International - Quizzes (S/P) - Part 41

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International

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Showing Quizzes: 10 (401-410) [Part - 41 of 97]

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Q401. The largest of 2⁶, 3⁵, 4⁴ and 5³ is
Q401. The largest of 2⁶, 3⁵, 4⁴ and 5³ is

(A) 2⁶
(A) 2⁶

(B) 3⁵
(B) 3⁵

(D) 5³
(D) 5³

Answer: (C) 4⁴
Answer: (C) 4⁴

2⁶ = 64 3⁵ = 243 4⁴ = 256 5³ = 125

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Q402. If A : B = 3, then 144A : 36B is
Q402. If A : B = 3, then 144A : 36B is

(A) 4
(A) 4

(B) 12
(B) 12

(D) 16
(D) 16

Answer: (B) 12
Answer: (B) 12

A : B = 3 =>

\frac{A}{B}

= 3

\frac{144 A}{36 B}

\frac{144}{36} \times \frac{A}{B}

\frac{144}{36}

x 3 = 4 x 3 = 12

A : B = 3 =>

\frac{A}{B}

= 3

\frac{144 A}{36 B}

\frac{144}{36} \times \frac{A}{B}

\frac{144}{36}

x 3 = 4 x 3 = 12

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Q403. The count of prime numbers between 80 and 100 is
Q403. The count of prime numbers between 80 and 100 is

(A) 2
(A) 2

(B) 5
(B) 5

(D) 4
(D) 4

Answer: (C) 3
Answer: (C) 3

Prime numbers are numbers that are only divisible by 1 and themselves. Between 80 and 100, the prime numbers are 83, 89, and 97. Therefore, there are 3 prime numbers in this range.

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Q404. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is
Q404. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is

(A) 55
(A) 55

(B) 0
(B) 0

(D) 45
(D) 45

Answer: (B) 0
Answer: (B) 0

1st Month -> (105 * 2) - 120 = 210 - 120 = 90 2nd Month -> (90 * 2) - 120 = 180 - 120 = 60 3rd Month -> (60 * 2) - 120 = 120 - 120 = 0

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Q405. The value of $\sqrt[3]{8^{2}}$ is
Q405. The value of $\sqrt[3]{8^{2}}$ is

(A) 1
(A) 1

(B) 3
(B) 3

(D) 4
(D) 4

Answer: (D) 4
Answer: (D) 4

\sqrt[3]{8^{2}}

\sqrt[3]{64}

\sqrt[3]{4^{3}}

= 4

\sqrt[3]{8^{2}}

\sqrt[3]{64}

\sqrt[3]{4^{3}}

= 4

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Q406. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is
Q406. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is

(A) 18
(A) 18

(B) 20
(B) 20

(D) 24
(D) 24

Answer: (B) 20
Answer: (B) 20

2:3 = 8:12 N1*N2 = HCF*LCM 8*12 = 96 N1+N2 = 8+12 = 20

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Q407. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to
Q407. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to

(A) 2
(A) 2

(B) 3
(B) 3

(D) 5
(D) 5

Answer: (A) 2
Answer: (A) 2

\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}

Hence, X:Y:Z = 3:4:7

\frac{X + Y + Z}{Z}

\frac{3 + 4 + 7}{7}

\frac{14}{7}

= 2

\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}

Hence, X:Y:Z = 3:4:7

\frac{X + Y + Z}{Z}

\frac{3 + 4 + 7}{7}

\frac{14}{7}

= 2

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Q408. The smallest among $\sqrt{\frac{1}{2}}, \sqrt{\frac{1}{3}}, \sqrt{\frac{1}{4}} a n d \sqrt{\frac{2}{3}}$ is
Q408. The smallest among $\sqrt{\frac{1}{2}}, \sqrt{\frac{1}{3}}, \sqrt{\frac{1}{4}} a n d \sqrt{\frac{2}{3}}$ is

(A)

\sqrt{\frac{1}{2}}

(A)

\sqrt{\frac{1}{2}}

(B)

\sqrt{\frac{1}{3}}

(B)

\sqrt{\frac{1}{3}}

(C)

\sqrt{\frac{1}{4}}

(C)

\sqrt{\frac{1}{4}}

(D)

\sqrt{\frac{2}{3}}

(D)

\sqrt{\frac{2}{3}}

Answer: (C)

\sqrt{\frac{1}{4}}

Answer: (C)

\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}}

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Q409. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.
Q409. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.

(A) 25 years
(A) 25 years

(B) 35 years
(B) 35 years

(D) 45 years
(D) 45 years

Answer: (A) 25 years
Answer: (A) 25 years

25 years => A+B+C = 22*3 => A+(B+C) = 66 => A+(25*2) = 66 => A = 66-50 => A = 16 After 9 years A = 16+9 = 25 years

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Q410. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is
Q410. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is

(A) 16% increase
(A) 16% increase

(B) 16% decrease
(B) 16% decrease

(D) No change
(D) No change

Answer: (B) 16% decrease
Answer: (B) 16% decrease

16% decrease = 40-40-

\frac{40 * 40}{100}

% = -

\frac{1600}{100}

% = -16%

16% decrease = 40-40-

\frac{40 * 40}{100}

% = -

\frac{1600}{100}

% = -16%

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International - Quizzes (S/P) - Part 41

Q401. The largest of 26, 35, 44 and 53 isQ401. The largest of 26, 35, 44 and 53 is

Q402. If A : B = 3, then 144A : 36B isQ402. If A : B = 3, then 144A : 36B is

Q403. The count of prime numbers between 80 and 100 isQ403. The count of prime numbers between 80 and 100 is

Q405. The value of 823 isQ405. The value of 823 is

Q406. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers isQ406. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is

Q407. If X3=Y4=Z7, then X+Y+ZZ is equal toQ407. If X3=Y4=Z7, then X+Y+ZZ is equal to

Q408. The smallest among 12, 13, 14 and 23 isQ408. The smallest among 12, 13, 14 and 23 is

Q409. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.Q409. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.

Q410. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage isQ410. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is

Q401. The largest of 2⁶, 3⁵, 4⁴ and 5³ is
Q401. The largest of 2⁶, 3⁵, 4⁴ and 5³ is

Q402. If A : B = 3, then 144A : 36B is
Q402. If A : B = 3, then 144A : 36B is

Q403. The count of prime numbers between 80 and 100 is
Q403. The count of prime numbers between 80 and 100 is

Q405. The value of $\sqrt[3]{8^{2}}$ is
Q405. The value of $\sqrt[3]{8^{2}}$ is

Q406. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is
Q406. Two numbers are in the ratio 2 : 3 and the product of their HCF and LCM is 96. The sum of the two numbers is

Q407. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to
Q407. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to

Q408. The smallest among $\sqrt{\frac{1}{2}}, \sqrt{\frac{1}{3}}, \sqrt{\frac{1}{4}} a n d \sqrt{\frac{2}{3}}$ is
Q408. The smallest among $\sqrt{\frac{1}{2}}, \sqrt{\frac{1}{3}}, \sqrt{\frac{1}{4}} a n d \sqrt{\frac{2}{3}}$ is

Q409. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.
Q409. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.

Q410. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is
Q410. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is