Unmemorable (Non Memory Based) | 57+ MCQ Quizzes | Category (T/R/M) - SPPMMC

Unmemorable (Non Memory Based) | MCQ Quizzes | Category (T/R/M)

@18

57 quizzes

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2025-07-30 14:47:20

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Category UID: 18

Label UID: 42

Category Name: Unmemorable

Category Full Name: Non Memory Based

Category Link/Slug: unmemorable

Total Quizzes: 57

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Last Refreshed: 2025-07-30 14:47:20

Category Description: This category is for the informations which we can't memorise.

Q1. What is the value of x in the equation 2x + 5 = 11?
Q1. What is the value of x in the equation 2x + 5 = 11?

(A) 2
(A) 2
(B) 3
(B) 3
(C) 4
(C) 4
(D) 5
(D) 5
Answer: (B) 3
Answer: (B) 3
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.

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@1256

2024-07-02

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Q2. If '÷' means ‘addition’, ‘+’ means ‘subtraction’, ‘–’ means ‘multiplication’ and ‘×’ means ‘division’, then the value of 18 ÷ 12 × 4 – 5 is
Q2. If '÷' means ‘addition’, ‘+’ means ‘subtraction’, ‘–’ means ‘multiplication’ and ‘×’ means ‘division’, then the value of 18 ÷ 12 × 4 – 5 is

(A) 25
(A) 25
(B) 35
(B) 35
(C) 40
(C) 40
(D) 33
(D) 33
Answer: (D) 33
Answer: (D) 33
33
33

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@1014

2024-04-13

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Q3. The sum of first 6 prime numbers is
Q3. The sum of first 6 prime numbers is

(A) 40
(A) 40
(B) 43
(B) 43
(C) 41
(C) 41
(D) 42
(D) 42
Answer: (C) 41
Answer: (C) 41
41
41

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@661

2024-03-03

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Q4. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is
Q4. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is

(A) 25
(A) 25
(B) 45
(B) 45
(C) 32
(C) 32
(D) 27
(D) 27
Answer: (D) 27
Answer: (D) 27
27
27

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@900

2024-03-03

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Q5. Three fourth of a number is more than two third of the number by 5. Then the number is
Q5. Three fourth of a number is more than two third of the number by 5. Then the number is

(A) 72
(A) 72
(B) 60
(B) 60
(C) 80
(C) 80
(D) 48
(D) 48
Answer: (B) 60
Answer: (B) 60
60
60

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@875

2024-03-03

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Q6. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :
Q6. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :

(A) 2 : 3
(A) 2 : 3
(B) 3 : 5
(B) 3 : 5
(C) 3 : 2
(C) 3 : 2
(D) 2 : 5
(D) 2 : 5
Answer: (A) 2 : 3
Answer: (A) 2 : 3
45100*X = 30100 * Y = XY = 30*100100*45 = XY = 23 = X:Y = 2:3
45100*X = 30100 * Y = XY = 30*100100*45 = XY = 23 = X:Y = 2:3

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@1118

2024-05-09

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Q7. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?
Q7. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?

(A) 120 sec
(A) 120 sec
(B) 100 sec
(B) 100 sec
(C) 60 sec
(C) 60 sec
(D) 50 sec
(D) 50 sec
Answer: (D) 50 sec
Answer: (D) 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec

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@1132

2024-05-15

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Q8. The missing term in the sequence 7, 11, 19, 31, ______, 67 is
Q8. The missing term in the sequence 7, 11, 19, 31, ______, 67 is

(A) 43
(A) 43
(B) 47
(B) 47
(C) 51
(C) 51
(D) 45
(D) 45
Answer: (B) 47
Answer: (B) 47
47
47

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@1015

2024-04-13

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Q9. The conversion of 0.037 in the fractional form is
Q9. The conversion of 0.037 in the fractional form is

(A) 37100
(A) 37100
(B) 37999
(B) 37999
(C) 37990
(C) 37990
(D) 371000
(D) 371000
Answer: (C) 37990
Answer: (C) 37990
37990
37990

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@1032

2024-04-20

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Q10. 4/5 of a number is 64. Then half of the number is
Q10. 4/5 of a number is 64. Then half of the number is

(A) 16
(A) 16
(B) 80
(B) 80
(C) 32
(C) 32
(D) 40
(D) 40
Answer: (D) 40
Answer: (D) 40
40
40

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@876

2024-03-03

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Q11. A 20 m long ladder is leaning on a vertical wall. It makes an angle of 30° with the ground. The height of the point the ladder touches wall is
Q11. A 20 m long ladder is leaning on a vertical wall. It makes an angle of 30° with the ground. The height of the point the ladder touches wall is

(A) 10 m
(A) 10 m
(B) 17.32 m
(B) 17.32 m
(C) 8.16 m
(C) 8.16 m
(D) 13 m
(D) 13 m
Answer: (A) 10 m
Answer: (A) 10 m
10 m
10 m

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@1022

2024-04-19

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Q12. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :
Q12. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :

(A) 5,420
(A) 5,420
(B) 5,580
(B) 5,580
(C) 5,620
(C) 5,620
(D) 5,780
(D) 5,780
Answer: (B) 5,580
Answer: (B) 5,580
The formula for the sum of the first n terms of an arithmetic progression is Sn = n2(a+an) 302(12+12*30) = 15*(12+360) = 15 * 372 = 5580
The formula for the sum of the first n terms of an arithmetic progression is Sn = n2(a+an) 302(12+12*30) = 15*(12+360) = 15 * 372 = 5580

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@1119

2024-05-09

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Q13. Find the value of 225729-25144-1681
Q13. Find the value of 225729-25144-1681

(A) -59
(A) -59
(B) -712
(B) -712
(C) -2027
(C) -2027
(D) -1136
(D) -1136
Answer: (D) -1136
Answer: (D) -1136
225729-25144-1681 = 15*1527*27-5*512*12-4*49*9 = 1527-512-49 = 60-45-48108 = -33108 = -1136
225729-25144-1681 = 15*1527*27-5*512*12-4*49*9 = 1527-512-49 = 60-45-48108 = -33108 = -1136

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@1121

2024-05-09

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Q14. The LCM of two numbers is 40 and their HCF is 4. If the difference between the two numbers is 12, then the sum of the numbers is
Q14. The LCM of two numbers is 40 and their HCF is 4. If the difference between the two numbers is 12, then the sum of the numbers is

(A) 20
(A) 20
(B) 24
(B) 24
(C) 28
(C) 28
(D) 32
(D) 32
Answer: (C) 28
Answer: (C) 28
X * (X-12) = 40 * 4 X = 20 X + (X-12) = 20 + 20 - 12 = 28
X * (X-12) = 40 * 4 X = 20 X + (X-12) = 20 + 20 - 12 = 28

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@1087

2024-05-01

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Q15. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
Q15. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is

(A) 13
(A) 13
(B) 11
(B) 11
(C) 16
(C) 16
(D) 9
(D) 9
Answer: (A) 13
Answer: (A) 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13

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@1109

2024-05-09

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Q16. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q16. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :

(A) 1.5 km
(A) 1.5 km
(B) 1.75 km
(B) 1.75 km
(C) 1.2 km
(C) 1.2 km
(D) 1.25 km
(D) 1.25 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

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@1122

2024-05-15

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Q17. Find the value of the following expression
Q17. Find the value of the following expression

48÷12+4×25÷5

48÷12+4×25÷5
(A) 15
(A) 15
(B) 24
(B) 24
(C) 40
(C) 40
(D) 25
(D) 25
Answer: (B) 24
Answer: (B) 24
24
24

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@675

2024-03-03

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Q18. A hostel has 120 students and food supplies are for 45 days. If 30 more students joined the hostel, then how many days the hostel will run with the existing food?
Q18. A hostel has 120 students and food supplies are for 45 days. If 30 more students joined the hostel, then how many days the hostel will run with the existing food?

(A) 40 days
(A) 40 days
(B) 38 days
(B) 38 days
(C) 36 days
(C) 36 days
(D) 32 days
(D) 32 days
Answer: (C) 36 days
Answer: (C) 36 days
36 days
36 days

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@1021

2024-04-19

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Q19. The least number by which 2450 must be multiplied to make it a perfect square, is
Q19. The least number by which 2450 must be multiplied to make it a perfect square, is

(A) 2
(A) 2
(B) 3
(B) 3
(C) 4
(C) 4
(D) 5
(D) 5
Answer: (A) 2
Answer: (A) 2
2
2

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@1028

2024-04-19

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Q20. A number when divided by 6 is diminished by 40. The number is
Q20. A number when divided by 6 is diminished by 40. The number is

(A) 72
(A) 72
(B) 48
(B) 48
(C) 60
(C) 60
(D) 84
(D) 84
Answer: (B) 48
Answer: (B) 48
48
48

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957 views

@871

2024-03-03

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