International - Quizzes (S/P) - Part 41

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International

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Showing Quizzes: 10 (401-410) [Part - 41 of 96]

Q401. If A : B = 3, then 144A : 36B is
Q401. If A : B = 3, then 144A : 36B is

(A) 4
(A) 4

(B) 12
(B) 12

(D) 16
(D) 16

Answer: (B) 12
Answer: (B) 12

A : B = 3 =>

\frac{A}{B}

= 3

\frac{144 A}{36 B}

\frac{144}{36} \times \frac{A}{B}

\frac{144}{36}

x 3 = 4 x 3 = 12

A : B = 3 =>

\frac{A}{B}

= 3

\frac{144 A}{36 B}

\frac{144}{36} \times \frac{A}{B}

\frac{144}{36}

x 3 = 4 x 3 = 12

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@1697

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2024-10-23

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Q402. The count of prime numbers between 80 and 100 is
Q402. The count of prime numbers between 80 and 100 is

(A) 2
(A) 2

(B) 5
(B) 5

(D) 4
(D) 4

Answer: (C) 3
Answer: (C) 3

Prime numbers are numbers that are only divisible by 1 and themselves. Between 80 and 100, the prime numbers are 83, 89, and 97. Therefore, there are 3 prime numbers in this range.

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@1696

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2024-10-23

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Q403. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is
Q403. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is

(A) 55
(A) 55

(B) 0
(B) 0

(D) 45
(D) 45

Answer: (B) 0
Answer: (B) 0

1st Month -> (105 * 2) - 120 = 210 - 120 = 90 2nd Month -> (90 * 2) - 120 = 180 - 120 = 60 3rd Month -> (60 * 2) - 120 = 120 - 120 = 0

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@1695

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2024-10-23

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Q404. The value of $\sqrt[3]{8^{2}}$ is
Q404. The value of $\sqrt[3]{8^{2}}$ is

(A) 1
(A) 1

(B) 3
(B) 3

(D) 4
(D) 4

Answer: (D) 4
Answer: (D) 4

\sqrt[3]{8^{2}}

\sqrt[3]{64}

\sqrt[3]{4^{3}}

= 4

\sqrt[3]{8^{2}}

\sqrt[3]{64}

\sqrt[3]{4^{3}}

= 4

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@1694

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2024-10-23

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Q405. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is
Q405. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is

(A) 18
(A) 18

(B) 20
(B) 20

(D) 24
(D) 24

Answer: (B) 20
Answer: (B) 20

2:3 = 8:12 N1*N2 = HCF*LCM 8*12 = 96 N1+N2 = 8+12 = 20

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@1693

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2024-10-23

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Q406. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to
Q406. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to

(A) 2
(A) 2

(B) 3
(B) 3

(D) 5
(D) 5

Answer: (A) 2
Answer: (A) 2

\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}

Hence, X:Y:Z = 3:4:7

\frac{X + Y + Z}{Z}

\frac{3 + 4 + 7}{7}

\frac{14}{7}

= 2

\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}

Hence, X:Y:Z = 3:4:7

\frac{X + Y + Z}{Z}

\frac{3 + 4 + 7}{7}

\frac{14}{7}

= 2

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@1692

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2024-10-23

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Q407. The smallest among $\sqrt{\frac{1}{2}}, \sqrt{\frac{1}{3}}, \sqrt{\frac{1}{4}} a n d \sqrt{\frac{2}{3}}$ is
Q407. The smallest among $\sqrt{\frac{1}{2}}, \sqrt{\frac{1}{3}}, \sqrt{\frac{1}{4}} a n d \sqrt{\frac{2}{3}}$ is

(A)

\sqrt{\frac{1}{2}}

(A)

\sqrt{\frac{1}{2}}

(B)

\sqrt{\frac{1}{3}}

(B)

\sqrt{\frac{1}{3}}

(C)

\sqrt{\frac{1}{4}}

(C)

\sqrt{\frac{1}{4}}

(D)

\sqrt{\frac{2}{3}}

(D)

\sqrt{\frac{2}{3}}

Answer: (C)

\sqrt{\frac{1}{4}}

Answer: (C)

\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}}

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@1691

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2024-10-23

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Q408. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.
Q408. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.

(A) 25 years
(A) 25 years

(B) 35 years
(B) 35 years

(D) 45 years
(D) 45 years

Answer: (A) 25 years
Answer: (A) 25 years

25 years => A+B+C = 22*3 => A+(B+C) = 66 => A+(25*2) = 66 => A = 66-50 => A = 16 After 9 years A = 16+9 = 25 years

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@1690

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2024-10-23

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Q409. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is
Q409. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is

(A) 16% increase
(A) 16% increase

(B) 16% decrease
(B) 16% decrease

(D) No change
(D) No change

Answer: (B) 16% decrease
Answer: (B) 16% decrease

16% decrease = 40-40-

\frac{40 * 40}{100}

% = -

\frac{1600}{100}

% = -16%

16% decrease = 40-40-

\frac{40 * 40}{100}

% = -

\frac{1600}{100}

% = -16%

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@1689

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2024-10-23

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Q410. Find the best option to fill in the third term : Gravity : Newton :: ? : Copernicus.
Q410. Find the best option to fill in the third term : Gravity : Newton :: ? : Copernicus.

(A) Blood circulation
(A) Blood circulation

(B) Heliocentric system
(B) Heliocentric system

(D) Radioactivity
(D) Radioactivity

Answer: (B) Heliocentric system
Answer: (B) Heliocentric system

Heliocentric system. Nicolaus Copernicus was a Renaissance polymath, active as a mathematician, astronomer, and Catholic canon, who formulated a model of the universe that placed the Sun rather than Earth at its center.

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2024-10-23

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International - Quizzes (S/P) - Part 41

Q401. If A : B = 3, then 144A : 36B isQ401. If A : B = 3, then 144A : 36B is

Q402. The count of prime numbers between 80 and 100 isQ402. The count of prime numbers between 80 and 100 is

Q404. The value of 823 isQ404. The value of 823 is

Q405. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers isQ405. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is

Q406. If X3=Y4=Z7, then X+Y+ZZ is equal toQ406. If X3=Y4=Z7, then X+Y+ZZ is equal to

Q407. The smallest among 12, 13, 14 and 23 isQ407. The smallest among 12, 13, 14 and 23 is

Q408. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.Q408. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.

Q409. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage isQ409. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is

Q410. Find the best option to fill in the third term : Gravity : Newton :: ? : Copernicus.Q410. Find the best option to fill in the third term : Gravity : Newton :: ? : Copernicus.

Q401. If A : B = 3, then 144A : 36B is
Q401. If A : B = 3, then 144A : 36B is

Q402. The count of prime numbers between 80 and 100 is
Q402. The count of prime numbers between 80 and 100 is

Q404. The value of $\sqrt[3]{8^{2}}$ is
Q404. The value of $\sqrt[3]{8^{2}}$ is

Q405. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is
Q405. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is

Q406. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to
Q406. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to

Q407. The smallest among $\sqrt{\frac{1}{2}}, \sqrt{\frac{1}{3}}, \sqrt{\frac{1}{4}} a n d \sqrt{\frac{2}{3}}$ is
Q407. The smallest among $\sqrt{\frac{1}{2}}, \sqrt{\frac{1}{3}}, \sqrt{\frac{1}{4}} a n d \sqrt{\frac{2}{3}}$ is

Q408. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.
Q408. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.

Q409. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is
Q409. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is

Q410. Find the best option to fill in the third term : Gravity : Newton :: ? : Copernicus.
Q410. Find the best option to fill in the third term : Gravity : Newton :: ? : Copernicus.