Unmemorable (Non Memory Based) | MCQ Quizzes | Category (L/R/A)
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2025-07-31 04:38:01
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Category UID: 18
Label UID: 42
Category Name: Unmemorable
Category Full Name: Non Memory Based
Category Link/Slug: unmemorable
Total Quizzes: 57
Total Views: 827
Last Refreshed: 2025-07-31 04:38:01
Category Description: This category is for the informations which we can't memorise.
Q1. The missing term in the sequence 7, 11, 19, 31, ______, 67 is
Q1. The missing term in the sequence 7, 11, 19, 31, ______, 67 is
Answer: (B) 47
Answer: (B) 47
Answer: (B) 47
47
47
47
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Q2. If the sum of five consecutive numbers is 190, then the lowest number amongst them is
Q2. If the sum of five consecutive numbers is 190, then the lowest number amongst them is
Answer: (D) 36
Answer: (D) 36
Answer: (D) 36
36
36
36
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Q3. A hostel has 120 students and food supplies are for 45 days. If 30 more students joined the hostel, then how many days the hostel will run with the existing food?
Q3. A hostel has 120 students and food supplies are for 45 days. If 30 more students joined the hostel, then how many days the hostel will run with the existing food?
Answer: (C) 36 days
Answer: (C) 36 days
Answer: (C) 36 days
36 days
36 days
36 days
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Q4. The angles of a quadrilateral are in the ratio of 1 : 3 : 4 : 7. The difference between the largest and the smallest angle is
Q4. The angles of a quadrilateral are in the ratio of 1 : 3 : 4 : 7. The difference between the largest and the smallest angle is
Answer: (C) 144°
Answer: (C) 144°
Answer: (C) 144°
(360°/15) * (7-1) = 144°
(360°/15) * (7-1) = 144°
(360°/15) * (7-1) = 144°
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Q5. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
Q5. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
Answer: (A) 13
Answer: (A) 13
Answer: (A) 13
The smallest number amongst them is 13
=> X + (X+2) + (X+4) + (X+6) = 64
=> 4X + 12 = 64
=> 4X = 64 - 12
=> 4X = 52
=> X = 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13
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Q6. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?
Q6. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?
Answer: (B) 120
Answer: (B) 120
Answer: (B) 120
120
120
120
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Q7. Three numbers are in the ratio 3:4:6 and their product is 1944. The largest of the numbers is.
Q7. Three numbers are in the ratio 3:4:6 and their product is 1944. The largest of the numbers is.
Answer: (C) 18
Answer: (C) 18
Answer: (C) 18
18
18
18
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Q8. What is the value of x in the equation 2x + 5 = 11?
Q8. What is the value of x in the equation 2x + 5 = 11?
Answer: (B) 3
Answer: (B) 3
Answer: (B) 3
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
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Q9. 3/4 of a number is 19 less than the original number. The number is
Q9. 3/4 of a number is 19 less than the original number. The number is
Answer: (D) 76
Answer: (D) 76
Answer: (D) 76
76
76
76
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Q10. A number when divided by 6 is diminished by 40. The number is
Q10. A number when divided by 6 is diminished by 40. The number is
Answer: (B) 48
Answer: (B) 48
Answer: (B) 48
48
48
48
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Q11. The remainder when –76 is divided by 3, is
Q11. The remainder when –76 is divided by 3, is
Answer: (C) 2
Answer: (C) 2
Answer: (C) 2
2
Because, Reminder must be positive and it should be less then the divisor
2 Because, Reminder must be positive and it should be less then the divisor
2 Because, Reminder must be positive and it should be less then the divisor
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Q12. Find the median of the data set.
Q12. Find the median of the data set.
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12
Answer: (C) 5
Answer: (C) 5
Answer: (C) 5
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12
= 1, 1, 1, 2, 4, 5, 5, 7, 8, 12, 12, 16, 17
Total numbers of values N = 13
Hence median value = (N + 1)/2 = (13 + 1)/2 = 7th
7th Number = 5
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12 = 1, 1, 1, 2, 4, 5, 5, 7, 8, 12, 12, 16, 17 Total numbers of values N = 13 Hence median value = (N + 1)/2 = (13 + 1)/2 = 7th 7th Number = 5
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12 = 1, 1, 1, 2, 4, 5, 5, 7, 8, 12, 12, 16, 17 Total numbers of values N = 13 Hence median value = (N + 1)/2 = (13 + 1)/2 = 7th 7th Number = 5
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Q13. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is
Q13. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is
Answer: (D) 11
Answer: (D) 11
Answer: (D) 11
11
11
11
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Q14. Find the value of
Q14. Find the value of
Answer: (D)
Answer: (D)
Answer: (D)
=
=
=
=
=
= = = = =
= = = = =
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Q15. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Q15. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Answer: (D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
The son becomes 15 years old after 3 years.
Hence son's present age = 15 years - 3 years = 12 years
Man is four times as old as his son.
Hence Man's present age = 12 years * 4 = 48 years
Man is 3 years older than his wife.
Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
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Q16. Three fourth of a number is more than two third of the number by 5. Then the number is
Q16. Three fourth of a number is more than two third of the number by 5. Then the number is
Answer: (B) 60
Answer: (B) 60
Answer: (B) 60
60
60
60
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Q17. When the numerator of a fraction increases by 3, the fraction increases by its three-fourth. The numerator of the fraction is
Q17. When the numerator of a fraction increases by 3, the fraction increases by its three-fourth. The numerator of the fraction is
Answer: (B) 4
Answer: (B) 4
Answer: (B) 4
4
4
4
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Q18. A number is as much greater than 22 as is less than 72. Then the number is
Q18. A number is as much greater than 22 as is less than 72. Then the number is
Answer: (D) 47
Answer: (D) 47
Answer: (D) 47
47
47
47
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Q19. The value of is :
Q19. The value of is :
Answer: (C) 2.73
Answer: (C) 2.73
Answer: (C) 2.73
=
=
= 0.2 + 1.2 + 1.3 + 0.03
= 2.73
= = = 0.2 + 1.2 + 1.3 + 0.03 = 2.73
= = = 0.2 + 1.2 + 1.3 + 0.03 = 2.73
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Q20. The sum of first 6 prime numbers is
Q20. The sum of first 6 prime numbers is
Answer: (C) 41
Answer: (C) 41
Answer: (C) 41
41
41
41
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