General Mathematics (General Mathematics) | MCQ Quizzes | Category (T/R/M)
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41 quizzes
1050 views
2025-06-15 23:07:56
General Mathematics aims to develop learners' understanding of concepts and techniques drawn from number and algebra, trigonometry and world geometry, sequences, finance, networks and decision mathematics and statistics, in order to solve applied pro
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Category UID: 14
Label UID: 38
Category Name: General Mathematics
Category Full Name: General Mathematics
Category Link/Slug: general-mathematics
Total Quizzes: 41
Total Views: 1050
Last Refreshed: 2025-06-15 23:07:56
Category Description: General Mathematics aims to develop learners' understanding of concepts and techniques drawn from number and algebra, trigonometry and world geometry, sequences, finance, networks and decision mathematics and statistics, in order to solve applied problems.
Q1. If 16℅ of 40℅ of a number is 8, then the number is
Q1. If 16℅ of 40℅ of a number is 8, then the number is
Answer: (B) 125
Answer: (B) 125
Answer: (B) 125
125
125
125
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Q2. 4/5 of a number is 64. Then half of the number is
Q2. 4/5 of a number is 64. Then half of the number is
Answer: (D) 40
Answer: (D) 40
Answer: (D) 40
40
40
40
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Q3. If 2x = 32, then the value of x is
Q3. If 2x = 32, then the value of x is
Answer: (B) 5
Answer: (B) 5
Answer: (B) 5
25 = 2*2*2*2*2 = 32
25 = 2*2*2*2*2 = 32
25 = 2*2*2*2*2 = 32
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Q4. The value of is
Q4. The value of is
Answer: (D) 4
Answer: (D) 4
Answer: (D) 4
=
=
= 4
= = = 4
= = = 4
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Q5. Find the least number by which 1250 must be multiplied to make it a perfect square.
Q5. Find the least number by which 1250 must be multiplied to make it a perfect square.
Answer: (D) 2
Answer: (D) 2
Answer: (D) 2
1250 = 2*5*5*5*5
1250*2 = 2*2*5*5*5*5 = 2500
= 2*5*5 = 50
1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 = 2*5*5 = 50
1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 = 2*5*5 = 50
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Q6. 3/4 of a number is 19 less than the original number. The number is
Q6. 3/4 of a number is 19 less than the original number. The number is
Answer: (D) 76
Answer: (D) 76
Answer: (D) 76
76
76
76
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Q7. The sum of two numbers is 15 and the sum of their squares is 113. The numbers are
Q7. The sum of two numbers is 15 and the sum of their squares is 113. The numbers are
Answer: (D) 7 and 8
Answer: (D) 7 and 8
Answer: (D) 7 and 8
7 and 8
7 and 8
7 and 8
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Q8. Three numbers are in the ratio 3:4:5. The sum of the largest and the smallest equals the sum of the third and 52. The smallest number is
Q8. Three numbers are in the ratio 3:4:5. The sum of the largest and the smallest equals the sum of the third and 52. The smallest number is
Answer: (C) 39
Answer: (C) 39
Answer: (C) 39
39
39
39
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Q9. 100% of 100 when added to 200% of 200 would result
Q9. 100% of 100 when added to 200% of 200 would result
Answer: (C) 500
Answer: (C) 500
Answer: (C) 500
100 * 100% + 200 * 200%
=
=
= 100 + 400
= 500
100 * 100% + 200 * 200% = = = 100 + 400 = 500
100 * 100% + 200 * 200% = = = 100 + 400 = 500
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Q10. The smallest among is
Q10. The smallest among is
Answer: (C)
Answer: (C)
Answer: (C)
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Q11. If A : B = 3, then 144A : 36B is
Q11. If A : B = 3, then 144A : 36B is
Answer: (B) 12
Answer: (B) 12
Answer: (B) 12
A : B = 3
=> = 3
=
= x 3
= 4 x 3
= 12
A : B = 3 => = 3 = = x 3 = 4 x 3 = 12
A : B = 3 => = 3 = = x 3 = 4 x 3 = 12
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Q12. Three numbers are in the ratio 3:4:6 and their product is 1944. The largest of the numbers is.
Q12. Three numbers are in the ratio 3:4:6 and their product is 1944. The largest of the numbers is.
Answer: (C) 18
Answer: (C) 18
Answer: (C) 18
18
18
18
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Q13. In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is
Q13. In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is
Answer: (C) 49
Answer: (C) 49
Answer: (C) 49
1+3+5+7+9+11+13 = 49
1+3+5+7+9+11+13 = 49
1+3+5+7+9+11+13 = 49
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Q14. The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is
Q14. The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is
Answer: (C) 23
Answer: (C) 23
Answer: (C) 23
X + (X+2) + (X+4) + (X+6) + (X+8) = 95
=> 5X + 20 = 95
=> 5X = 95-20
=> 5X = 75
=> X = 15
Hence (X+8) = 15+8 = 23
X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23
X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23
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Q15. If the decimal number 34p5 is divisible by 9, then the value of p is
Q15. If the decimal number 34p5 is divisible by 9, then the value of p is
Answer: (D) 6
Answer: (D) 6
Answer: (D) 6
34p5 -> 3+4+p+5 = 12+p
12+p = 9k
12+6 = 18 = 9k
p = 6
34p5 -> 3+4+p+5 = 12+p 12+p = 9k 12+6 = 18 = 9k p = 6
34p5 -> 3+4+p+5 = 12+p 12+p = 9k 12+6 = 18 = 9k p = 6
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Q16. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is
Q16. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is
Answer: (B) 16% decrease
Answer: (B) 16% decrease
Answer: (B) 16% decrease
16% decrease
= 40-40-%
= -%
= -16%
16% decrease = 40-40-% = -% = -16%
16% decrease = 40-40-% = -% = -16%
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Q17. A person moves along a path such that he is always away from a given point by 7 m. After moving for some time, he again reaches his starting point. The approximate distance the person moved during the time is
Q17. A person moves along a path such that he is always away from a given point by 7 m. After moving for some time, he again reaches his starting point. The approximate distance the person moved during the time is
Answer: (B) 44 m
Answer: (B) 44 m
Answer: (B) 44 m
2 * * 7
= 2 * 22
= 44
2 * * 7 = 2 * 22 = 44
2 * * 7 = 2 * 22 = 44
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Q18. The largest of 26, 35, 44 and 53 is
Q18. The largest of 26, 35, 44 and 53 is
Answer: (C) 44
Answer: (C) 44
Answer: (C) 44
26 = 64
35 = 243
44 = 256
53 = 125
26 = 64 35 = 243 44 = 256 53 = 125
26 = 64 35 = 243 44 = 256 53 = 125
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Q19. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is
Q19. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is
Answer: (B) 20
Answer: (B) 20
Answer: (B) 20
2:3 = 8:12
N1*N2 = HCF*LCM
8*12 = 96
N1+N2 = 8+12 = 20
2:3 = 8:12 N1*N2 = HCF*LCM 8*12 = 96 N1+N2 = 8+12 = 20
2:3 = 8:12 N1*N2 = HCF*LCM 8*12 = 96 N1+N2 = 8+12 = 20
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Q20. The product of two consecutive odd numbers is 19043. Which is the smaller number?
Q20. The product of two consecutive odd numbers is 19043. Which is the smaller number?
Answer: (C) 137
Answer: (C) 137
Answer: (C) 137
137
137
137
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