4/5 of a number is 64. Then half of the number is [#876]

40

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40

$\frac{45}{100}*X = \frac{30}{100} * Y$ = $\frac{X}{Y} = \frac{30*100}{100*45}$ = $\frac{X}{Y} = \frac{2}{3}$ = X:Y = 2:3

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$\frac{45}{100}*X = \frac{30}{100} * Y$ = $\frac{X}{Y} = \frac{30*100}{100*45}$ = $\frac{X}{Y} = \frac{2}{3}$ = X:Y = 2:3

12 ---- x 60 = 48 KMPH 15

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12 ---- x 60 = 48 KMPH 15

An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.

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An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.

The formula for the sum of the first n terms of an arithmetic progression is $S_n\mathit{ }\mathit{=}\mathit{ }\frac{n}{2}(a+an)$ $\frac{30}{2}(12+12*30)$ = 15*(12+360) = 15 * 372 = 5580

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The formula for the sum of the first n terms of an arithmetic progression is $S_n\mathit{ }\mathit{=}\mathit{ }\frac{n}{2}(a+an)$ $\frac{30}{2}(12+12*30)$ = 15*(12+360) = 15 * 372 = 5580

376 -> 367 629 -> 269 921 -> 129 * 397 -> 379

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376 -> 367 629 -> 269 921 -> 129 * 397 -> 379

17 which is a Prime number.

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17 which is a Prime number.

A : B = 3 => $\frac{A}{B}$ = 3 $\frac{144A}{36B}$ = $\frac{144}{36}\times \frac{A}{B}$ = $\frac{144}{36}$ x 3 = 4 x 3 = 12

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A : B = 3 => $\frac{A}{B}$ = 3 $\frac{144A}{36B}$ = $\frac{144}{36}\times \frac{A}{B}$ = $\frac{144}{36}$ x 3 = 4 x 3 = 12

In geometry, a vertex (plural: vertices) is the point where two or more lines, rays, or edges meet, like the corner of a triangle or the point where two streets intersect.

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In geometry, a vertex (plural: vertices) is the point where two or more lines, rays, or edges meet, like the corner of a triangle or the point where two streets intersect.

20% = $\frac{25}{100+25} * 100$% $\frac{25}{125} * 100$% = 20%

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20% = $\frac{25}{100+25} * 100$% $\frac{25}{125} * 100$% = 20%

A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

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A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km