The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is [#1706]

X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23

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X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23

The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.

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The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.

5

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5

11

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11

$\sqrt[3]{8^2}$ = $\sqrt[3]{64}$ = $\sqrt[3]{4^3}$ = 4

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$\sqrt[3]{8^2}$ = $\sqrt[3]{64}$ = $\sqrt[3]{4^3}$ = 4

25 years + (3*10) years = 55 years

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25 years + (3*10) years = 55 years

5 : (5² + 2) = 5 : 27 Hence 9 : (9² + 2) = 9 : 83

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5 : (5² + 2) = 5 : 27 Hence 9 : (9² + 2) = 9 : 83

100 * 100% + 200 * 200% = $100\times \frac{100}{100} + 200 \times \frac{200}{100}$ = $\frac{10000}{100} + \frac{40000}{100}$ = 100 + 400 = 500

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100 * 100% + 200 * 200% = $100\times \frac{100}{100} + 200 \times \frac{200}{100}$ = $\frac{10000}{100} + \frac{40000}{100}$ = 100 + 400 = 500

10 m

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10 m

43

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43

7 and 8

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7 and 8