A number is as much greater than 22 as is less than 72. Then the number is [#898]
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Q1. A number is as much greater than 22 as is less than 72. Then the number is
Q1. A number is as much greater than 22 as is less than 72. Then the number is
(A) 44
(A) 44
(A) 44
(B) 50
(B) 50
(B) 50
(C) 52
(C) 52
(C) 52
(D) 47
(D) 47
(D) 47
Answer: (D) 47
Answer: (D) 47
Answer: (D) 47
47
47
47
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Related MCQ Quizzes
Q1. What is the term for a number that has no decimal places or fractional part?
Q1. What is the term for a number that has no decimal places or fractional part?
(A) Integer
(A) Integer
(A) Integer
(B) Fraction
(B) Fraction
(B) Fraction
(C) Decimal
(C) Decimal
(C) Decimal
(D) Percentage
(D) Percentage
(D) Percentage
Answer: (A) Integer
Answer: (A) Integer
Answer: (A) Integer
An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.
An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.
An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.
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Q2. The smallest positive integer that is simultaneously divisible by 6, 8 and 12 is
Q2. The smallest positive integer that is simultaneously divisible by 6, 8 and 12 is
(A) 24
(A) 24
(A) 24
(B) 18
(B) 18
(B) 18
(C) 48
(C) 48
(C) 48
(D) 36
(D) 36
(D) 36
Answer: (A) 24
Answer: (A) 24
Answer: (A) 24
6*4 = 24
8*3 = 24
12*2 = 24
6*4 = 24 8*3 = 24 12*2 = 24
6*4 = 24 8*3 = 24 12*2 = 24
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Q3. The value of is :
Q3. The value of is :
(A) 1.73
(A) 1.73
(A) 1.73
(B) 2.03
(B) 2.03
(B) 2.03
(C) 2.73
(C) 2.73
(C) 2.73
(D) 1.03
(D) 1.03
(D) 1.03
Answer: (C) 2.73
Answer: (C) 2.73
Answer: (C) 2.73
=
=
= 0.2 + 1.2 + 1.3 + 0.03
= 2.73
= = = 0.2 + 1.2 + 1.3 + 0.03 = 2.73
= = = 0.2 + 1.2 + 1.3 + 0.03 = 2.73
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Q4. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :
Q4. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :
(A) 2 : 3
(A) 2 : 3
(A) 2 : 3
(B) 3 : 5
(B) 3 : 5
(B) 3 : 5
(C) 3 : 2
(C) 3 : 2
(C) 3 : 2
(D) 2 : 5
(D) 2 : 5
(D) 2 : 5
Answer: (A) 2 : 3
Answer: (A) 2 : 3
Answer: (A) 2 : 3
=
=
= X:Y = 2:3
= = = X:Y = 2:3
= = = X:Y = 2:3
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Q5. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
Q5. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
(A) 5
(A) 5
(A) 5
(B) 7
(B) 7
(B) 7
(C) 10
(C) 10
(C) 10
(D) 14
(D) 14
(D) 14
Answer: (B) 7
Answer: (B) 7
Answer: (B) 7
7
=> x * 2x = 98
=> x2 =
=> x2 = 49
=> x = 7
7 => x * 2x = 98 => x2 = => x2 = 49 => x = 7
7 => x * 2x = 98 => x2 = => x2 = 49 => x = 7
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Q6. What is the value of x in the equation 2x + 5 = 11?
Q6. What is the value of x in the equation 2x + 5 = 11?
(A) 2
(A) 2
(A) 2
(B) 3
(B) 3
(B) 3
(C) 4
(C) 4
(C) 4
(D) 5
(D) 5
(D) 5
Answer: (B) 3
Answer: (B) 3
Answer: (B) 3
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
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Q7. Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is
Q7. Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is
(A) 2 : 5
(A) 2 : 5
(A) 2 : 5
(B) 3 : 5
(B) 3 : 5
(B) 3 : 5
(C) 4 : 5
(C) 4 : 5
(C) 4 : 5
(D) 7 : 5
(D) 7 : 5
(D) 7 : 5
Answer: (C) 4 : 5
Answer: (C) 4 : 5
Answer: (C) 4 : 5
4 : 5
4 : 5
4 : 5
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Q8. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :
Q8. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :
(A) 5,420
(A) 5,420
(A) 5,420
(B) 5,580
(B) 5,580
(B) 5,580
(C) 5,620
(C) 5,620
(C) 5,620
(D) 5,780
(D) 5,780
(D) 5,780
Answer: (B) 5,580
Answer: (B) 5,580
Answer: (B) 5,580
The formula for the sum of the first n terms of an arithmetic progression is
= 15*(12+360)
= 15 * 372
= 5580
The formula for the sum of the first n terms of an arithmetic progression is = 15*(12+360) = 15 * 372 = 5580
The formula for the sum of the first n terms of an arithmetic progression is = 15*(12+360) = 15 * 372 = 5580
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Q9. The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is
Q9. The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is
(A) 17
(A) 17
(A) 17
(B) 21
(B) 21
(B) 21
(C) 23
(C) 23
(C) 23
(D) 19
(D) 19
(D) 19
Answer: (C) 23
Answer: (C) 23
Answer: (C) 23
X + (X+2) + (X+4) + (X+6) + (X+8) = 95
=> 5X + 20 = 95
=> 5X = 95-20
=> 5X = 75
=> X = 15
Hence (X+8) = 15+8 = 23
X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23
X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23
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Q10. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is
Q10. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is
(A) 1
(A) 1
(A) 1
(B) -1
(B) -1
(B) -1
(C) 2
(C) 2
(C) 2
(D) 3
(D) 3
(D) 3
Answer: (C) 2
Answer: (C) 2
Answer: (C) 2
In ascending order = -2, -1, 1, 2, 3, 5, 6
median = th term
= 4th term
= 2
In ascending order = -2, -1, 1, 2, 3, 5, 6 median = th term = 4th term = 2
In ascending order = -2, -1, 1, 2, 3, 5, 6 median = th term = 4th term = 2
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Related Questions
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