Unmemorable (Non Memory Based) | 57+ MCQ Quizzes | Category (L/R/A) - SPPMMC

Unmemorable (Non Memory Based) | MCQ Quizzes | Category (L/R/A)

@18

57 quizzes

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2025-06-15 17:12:12

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Category UID: 18

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Category Name: Unmemorable

Category Full Name: Non Memory Based

Category Link/Slug: unmemorable

Total Quizzes: 57

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Last Refreshed: 2025-06-15 17:12:12

Category Description: This category is for the informations which we can't memorise.

Q1. The sum of first 6 prime numbers is
Q1. The sum of first 6 prime numbers is

(A) 40
(A) 40
(B) 43
(B) 43
(C) 41
(C) 41
(D) 42
(D) 42
Answer: (C) 41
Answer: (C) 41
41
41

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@661

2024-03-03

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Q2. The value of 0.04 + 1.44 + 1.69 + 0.0009 is :
Q2. The value of 0.04 + 1.44 + 1.69 + 0.0009 is :

(A) 1.73
(A) 1.73
(B) 2.03
(B) 2.03
(C) 2.73
(C) 2.73
(D) 1.03
(D) 1.03
Answer: (C) 2.73
Answer: (C) 2.73
= 0.04 + 1.44 + 1.69 + 0.0009 = 0.02*0.02 + 1.2*1.2 + 1.3*1.3 + 0.03*0.03 = 0.2 + 1.2 + 1.3 + 0.03 = 2.73
= 0.04 + 1.44 + 1.69 + 0.0009 = 0.02*0.02 + 1.2*1.2 + 1.3*1.3 + 0.03*0.03 = 0.2 + 1.2 + 1.3 + 0.03 = 2.73

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@1117

2024-05-09

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Q3. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will be
Q3. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will be

(A) q
(A) q
(B) r
(B) r
(C) qr
(C) qr
(D) pqr
(D) pqr
Answer: (B) r
Answer: (B) r
LCM will be r. px= q and qy = r, hence r = pxy.
LCM will be r. px= q and qy = r, hence r = pxy.

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@1030

2024-04-20

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Q4. If 16℅ of 40℅ of a number is 8, then the number is
Q4. If 16℅ of 40℅ of a number is 8, then the number is

(A) 250
(A) 250
(B) 125
(B) 125
(C) 200
(C) 200
(D) 100
(D) 100
Answer: (B) 125
Answer: (B) 125
125
125

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@872

2024-03-03

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Q5. Shyam stored Rs 35 in the form of 1 rupee coin and 50 paise coins in the ratio 2 : 3. The number of 50 paise coins are
Q5. Shyam stored Rs 35 in the form of 1 rupee coin and 50 paise coins in the ratio 2 : 3. The number of 50 paise coins are

(A) 20
(A) 20
(B) 25
(B) 25
(C) 30
(C) 30
(D) 35
(D) 35
Answer: (C) 30
Answer: (C) 30
1*20 + 0.5*30 = 20+15 = 35
1*20 + 0.5*30 = 20+15 = 35

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@1026

2024-04-19

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Q6. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be
Q6. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be

(A) 3
(A) 3
(B) 25
(B) 25
(C) 5
(C) 5
(D) 33
(D) 33
Answer: (C) 5
Answer: (C) 5
5
5

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@1020

2024-04-19

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Q7. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is
Q7. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is

(A) 8
(A) 8
(B) 12
(B) 12
(C) 20
(C) 20
(D) 36
(D) 36
Answer: (C) 20
Answer: (C) 20
=> 2x * 3x = 96 => 6x2 = 96 => x2 = 96/6 => x2 = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20
=> 2x * 3x = 96 => 6x2 = 96 => x2 = 96/6 => x2 = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20

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@1110

2024-05-09

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Q8. What is the value of x in the equation 2x + 5 = 11?
Q8. What is the value of x in the equation 2x + 5 = 11?

(A) 2
(A) 2
(B) 3
(B) 3
(C) 4
(C) 4
(D) 5
(D) 5
Answer: (B) 3
Answer: (B) 3
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.

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@1256

2024-07-02

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Q9. The LCM of two numbers is 40 and their HCF is 4. If the difference between the two numbers is 12, then the sum of the numbers is
Q9. The LCM of two numbers is 40 and their HCF is 4. If the difference between the two numbers is 12, then the sum of the numbers is

(A) 20
(A) 20
(B) 24
(B) 24
(C) 28
(C) 28
(D) 32
(D) 32
Answer: (C) 28
Answer: (C) 28
X * (X-12) = 40 * 4 X = 20 X + (X-12) = 20 + 20 - 12 = 28
X * (X-12) = 40 * 4 X = 20 X + (X-12) = 20 + 20 - 12 = 28

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@1087

2024-05-01

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Q10. 5 : 27 :: 9 : ________
Q10. 5 : 27 :: 9 : ________

Fill the blank.

Fill the blank.
(A) 83
(A) 83
(B) 81
(B) 81
(C) 36
(C) 36
(D) 18
(D) 18
Answer: (A) 83
Answer: (A) 83
5 : (52 + 2) = 5 : 27 Hence 9 : (92 + 2) = 9 : 83
5 : (52 + 2) = 5 : 27 Hence 9 : (92 + 2) = 9 : 83

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@1134

2024-05-15

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Q11. How many prime numbers exist, which are less than 40?
Q11. How many prime numbers exist, which are less than 40?

(A) 10
(A) 10
(B) 11
(B) 11
(C) 12
(C) 12
(D) 13
(D) 13
Answer: (C) 12
Answer: (C) 12
12
12

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@673

2024-03-03

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Q12. A 100 metre long train moving in a uniform speed of 20 m/sec crosses a bridge of length 1 km. The time taken by the train to cross the bridge is
Q12. A 100 metre long train moving in a uniform speed of 20 m/sec crosses a bridge of length 1 km. The time taken by the train to cross the bridge is

(A) 45 seconds
(A) 45 seconds
(B) 50 seconds
(B) 50 seconds
(C) 55 seconds
(C) 55 seconds
(D) 60 seconds
(D) 60 seconds
Answer: (C) 55 seconds
Answer: (C) 55 seconds
(1000+100)m / (20m/s) = 55 seconds
(1000+100)m / (20m/s) = 55 seconds

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@1031

2024-04-20

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Q13. A 20 m long ladder is leaning on a vertical wall. It makes an angle of 30° with the ground. The height of the point the ladder touches wall is
Q13. A 20 m long ladder is leaning on a vertical wall. It makes an angle of 30° with the ground. The height of the point the ladder touches wall is

(A) 10 m
(A) 10 m
(B) 17.32 m
(B) 17.32 m
(C) 8.16 m
(C) 8.16 m
(D) 13 m
(D) 13 m
Answer: (A) 10 m
Answer: (A) 10 m
10 m
10 m

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@1022

2024-04-19

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Q14. A number is as much greater than 22 as is less than 72. Then the number is
Q14. A number is as much greater than 22 as is less than 72. Then the number is

(A) 44
(A) 44
(B) 50
(B) 50
(C) 52
(C) 52
(D) 47
(D) 47
Answer: (D) 47
Answer: (D) 47
47
47

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@898

2024-03-03

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Q15. If the price of sugar increases by 20%, by what percentage should a household reduce its consumption of sugar so that the budget remains the same?
Q15. If the price of sugar increases by 20%, by what percentage should a household reduce its consumption of sugar so that the budget remains the same?

(A) 1323%
(A) 1323%
(B) 1423%
(B) 1423%
(C) 1523%
(C) 1523%
(D) 1623%
(D) 1623%
Answer: (D) 1623%
Answer: (D) 1623%
1623%
1623%

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@1029

2024-04-20

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Q16. A hostel has 120 students and food supplies are for 45 days. If 30 more students joined the hostel, then how many days the hostel will run with the existing food?
Q16. A hostel has 120 students and food supplies are for 45 days. If 30 more students joined the hostel, then how many days the hostel will run with the existing food?

(A) 40 days
(A) 40 days
(B) 38 days
(B) 38 days
(C) 36 days
(C) 36 days
(D) 32 days
(D) 32 days
Answer: (C) 36 days
Answer: (C) 36 days
36 days
36 days

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657 views

@1021

2024-04-19

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Q17. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?
Q17. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?

(A) 60
(A) 60
(B) 120
(B) 120
(C) 180
(C) 180
(D) 240
(D) 240
Answer: (B) 120
Answer: (B) 120
120
120

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@1025

2024-04-19

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Q18. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q18. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :

(A) 1.5 km
(A) 1.5 km
(B) 1.75 km
(B) 1.75 km
(C) 1.2 km
(C) 1.2 km
(D) 1.25 km
(D) 1.25 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

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@1122

2024-05-15

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Q19. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
Q19. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is

(A) 13
(A) 13
(B) 11
(B) 11
(C) 16
(C) 16
(D) 9
(D) 9
Answer: (A) 13
Answer: (A) 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13

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@1109

2024-05-09

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Q20. A number when divided by 6 is diminished by 40. The number is
Q20. A number when divided by 6 is diminished by 40. The number is

(A) 72
(A) 72
(B) 48
(B) 48
(C) 60
(C) 60
(D) 84
(D) 84
Answer: (B) 48
Answer: (B) 48
48
48

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780 views

@871

2024-03-03

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