) 14
(C) 14
(D) 23
(D) 23
Answer: (C) 14
Answer: (C) 14
14
14

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@1691

2024-10-23

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Q9. A ladder of length 13 m is leaning against a vertical wall with the upper end at the height of 5 m. The horizontal distance between the foot of the wall and the lower end of the ladder is
Q9. A ladder of length 13 m is leaning against a vertical wall with the upper end at the height of 5 m. The horizontal distance between the foot of the wall and the lower end of the ladder is

(A) 9m
(A) 9m
(B) 5m
(B) 5m
(C) 11m
(C) 11m
(D) 12m
(D) 12m
Answer: (D) 12m
Answer: (D) 12m
52 + X2 = 132 => 25 + X2 = 169 => X2 = 196 - 25 => X2 = 144 => X = 12
52 + X2 = 132 => 25 + X2 = 169 => X2 = 196 - 25 => X2 = 144 => X = 12

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@1711

2024-10-23

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Q10. In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is
Q10. In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is

(A) 35
(A) 35
(B) 42
(B) 42
(C) 49
(C) 49
(D) 56
(D) 56
Answer: (C) 49
Answer: (C) 49
1+3+5+7+9+11+13 = 49
1+3+5+7+9+11+13 = 49

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@1699

2024-10-23

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Q11. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is
Q11. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is

(A) 1
(A) 1
(B) -1
(B) -1
(C) 2
(C) 2
(D) 3
(D) 3
Answer: (C) 2
Answer: (C) 2
In ascending order = -2, -1, 1, 2, 3, 5, 6 median = 7+12th term = 4th term = 2
In ascending order = -2, -1, 1, 2, 3, 5, 6 median = 7+12th term = 4th term = 2

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@1712

2024-10-23

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Q12. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is
Q12. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is

(A) 25
(A) 25
(B) 45
(B) 45
(C) 32
(C) 32
(D) 27
(D) 27
Answer: (D) 27
Answer: (D) 27
27
27

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@900

2024-03-03

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Q13. 3/4 of a number is 19 less than the original number. The number is
Q13. 3/4 of a number is 19 less than the original number. The number is

(A) 62
(A) 62
(B) 64
(B) 64
(C) 79
(C) 79
(D) 76
(D) 76
Answer: (D) 76
Answer: (D) 76
76
76

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@873

2024-03-03

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Q14. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is
Q14. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is

(A) 16% increase
(A) 16% increase
(B) 16% decrease
(B) 16% decrease
(C) 32% decrease
(C) 32% decrease
(D) No change
(D) No change
Answer: (B) 16% decrease
Answer: (B) 16% decrease
16% decrease = 40-40-40*40100% = -1600100% = -16%
16% decrease = 40-40-40*40100% = -1600100% = -16%

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@1689

2024-10-23

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Q15. If A : B = 3, then 144A : 36B is
Q15. If A : B = 3, then 144A : 36B is

(A) 4
(A) 4
(B) 12
(B) 12
(C) 3
(C) 3
(D) 16
(D) 16
Answer: (B) 12
Answer: (B) 12
A : B = 3 => AB = 3 144A36B = 14436×AB = 14436 x 3 = 4 x 3 = 12
A : B = 3 => AB = 3 144A36B = 14436×AB = 14436 x 3 = 4 x 3 = 12

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@1697

2024-10-23

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Q16. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is
Q16. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is

(A) 55
(A) 55
(B) 0
(B) 0
(C) 270
(C) 270
(D) 45
(D) 45
Answer: (B) 0
Answer: (B) 0
1st Month -> (105 * 2) - 120 = 210 - 120 = 90 2nd Month -> (90 * 2) - 120 = 180 - 120 = 60 3rd Month -> (60 * 2) - 120 = 120 - 120 = 0
1st Month -> (105 * 2) - 120 = 210 - 120 = 90 2nd Month -> (90 * 2) - 120 = 180 - 120 = 60 3rd Month -> (60 * 2) - 120 = 120 - 120 = 0

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@1695

2024-10-23

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Q17. The sum of two numbers is 15 and the sum of their squares is 113. The numbers are
Q17. The sum of two numbers is 15 and the sum of their squares is 113. The numbers are

(A) 4 and 10
(A) 4 and 10
(B) 6 and 9
(B) 6 and 9
(C) 5 and 10
(C) 5 and 10
(D) 7 and 8
(D) 7 and 8
Answer: (D) 7 and 8
Answer: (D) 7 and 8
7 and 8
7 and 8

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@674

2024-03-03

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Q18. If X3=Y4=Z7, then X+Y+ZZ is equal to
Q18. If X3=Y4=Z7, then X+Y+ZZ is equal to

(A) 2
(A) 2
(B) 3
(B) 3
(C) 4
(C) 4
(D) 5
(D) 5
Answer: (A) 2
Answer: (A) 2
X3=Y4=Z7 Hence, X:Y:Z = 3:4:7 X+Y+ZZ = 3+4+77 = 147 = 2
X3=Y4=Z7 Hence, X:Y:Z = 3:4:7 X+Y+ZZ = 3+4+77 = 147 = 2

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@1692

2024-10-23

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Q19. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.
Q19. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.

(A) 25 years
(A) 25 years
(B) 35 years
(B) 35 years
(C) 50 years
(C) 50 years
(D) 45 years
(D) 45 years
Answer: (A) 25 years
Answer: (A) 25 years
25 years => A+B+C = 22*3 => A+(B+C) = 66 => A+(25*2) = 66 => A = 66-50 => A = 16 After 9 years A = 16+9 = 25 years
25 years => A+B+C = 22*3 => A+(B+C) = 66 => A+(25*2) = 66 => A = 66-50 => A = 16 After 9 years A = 16+9 = 25 years

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@1690

2024-10-23

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Q20. Three numbers are in the ratio 3:4:5. The sum of the largest and the smallest equals the sum of the third and 52. The smallest number is
Q20. Three numbers are in the ratio 3:4:5. The sum of the largest and the smallest equals the sum of the third and 52. The smallest number is

(A) 48
(A) 48
(B) 36
(B) 36
(C) 39
(C) 39
(D) 30
(D) 30
Answer: (C) 39
Answer: (C) 39
39
39

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26646 views

@899

2024-03-03

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