The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1? [#1025]

120

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120

5 : (5² + 2) = 5 : 27 Hence 9 : (9² + 2) = 9 : 83

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5 : (5² + 2) = 5 : 27 Hence 9 : (9² + 2) = 9 : 83

7 and 8

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7 and 8

20% = $\frac{25}{100+25} * 100$% $\frac{25}{125} * 100$% = 20%

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20% = $\frac{25}{100+25} * 100$% $\frac{25}{125} * 100$% = 20%

2⁶ = 64 3⁵ = 243 4⁴ = 256 5³ = 125

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2⁶ = 64 3⁵ = 243 4⁴ = 256 5³ = 125

$\sqrt{\frac{225}{729}}-\sqrt{\frac{25}{144}}-\sqrt{\frac{16}{81}}$ = $\sqrt{\frac{15*15}{27*27}}-\sqrt{\frac{5*5}{12*12}}-\sqrt{\frac{4*4}{9*9}}$ = $\frac{15}{27}-\frac{5}{12}-\frac{4}{9}$ = $\frac{60-45-48}{108}$ = $\frac{-33}{108}$ = $\frac{-11}{36}$

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$\sqrt{\frac{225}{729}}-\sqrt{\frac{25}{144}}-\sqrt{\frac{16}{81}}$ = $\sqrt{\frac{15*15}{27*27}}-\sqrt{\frac{5*5}{12*12}}-\sqrt{\frac{4*4}{9*9}}$ = $\frac{15}{27}-\frac{5}{12}-\frac{4}{9}$ = $\frac{60-45-48}{108}$ = $\frac{-33}{108}$ = $\frac{-11}{36}$

LCM will be r. px= q and qy = r, hence r = pxy.

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LCM will be r. px= q and qy = r, hence r = pxy.

25 years + (3*10) years = 55 years

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25 years + (3*10) years = 55 years

$\frac{X}{3}=\frac{Y}{4}=\frac{Z}{7}$ Hence, X:Y:Z = 3:4:7 $\frac{X+Y+Z}{Z}$ = $\frac{3+4+7}{7}$ = $\frac{14}{7}$ = 2

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$\frac{X}{3}=\frac{Y}{4}=\frac{Z}{7}$ Hence, X:Y:Z = 3:4:7 $\frac{X+Y+Z}{Z}$ = $\frac{3+4+7}{7}$ = $\frac{14}{7}$ = 2

A constant is a mathematical concept that represents a value that remains unchanged, like pi (π), which is approximately 3.14 and never changes.

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A constant is a mathematical concept that represents a value that remains unchanged, like pi (π), which is approximately 3.14 and never changes.

The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.

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The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.