SPPMMC TEAM - Quizzes (S/P) - Part 124
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Showing Quizzes: 10 (1231-1240) [Part -124]
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Publisher Name: SPPMMC TEAM
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Date of Joining: 2023-01-26
Q1231. Select the number pair in which the two numbers are related in the same way as 35 : 6.
Q1231. Select the number pair in which the two numbers are related in the same way as 35 : 6.
Answer: (D) 120 : 11
Answer: (D) 120 : 11
Answer: (D) 120 : 11
62-1 : 6 = 35 : 6
112-1 : 11 = 120 : 11
62-1 : 6 = 35 : 6 112-1 : 11 = 120 : 11
62-1 : 6 = 35 : 6 112-1 : 11 = 120 : 11
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Q1232. If 20% of a is b, then b% of 20 is the same as :
Q1232. If 20% of a is b, then b% of 20 is the same as :
Answer: (A) 4% of a
Answer: (A) 4% of a
Answer: (A) 4% of a
20% of a is b
Hence b = 20% of a = 20a/100
b% of 20
= 20% of b
= (20/100) * 20a/100
= (20*20*a)/(100*100)
= 4a/100
= (4/100) * a
= 4% of a
20% of a is b Hence b = 20% of a = 20a/100 b% of 20 = 20% of b = (20/100) * 20a/100 = (20*20*a)/(100*100) = 4a/100 = (4/100) * a = 4% of a
20% of a is b Hence b = 20% of a = 20a/100 b% of 20 = 20% of b = (20/100) * 20a/100 = (20*20*a)/(100*100) = 4a/100 = (4/100) * a = 4% of a
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Q1233. Sarita and Savita were coming to each other in the garden in the morning. Savita saw that Sarita’s shadow was at Sarita’s left side. Which direction was Savita facing to?
Q1233. Sarita and Savita were coming to each other in the garden in the morning. Savita saw that Sarita’s shadow was at Sarita’s left side. Which direction was Savita facing to?
Answer: (A) South
Answer: (A) South
Answer: (A) South
Sarita was facing to North and Savita was facing to South.
In the morning the sun was in the East and the shadow was in the west.
As Sarita was facing to North his shadow was in the west and west was in left side of her.
Sarita was facing to North and Savita was facing to South. In the morning the sun was in the East and the shadow was in the west. As Sarita was facing to North his shadow was in the west and west was in left side of her.
Sarita was facing to North and Savita was facing to South. In the morning the sun was in the East and the shadow was in the west. As Sarita was facing to North his shadow was in the west and west was in left side of her.
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Q1234. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Q1234. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Answer: (D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
The son becomes 15 years old after 3 years.
Hence son's present age = 15 years - 3 years = 12 years
Man is four times as old as his son.
Hence Man's present age = 12 years * 4 = 48 years
Man is 3 years older than his wife.
Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
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Q1235. Five boys are sitting in a circle facing inward. Ajay is between Rohit and Doljit. Suman is at the left of Shyamal, Rohit is at the left of Suman. Who is sitting at the immediate right of Ajay?
Q1235. Five boys are sitting in a circle facing inward. Ajay is between Rohit and Doljit. Suman is at the left of Shyamal, Rohit is at the left of Suman. Who is sitting at the immediate right of Ajay?
Answer: (C) Rohit
Answer: (C) Rohit
Answer: (C) Rohit
Rohit
Rohit
Rohit
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Q1236. Which letter of the English Alphabet is the seventh from left of sixteenth from right?
Q1236. Which letter of the English Alphabet is the seventh from left of sixteenth from right?
Answer: (C) R
Answer: (C) R
Answer: (C) R
K is the 19th from right
R is the 7th from left of K.
K is the 19th from right R is the 7th from left of K.
K is the 19th from right R is the 7th from left of K.
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Q1237. On the moon, ________ air because the Moon’s gravitational field is too weak to retain an atmosphere.
Q1237. On the moon, ________ air because the Moon’s gravitational field is too weak to retain an atmosphere.
Answer: (A) there is no
Answer: (A) there is no
Answer: (A) there is no
On the Moon, there is no air because the Moon's gravitational field is too weak to retain an atmosphere.
On the Moon, there is no air because the Moon's gravitational field is too weak to retain an atmosphere.
On the Moon, there is no air because the Moon's gravitational field is too weak to retain an atmosphere.
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Q1238. The price of an article is first decreased by 40% and then increased by 20%. The net change in the price will be :
Q1238. The price of an article is first decreased by 40% and then increased by 20%. The net change in the price will be :
Answer: (D) 28%
Answer: (D) 28%
Answer: (D) 28%
Net change (-40 + 20 + )%
= (-20 + )%
= (-20 - 8)%
= -28%
= 28%
Net change (-40 + 20 + )% = (-20 + )% = (-20 - 8)% = -28% = 28%
Net change (-40 + 20 + )% = (-20 + )% = (-20 - 8)% = -28% = 28%
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Q1239. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q1239. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Answer: (C) 1.2 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
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Q1240. Find the value of
Q1240. Find the value of
Answer: (D)
Answer: (D)
Answer: (D)
=
=
=
=
=
= = = = =
= = = = =
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