A number when divided by 6 is diminished by 40. The number is [#871]

48

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48

$\frac{X}{3}=\frac{Y}{4}=\frac{Z}{7}$ Hence, X:Y:Z = 3:4:7 $\frac{X+Y+Z}{Z}$ = $\frac{3+4+7}{7}$ = $\frac{14}{7}$ = 2

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$\frac{X}{3}=\frac{Y}{4}=\frac{Z}{7}$ Hence, X:Y:Z = 3:4:7 $\frac{X+Y+Z}{Z}$ = $\frac{3+4+7}{7}$ = $\frac{14}{7}$ = 2

$\sqrt[3]{8^2}$ = $\sqrt[3]{64}$ = $\sqrt[3]{4^3}$ = 4

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$\sqrt[3]{8^2}$ = $\sqrt[3]{64}$ = $\sqrt[3]{4^3}$ = 4

36 days

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36 days

X * (X-12) = 40 * 4 X = 20 X + (X-12) = 20 + 20 - 12 = 28

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X * (X-12) = 40 * 4 X = 20 X + (X-12) = 20 + 20 - 12 = 28

18

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18

120

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120

An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.

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An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.

Zero

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Zero

$\frac{45}{100}*X = \frac{30}{100} * Y$ = $\frac{X}{Y} = \frac{30*100}{100*45}$ = $\frac{X}{Y} = \frac{2}{3}$ = X:Y = 2:3

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$\frac{45}{100}*X = \frac{30}{100} * Y$ = $\frac{X}{Y} = \frac{30*100}{100*45}$ = $\frac{X}{Y} = \frac{2}{3}$ = X:Y = 2:3

The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.

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The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.