Unmemorable (Non Memory Based) | MCQ Quizzes | Category (T/R/M)
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Category UID: 18
Label UID: 42
Category Name: Unmemorable
Category Full Name: Non Memory Based
Category Link/Slug: unmemorable
Total Quizzes: 57
Total Views: 1686
Last Refreshed: 2026-06-16 22:37:53
Category Description: This category is for the informations which we can't memorise.
Q1. The angles of a quadrilateral are in the ratio of 1 : 3 : 4 : 7. The difference between the largest and the smallest angle is
Q1. The angles of a quadrilateral are in the ratio of 1 : 3 : 4 : 7. The difference between the largest and the smallest angle is
Answer: (C) 144°
Answer: (C) 144°
Answer: (C) 144°
(360°/15) * (7-1) = 144°
(360°/15) * (7-1) = 144°
(360°/15) * (7-1) = 144°
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Q2. If '÷' means ‘addition’, ‘+’ means ‘subtraction’, ‘–’ means ‘multiplication’ and ‘×’ means ‘division’, then the value of 18 ÷ 12 × 4 – 5 is
Q2. If '÷' means ‘addition’, ‘+’ means ‘subtraction’, ‘–’ means ‘multiplication’ and ‘×’ means ‘division’, then the value of 18 ÷ 12 × 4 – 5 is
Answer: (D) 33
Answer: (D) 33
Answer: (D) 33
33
33
33
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Q3. When the numerator of a fraction increases by 3, the fraction increases by its three-fourth. The numerator of the fraction is
Q3. When the numerator of a fraction increases by 3, the fraction increases by its three-fourth. The numerator of the fraction is
Answer: (B) 4
Answer: (B) 4
Answer: (B) 4
4
4
4
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Q4. 4/5 of a number is 64. Then half of the number is
Q4. 4/5 of a number is 64. Then half of the number is
Answer: (D) 40
Answer: (D) 40
Answer: (D) 40
40
40
40
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Q5. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is
Q5. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is
Answer: (D) 27
Answer: (D) 27
Answer: (D) 27
27
27
27
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Q6. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q6. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Answer: (C) 1.2 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
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Q7. 3/4 of a number is 19 less than the original number. The number is
Q7. 3/4 of a number is 19 less than the original number. The number is
Answer: (D) 76
Answer: (D) 76
Answer: (D) 76
76
76
76
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Q8. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?
Q8. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?
Answer: (B) 120
Answer: (B) 120
Answer: (B) 120
120
120
120
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Q9. The least number by which 2450 must be multiplied to make it a perfect square, is
Q9. The least number by which 2450 must be multiplied to make it a perfect square, is
Answer: (A) 2
Answer: (A) 2
Answer: (A) 2
2
2
2
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Q10. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be
Q10. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be
Answer: (C) 5
Answer: (C) 5
Answer: (C) 5
5
5
5
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Q11. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :
Q11. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :
Answer: (A) 2 : 3
Answer: (A) 2 : 3
Answer: (A) 2 : 3
=
=
= X:Y = 2:3
= = = X:Y = 2:3
= = = X:Y = 2:3
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Q12. Find the odd number - 15, 17, 6, 12.
Q12. Find the odd number - 15, 17, 6, 12.
Answer: (D) 17
Answer: (D) 17
Answer: (D) 17
17 which is a Prime number.
17 which is a Prime number.
17 which is a Prime number.
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Q13. A number when divided by 6 is diminished by 40. The number is
Q13. A number when divided by 6 is diminished by 40. The number is
Answer: (B) 48
Answer: (B) 48
Answer: (B) 48
48
48
48
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Q14. The remainder when –76 is divided by 3, is
Q14. The remainder when –76 is divided by 3, is
Answer: (C) 2
Answer: (C) 2
Answer: (C) 2
2
Because, Reminder must be positive and it should be less then the divisor
2 Because, Reminder must be positive and it should be less then the divisor
2 Because, Reminder must be positive and it should be less then the divisor
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Q15. If the sum of five consecutive numbers is 190, then the lowest number amongst them is
Q15. If the sum of five consecutive numbers is 190, then the lowest number amongst them is
Answer: (D) 36
Answer: (D) 36
Answer: (D) 36
36
36
36
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Q16. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
Q16. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
Answer: (B) 7
Answer: (B) 7
Answer: (B) 7
7
=> x * 2x = 98
=> x2 =
=> x2 = 49
=> x = 7
7 => x * 2x = 98 => x2 = => x2 = 49 => x = 7
7 => x * 2x = 98 => x2 = => x2 = 49 => x = 7
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Q17. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is
Q17. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is
Answer: (D) 11
Answer: (D) 11
Answer: (D) 11
11
11
11
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Q18. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Q18. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Answer: (D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
The son becomes 15 years old after 3 years.
Hence son's present age = 15 years - 3 years = 12 years
Man is four times as old as his son.
Hence Man's present age = 12 years * 4 = 48 years
Man is 3 years older than his wife.
Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
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Q19. What is the value of x in the equation 2x + 5 = 11?
Q19. What is the value of x in the equation 2x + 5 = 11?
Answer: (B) 3
Answer: (B) 3
Answer: (B) 3
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
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Q20. Shyam stored Rs 35 in the form of 1 rupee coin and 50 paise coins in the ratio 2 : 3. The number of 50 paise coins are
Q20. Shyam stored Rs 35 in the form of 1 rupee coin and 50 paise coins in the ratio 2 : 3. The number of 50 paise coins are
Answer: (C) 30
Answer: (C) 30
Answer: (C) 30
1*20 + 0.5*30 = 20+15 = 35
1*20 + 0.5*30 = 20+15 = 35
1*20 + 0.5*30 = 20+15 = 35
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