SPPMMC TEAM - Quizzes (S/P) - Part 125 | SPPMMC

SPPMMC TEAM - Quizzes (S/P) - Part 125

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1898 quizzes

Showing Quizzes: 10 (1241-1250) [Part -125]

Publisher UID: 3

Publisher Name: SPPMMC TEAM

Publisher Link/Slug: sppmmc-team-3

Date of Joining: 2023-01-26

Q1241. Find the median of the data set.
Q1241. Find the median of the data set.

1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12

1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12
(A) 8
(A) 8
(B) 7
(B) 7
(C) 5
(C) 5
(D) 4
(D) 4
Answer: (C) 5
Answer: (C) 5
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12 = 1, 1, 1, 2, 4, 5, 5, 7, 8, 12, 12, 16, 17 Total numbers of values N = 13 Hence median value = (N + 1)/2 = (13 + 1)/2 = 7th 7th Number = 5
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12 = 1, 1, 1, 2, 4, 5, 5, 7, 8, 12, 12, 16, 17 Total numbers of values N = 13 Hence median value = (N + 1)/2 = (13 + 1)/2 = 7th 7th Number = 5

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@1120

2024-05-09

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Q1242. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :
Q1242. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :

(A) 5,420
(A) 5,420
(B) 5,580
(B) 5,580
(C) 5,620
(C) 5,620
(D) 5,780
(D) 5,780
Answer: (B) 5,580
Answer: (B) 5,580
The formula for the sum of the first n terms of an arithmetic progression is Sn = n2(a+an) 302(12+12*30) = 15*(12+360) = 15 * 372 = 5580
The formula for the sum of the first n terms of an arithmetic progression is Sn = n2(a+an) 302(12+12*30) = 15*(12+360) = 15 * 372 = 5580

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@1119

2024-05-09

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Q1243. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :
Q1243. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :

(A) 2 : 3
(A) 2 : 3
(B) 3 : 5
(B) 3 : 5
(C) 3 : 2
(C) 3 : 2
(D) 2 : 5
(D) 2 : 5
Answer: (A) 2 : 3
Answer: (A) 2 : 3
45100*X = 30100 * Y = XY = 30*100100*45 = XY = 23 = X:Y = 2:3
45100*X = 30100 * Y = XY = 30*100100*45 = XY = 23 = X:Y = 2:3

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@1118

2024-05-09

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Q1244. The value of 0.04 + 1.44 + 1.69 + 0.0009 is :
Q1244. The value of 0.04 + 1.44 + 1.69 + 0.0009 is :

(A) 1.73
(A) 1.73
(B) 2.03
(B) 2.03
(C) 2.73
(C) 2.73
(D) 1.03
(D) 1.03
Answer: (C) 2.73
Answer: (C) 2.73
= 0.04 + 1.44 + 1.69 + 0.0009 = 0.02*0.02 + 1.2*1.2 + 1.3*1.3 + 0.03*0.03 = 0.2 + 1.2 + 1.3 + 0.03 = 2.73
= 0.04 + 1.44 + 1.69 + 0.0009 = 0.02*0.02 + 1.2*1.2 + 1.3*1.3 + 0.03*0.03 = 0.2 + 1.2 + 1.3 + 0.03 = 2.73

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@1117

2024-05-09

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Q1245. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
Q1245. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was

(A) 5
(A) 5
(B) 7
(B) 7
(C) 10
(C) 10
(D) 14
(D) 14
Answer: (B) 7
Answer: (B) 7
7 => x * 2x = 98 => x2 = 982 => x2 = 49 => x = 7
7 => x * 2x = 98 => x2 = 982 => x2 = 49 => x = 7

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@1112

2024-05-09

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Q1246. If the salary of A is 25% more than that of B, how much percentage is the salary of B lower than that of A?
Q1246. If the salary of A is 25% more than that of B, how much percentage is the salary of B lower than that of A?

(A) 20%
(A) 20%
(B) 25%
(B) 25%
(C) 1212%
(C) 1212%
(D) 1612%
(D) 1612%
Answer: (A) 20%
Answer: (A) 20%
20% = 25100+25 =  * 100% 25125 * 100% = 20%
20% = 25100+25 =  * 100% 25125 * 100% = 20%

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@1111

2024-05-09

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Q1247. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is
Q1247. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is

(A) 8
(A) 8
(B) 12
(B) 12
(C) 20
(C) 20
(D) 36
(D) 36
Answer: (C) 20
Answer: (C) 20
=> 2x * 3x = 96 => 6x2 = 96 => x2 = 96/6 => x2 = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20
=> 2x * 3x = 96 => 6x2 = 96 => x2 = 96/6 => x2 = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20

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@1110

2024-05-09

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Q1248. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
Q1248. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is

(A) 13
(A) 13
(B) 11
(B) 11
(C) 16
(C) 16
(D) 9
(D) 9
Answer: (A) 13
Answer: (A) 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13

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@1109

2024-05-09

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Q1249. When the numerator of a fraction increases by 3, the fraction increases by its three-fourth. The numerator of the fraction is
Q1249. When the numerator of a fraction increases by 3, the fraction increases by its three-fourth. The numerator of the fraction is

(A) 3
(A) 3
(B) 4
(B) 4
(C) 5
(C) 5
(D) 6
(D) 6
Answer: (B) 4
Answer: (B) 4
4
4

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@1089

2024-05-01

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Q1250. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is
Q1250. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is

(A) 25
(A) 25
(B) 41
(B) 41
(C) 13
(C) 13
(D) 11
(D) 11
Answer: (D) 11
Answer: (D) 11
11
11

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@1088

2024-05-01

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