When three times of a given number is subtracted from the square of the number, the result is the number itself. The number is [#1709]

42 - (4*3) = 16 - 12 = 4

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4^{2 - (4*3) = 16 - 12 = 4}

2

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2

11

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11

47

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47

A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

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A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

5 : (5² + 2) = 5 : 27 Hence 9 : (9² + 2) = 9 : 83

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5 : (5² + 2) = 5 : 27 Hence 9 : (9² + 2) = 9 : 83

A bisector is a line that divides a shape into two equal parts, like a line that cuts a triangle into two equal areas or a line that divides a circle into two equal parts (semi-circles).

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A bisector is a line that divides a shape into two equal parts, like a line that cuts a triangle into two equal areas or a line that divides a circle into two equal parts (semi-circles).

$\frac{3}{2}$ >$\frac{3}{2}\times \frac{4}{9}$ = $\frac{12}{18}$ = $\frac{2}{3}$

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$\frac{3}{2}$ >$\frac{3}{2}\times \frac{4}{9}$ = $\frac{12}{18}$ = $\frac{2}{3}$

The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13

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The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13

1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 $\sqrt{2500}$ = 2*5*5 = 50

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1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 $\sqrt{2500}$ = 2*5*5 = 50

16% decrease = 40-40-$\frac{40*40}{100}$% = -$\frac{1600}{100}$% = -16%

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16% decrease = 40-40-$\frac{40*40}{100}$% = -$\frac{1600}{100}$% = -16%