SPPMMC TEAM - Quizzes (S/P) - Part 67 | SPPMMC

SPPMMC TEAM - Quizzes (S/P) - Part 67

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1898 quizzes

Showing Quizzes: 10 (661-670) [Part -67]

Publisher UID: 3

Publisher Name: SPPMMC TEAM

Publisher Link/Slug: sppmmc-team-3

Date of Joining: 2023-01-26

Q661. The ratio of the radii of two circles is 1 : 3. The ratio of their areas is
Q661. The ratio of the radii of two circles is 1 : 3. The ratio of their areas is

(A) 1:6
(A) 1:6
(B) 2:9
(B) 2:9
(C) 1:9
(C) 1:9
(D) 6:9
(D) 6:9
Answer: (C) 1:9
Answer: (C) 1:9
Area = πr2 π12 : π32 = π1 : π9 = 1:9
Area = πr2 π12 : π32 = π1 : π9 = 1:9

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@1703

2024-10-23

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Q662. At what percentage of simple interest does an amount of money double in 12 years?
Q662. At what percentage of simple interest does an amount of money double in 12 years?

(A) 912%
(A) 912%
(B) 812%
(B) 812%
(C) 813%
(C) 813%
(D) 913%
(D) 913%
Answer: (C) 813%
Answer: (C) 813%
P * 813% * 12 = P * 253% * 12 = P * 3003% = P * 100%
P * 813% * 12 = P * 253% * 12 = P * 3003% = P * 100%

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@1702

2024-10-23

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Q663. When the numerator of a fraction is multiplied by 4 and the denominator by 9, the fraction reverses. The fraction is
Q663. When the numerator of a fraction is multiplied by 4 and the denominator by 9, the fraction reverses. The fraction is

(A) 45
(A) 45
(B) 23
(B) 23
(C) 54
(C) 54
(D) 32
(D) 32
Answer: (D) 32
Answer: (D) 32
32 >32×49 = 1218 = 23
32 >32×49 = 1218 = 23

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@1701

2024-10-23

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Q664. Find the least number by which 1250 must be multiplied to make it a perfect square.
Q664. Find the least number by which 1250 must be multiplied to make it a perfect square.

(A) 4
(A) 4
(B) 3
(B) 3
(C) 5
(C) 5
(D) 2
(D) 2
Answer: (D) 2
Answer: (D) 2
1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 2500 = 2*5*5 = 50
1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 2500 = 2*5*5 = 50

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@1700

2024-10-23

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Q665. In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is
Q665. In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is

(A) 35
(A) 35
(B) 42
(B) 42
(C) 49
(C) 49
(D) 56
(D) 56
Answer: (C) 49
Answer: (C) 49
1+3+5+7+9+11+13 = 49
1+3+5+7+9+11+13 = 49

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@1699

2024-10-23

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Q666. The largest of 26, 35, 44 and 53 is
Q666. The largest of 26, 35, 44 and 53 is

(A) 26
(A) 26
(B) 35
(B) 35
(C) 44
(C) 44
(D) 53
(D) 53
Answer: (C) 44
Answer: (C) 44
26 = 64 35 = 243 44 = 256 53 = 125
26 = 64 35 = 243 44 = 256 53 = 125

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@1698

2024-10-23

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Q667. If A : B = 3, then 144A : 36B is
Q667. If A : B = 3, then 144A : 36B is

(A) 4
(A) 4
(B) 12
(B) 12
(C) 3
(C) 3
(D) 16
(D) 16
Answer: (B) 12
Answer: (B) 12
A : B = 3 => AB = 3 144A36B = 14436×AB = 14436 x 3 = 4 x 3 = 12
A : B = 3 => AB = 3 144A36B = 14436×AB = 14436 x 3 = 4 x 3 = 12

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@1697

2024-10-23

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Q668. The count of prime numbers between 80 and 100 is
Q668. The count of prime numbers between 80 and 100 is

(A) 2
(A) 2
(B) 5
(B) 5
(C) 3
(C) 3
(D) 4
(D) 4
Answer: (C) 3
Answer: (C) 3
Prime numbers are numbers that are only divisible by 1 and themselves. Between 80 and 100, the prime numbers are 83, 89, and 97. Therefore, there are 3 prime numbers in this range.
Prime numbers are numbers that are only divisible by 1 and themselves. Between 80 and 100, the prime numbers are 83, 89, and 97. Therefore, there are 3 prime numbers in this range.

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@1696

2024-10-23

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Q669. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is
Q669. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is

(A) 55
(A) 55
(B) 0
(B) 0
(C) 270
(C) 270
(D) 45
(D) 45
Answer: (B) 0
Answer: (B) 0
1st Month -> (105 * 2) - 120 = 210 - 120 = 90 2nd Month -> (90 * 2) - 120 = 180 - 120 = 60 3rd Month -> (60 * 2) - 120 = 120 - 120 = 0
1st Month -> (105 * 2) - 120 = 210 - 120 = 90 2nd Month -> (90 * 2) - 120 = 180 - 120 = 60 3rd Month -> (60 * 2) - 120 = 120 - 120 = 0

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@1695

2024-10-23

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Q670. The value of 823 is
Q670. The value of 823 is

(A) 1
(A) 1
(B) 3
(B) 3
(C) 2
(C) 2
(D) 4
(D) 4
Answer: (D) 4
Answer: (D) 4
823 = 643 = 433 = 4
823 = 643 = 433 = 4

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@1694

2024-10-23

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