International - Quizzes (S/P) - Part 44 - Area Wise | SPPMMC

International - Quizzes (S/P) - Part 44

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International

1007 quizzes

Showing Quizzes: 10 (431-440) [Part - 44 of 101]

Q431. The smallest positive integer that is simultaneously divisible by 6, 8 and 12 is
Q431. The smallest positive integer that is simultaneously divisible by 6, 8 and 12 is

(A) 24
(A) 24
(B) 18
(B) 18
(C) 48
(C) 48
(D) 36
(D) 36
Answer: (A) 24
Answer: (A) 24
6*4 = 24 8*3 = 24 12*2 = 24
6*4 = 24 8*3 = 24 12*2 = 24

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@1714

2024-10-23

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Q432. A person moves along a path such that he is always away from a given point by 7 m. After moving for some time, he again reaches his starting point. The approximate distance the person moved during the time is
Q432. A person moves along a path such that he is always away from a given point by 7 m. After moving for some time, he again reaches his starting point. The approximate distance the person moved during the time is

(A) 22 m
(A) 22 m
(B) 44 m
(B) 44 m
(C) 122 m
(C) 122 m
(D) 144 m
(D) 144 m
Answer: (B) 44 m
Answer: (B) 44 m
2 * 227 * 7 = 2 * 22 = 44
2 * 227 * 7 = 2 * 22 = 44

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@1713

2024-10-23

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Q433. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is
Q433. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is

(A) 1
(A) 1
(B) -1
(B) -1
(C) 2
(C) 2
(D) 3
(D) 3
Answer: (C) 2
Answer: (C) 2
In ascending order = -2, -1, 1, 2, 3, 5, 6 median = 7+12th term = 4th term = 2
In ascending order = -2, -1, 1, 2, 3, 5, 6 median = 7+12th term = 4th term = 2

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@1712

2024-10-23

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Q434. A ladder of length 13 m is leaning against a vertical wall with the upper end at the height of 5 m. The horizontal distance between the foot of the wall and the lower end of the ladder is
Q434. A ladder of length 13 m is leaning against a vertical wall with the upper end at the height of 5 m. The horizontal distance between the foot of the wall and the lower end of the ladder is

(A) 9m
(A) 9m
(B) 5m
(B) 5m
(C) 11m
(C) 11m
(D) 12m
(D) 12m
Answer: (D) 12m
Answer: (D) 12m
52 + X2 = 132 => 25 + X2 = 169 => X2 = 196 - 25 => X2 = 144 => X = 12
52 + X2 = 132 => 25 + X2 = 169 => X2 = 196 - 25 => X2 = 144 => X = 12

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@1711

2024-10-23

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Q435. In Roman numeral, XCI represents the decimal number
Q435. In Roman numeral, XCI represents the decimal number

(A) 41
(A) 41
(B) 21
(B) 21
(C) 91
(C) 91
(D) 111
(D) 111
Answer: (C) 91
Answer: (C) 91
100-10+1 = 91
100-10+1 = 91

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@1710

2024-10-23

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Q436. When three times of a given number is subtracted from the square of the number, the result is the number itself. The number is
Q436. When three times of a given number is subtracted from the square of the number, the result is the number itself. The number is

(A) 4
(A) 4
(B) 2
(B) 2
(C) -2
(C) -2
(D) -4
(D) -4
Answer: (A) 4
Answer: (A) 4
42 - (4*3) = 16 - 12 = 4
42 - (4*3) = 16 - 12 = 4

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@1709

2024-10-23

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Q437. If today is Sunday, then the day after 92 days will be
Q437. If today is Sunday, then the day after 92 days will be

(A) Saturday
(A) Saturday
(B) Friday
(B) Friday
(C) Sunday
(C) Sunday
(D) Monday
(D) Monday
Answer: (D) Monday
Answer: (D) Monday
927 -> Rem = 1 Sunday + 1 = Monday
927 -> Rem = 1 Sunday + 1 = Monday

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@1708

2024-10-23

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Q438. If the decimal number 34p5 is divisible by 9, then the value of p is
Q438. If the decimal number 34p5 is divisible by 9, then the value of p is

(A) 8
(A) 8
(B) 7
(B) 7
(C) 4
(C) 4
(D) 6
(D) 6
Answer: (D) 6
Answer: (D) 6
34p5 -> 3+4+p+5 = 12+p 12+p = 9k 12+6 = 18 = 9k p = 6
34p5 -> 3+4+p+5 = 12+p 12+p = 9k 12+6 = 18 = 9k p = 6

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@1707

2024-10-23

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Q439. The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is
Q439. The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is

(A) 17
(A) 17
(B) 21
(B) 21
(C) 23
(C) 23
(D) 19
(D) 19
Answer: (C) 23
Answer: (C) 23
X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23
X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23

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@1706

2024-10-23

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Q440. If 2x = 32, then the value of x is
Q440. If 2x = 32, then the value of x is

(A) 4
(A) 4
(B) 5
(B) 5
(C) 6
(C) 6
(D) 7
(D) 7
Answer: (B) 5
Answer: (B) 5
25 = 2*2*2*2*2 = 32
25 = 2*2*2*2*2 = 32

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@1705

2024-10-23

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