Unmemorable (Non Memory Based) | MCQ Quizzes | Category (R/R/M)
@18
•57 quizzes
•822 views
•2025-07-31 04:34:33
•
This category is for the informations which we can't memorise.
Test your Knowledge
Category UID: 18
Label UID: 42
Category Name: Unmemorable
Category Full Name: Non Memory Based
Category Link/Slug: unmemorable
Total Quizzes: 57
Total Views: 822
Last Refreshed: 2025-07-31 04:34:33
Category Description: This category is for the informations which we can't memorise.
Q1. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Q1. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Answer: (D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
The son becomes 15 years old after 3 years.
Hence son's present age = 15 years - 3 years = 12 years
Man is four times as old as his son.
Hence Man's present age = 12 years * 4 = 48 years
Man is 3 years older than his wife.
Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q2. Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is
Q2. Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is
Answer: (C) 4 : 5
Answer: (C) 4 : 5
Answer: (C) 4 : 5
4 : 5
4 : 5
4 : 5
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q3. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?
Q3. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?
Answer: (B) 120
Answer: (B) 120
Answer: (B) 120
120
120
120
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q4. The 8th term of the sequence 2, 6, 18, 54, ...... is
Q4. The 8th term of the sequence 2, 6, 18, 54, ...... is
Answer: (B) 4374
Answer: (B) 4374
Answer: (B) 4374
4374
4374
4374
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q5. A number when divided by 6 is diminished by 40. The number is
Q5. A number when divided by 6 is diminished by 40. The number is
Answer: (B) 48
Answer: (B) 48
Answer: (B) 48
48
48
48
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q6. A wheel can cover a distance of 22 km in 1000 rounds. The radius of the wheel is
Q6. A wheel can cover a distance of 22 km in 1000 rounds. The radius of the wheel is
Answer: (D) 3.5 m
Answer: (D) 3.5 m
Answer: (D) 3.5 m
3.5 m
3.5 m
3.5 m
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q7. The remainder when –76 is divided by 3, is
Q7. The remainder when –76 is divided by 3, is
Answer: (C) 2
Answer: (C) 2
Answer: (C) 2
2
Because, Reminder must be positive and it should be less then the divisor
2 Because, Reminder must be positive and it should be less then the divisor
2 Because, Reminder must be positive and it should be less then the divisor
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q8. The sum of first 6 prime numbers is
Q8. The sum of first 6 prime numbers is
Answer: (C) 41
Answer: (C) 41
Answer: (C) 41
41
41
41
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q9. What is the value of x in the equation 2x + 5 = 11?
Q9. What is the value of x in the equation 2x + 5 = 11?
Answer: (B) 3
Answer: (B) 3
Answer: (B) 3
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q10. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?
Q10. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?
Answer: (D) 50 sec
Answer: (D) 50 sec
Answer: (D) 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s
As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely.
Hence This train will be ahead of 100m with a speed of 2m/s.
Hence The time to cross each other will take = 100m / (2m/s)
= 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q11. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is
Q11. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is
Answer: (D) 11
Answer: (D) 11
Answer: (D) 11
11
11
11
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q12. The angles of a quadrilateral are in the ratio of 1 : 3 : 4 : 7. The difference between the largest and the smallest angle is
Q12. The angles of a quadrilateral are in the ratio of 1 : 3 : 4 : 7. The difference between the largest and the smallest angle is
Answer: (C) 144°
Answer: (C) 144°
Answer: (C) 144°
(360°/15) * (7-1) = 144°
(360°/15) * (7-1) = 144°
(360°/15) * (7-1) = 144°
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q13. Which of the following is a prime number?
Q13. Which of the following is a prime number?
81,33,71,93
81,33,71,93
81,33,71,93
Answer: (C) 71
Answer: (C) 71
Answer: (C) 71
71
71
71
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q14. 4/5 of a number is 64. Then half of the number is
Q14. 4/5 of a number is 64. Then half of the number is
Answer: (D) 40
Answer: (D) 40
Answer: (D) 40
40
40
40
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q15. The least number by which 2450 must be multiplied to make it a perfect square, is
Q15. The least number by which 2450 must be multiplied to make it a perfect square, is
Answer: (A) 2
Answer: (A) 2
Answer: (A) 2
2
2
2
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q16. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q16. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Answer: (C) 1.2 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q17. When the numerator of a fraction increases by 3, the fraction increases by its three-fourth. The numerator of the fraction is
Q17. When the numerator of a fraction increases by 3, the fraction increases by its three-fourth. The numerator of the fraction is
Answer: (B) 4
Answer: (B) 4
Answer: (B) 4
4
4
4
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q18. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is
Q18. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is
Answer: (D) 27
Answer: (D) 27
Answer: (D) 27
27
27
27
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q19. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will be
Q19. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will be
Answer: (B) r
Answer: (B) r
Answer: (B) r
LCM will be r.
px= q and qy = r, hence r = pxy.
LCM will be r. px= q and qy = r, hence r = pxy.
LCM will be r. px= q and qy = r, hence r = pxy.
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help
Q20. If the sum of five consecutive numbers is 190, then the lowest number amongst them is
Q20. If the sum of five consecutive numbers is 190, then the lowest number amongst them is
Answer: (D) 36
Answer: (D) 36
Answer: (D) 36
36
36
36
*** Choose the correct option to show answer. (Choose the correct option to show answer.) Need help