SPPMMC TEAM - Quizzes (S/P) - Part 66
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1898 quizzes
Showing Quizzes: 10 (651-660) [Part -66]
Publisher UID: 3
Publisher Name: SPPMMC TEAM
Publisher Link/Slug: sppmmc-team-3
Date of Joining: 2023-01-26
Q651. A person moves along a path such that he is always away from a given point by 7 m. After moving for some time, he again reaches his starting point. The approximate distance the person moved during the time is
Q651. A person moves along a path such that he is always away from a given point by 7 m. After moving for some time, he again reaches his starting point. The approximate distance the person moved during the time is
Answer: (B) 44 m
Answer: (B) 44 m
Answer: (B) 44 m
2 * * 7
= 2 * 22
= 44
2 * * 7 = 2 * 22 = 44
2 * * 7 = 2 * 22 = 44
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Q652. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is
Q652. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is
Answer: (C) 2
Answer: (C) 2
Answer: (C) 2
In ascending order = -2, -1, 1, 2, 3, 5, 6
median = th term
= 4th term
= 2
In ascending order = -2, -1, 1, 2, 3, 5, 6 median = th term = 4th term = 2
In ascending order = -2, -1, 1, 2, 3, 5, 6 median = th term = 4th term = 2
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Q653. A ladder of length 13 m is leaning against a vertical wall with the upper end at the height of 5 m. The horizontal distance between the foot of the wall and the lower end of the ladder is
Q653. A ladder of length 13 m is leaning against a vertical wall with the upper end at the height of 5 m. The horizontal distance between the foot of the wall and the lower end of the ladder is
Answer: (D) 12m
Answer: (D) 12m
Answer: (D) 12m
52 + X2 = 132
=> 25 + X2 = 169
=> X2 = 196 - 25
=> X2 = 144
=> X = 12
52 + X2 = 132 => 25 + X2 = 169 => X2 = 196 - 25 => X2 = 144 => X = 12
52 + X2 = 132 => 25 + X2 = 169 => X2 = 196 - 25 => X2 = 144 => X = 12
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Q654. In Roman numeral, XCI represents the decimal number
Q654. In Roman numeral, XCI represents the decimal number
Answer: (C) 91
Answer: (C) 91
Answer: (C) 91
100-10+1 = 91
100-10+1 = 91
100-10+1 = 91
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Q655. When three times of a given number is subtracted from the square of the number, the result is the number itself. The number is
Q655. When three times of a given number is subtracted from the square of the number, the result is the number itself. The number is
Answer: (A) 4
Answer: (A) 4
Answer: (A) 4
42 - (4*3)
= 16 - 12
= 4
42 - (4*3) = 16 - 12 = 4
42 - (4*3) = 16 - 12 = 4
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Q656. If today is Sunday, then the day after 92 days will be
Q656. If today is Sunday, then the day after 92 days will be
Answer: (D) Monday
Answer: (D) Monday
Answer: (D) Monday
-> Rem = 1
Sunday + 1 = Monday
-> Rem = 1 Sunday + 1 = Monday
-> Rem = 1 Sunday + 1 = Monday
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Q657. If the decimal number 34p5 is divisible by 9, then the value of p is
Q657. If the decimal number 34p5 is divisible by 9, then the value of p is
Answer: (D) 6
Answer: (D) 6
Answer: (D) 6
34p5 -> 3+4+p+5 = 12+p
12+p = 9k
12+6 = 18 = 9k
p = 6
34p5 -> 3+4+p+5 = 12+p 12+p = 9k 12+6 = 18 = 9k p = 6
34p5 -> 3+4+p+5 = 12+p 12+p = 9k 12+6 = 18 = 9k p = 6
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Q658. The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is
Q658. The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is
Answer: (C) 23
Answer: (C) 23
Answer: (C) 23
X + (X+2) + (X+4) + (X+6) + (X+8) = 95
=> 5X + 20 = 95
=> 5X = 95-20
=> 5X = 75
=> X = 15
Hence (X+8) = 15+8 = 23
X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23
X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23
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Q659. If 2x = 32, then the value of x is
Q659. If 2x = 32, then the value of x is
Answer: (B) 5
Answer: (B) 5
Answer: (B) 5
25 = 2*2*2*2*2 = 32
25 = 2*2*2*2*2 = 32
25 = 2*2*2*2*2 = 32
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Q660. 100% of 100 when added to 200% of 200 would result
Q660. 100% of 100 when added to 200% of 200 would result
Answer: (C) 500
Answer: (C) 500
Answer: (C) 500
100 * 100% + 200 * 200%
=
=
= 100 + 400
= 500
100 * 100% + 200 * 200% = = = 100 + 400 = 500
100 * 100% + 200 * 200% = = = 100 + 400 = 500
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