Find the least number by which 1250 must be multiplied to make it a perfect square. [#1700]

1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 $\sqrt{2500}$ = 2*5*5 = 50

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1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 $\sqrt{2500}$ = 2*5*5 = 50

A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

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A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

43

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43

$\frac{X}{3}=\frac{Y}{4}=\frac{Z}{7}$ Hence, X:Y:Z = 3:4:7 $\frac{X+Y+Z}{Z}$ = $\frac{3+4+7}{7}$ = $\frac{14}{7}$ = 2

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$\frac{X}{3}=\frac{Y}{4}=\frac{Z}{7}$ Hence, X:Y:Z = 3:4:7 $\frac{X+Y+Z}{Z}$ = $\frac{3+4+7}{7}$ = $\frac{14}{7}$ = 2

(360°/15) * (7-1) = 144°

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(360°/15) * (7-1) = 144°

= $\sqrt{0.04} + \sqrt{1.44} + \sqrt{1.69} + \sqrt{0.0009}$ = $\sqrt{\mathrm{0.02*0.02}} + \sqrt{\mathrm{1.2*1.2}} + \sqrt{\mathrm{1.3*1.3}} + \sqrt{\mathrm{0.03*0.03}}$ = 0.2 + 1.2 + 1.3 + 0.03 = 2.73

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= $\sqrt{0.04} + \sqrt{1.44} + \sqrt{1.69} + \sqrt{0.0009}$ = $\sqrt{\mathrm{0.02*0.02}} + \sqrt{\mathrm{1.2*1.2}} + \sqrt{\mathrm{1.3*1.3}} + \sqrt{\mathrm{0.03*0.03}}$ = 0.2 + 1.2 + 1.3 + 0.03 = 2.73

4 : 5

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4 : 5

120

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120

7 and 8

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7 and 8

A pentagon is a polygon with five sides, like the shape of the Pentagon building in Washington, D.C.

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A pentagon is a polygon with five sides, like the shape of the Pentagon building in Washington, D.C.

2:3 = 8:12 N1*N2 = HCF*LCM 8*12 = 96 N1+N2 = 8+12 = 20

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2:3 = 8:12 N1*N2 = HCF*LCM 8*12 = 96 N1+N2 = 8+12 = 20