In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is [#1699]
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Q1. In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is
Q1. In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is
(A) 35
(A) 35
(A) 35
(B) 42
(B) 42
(B) 42
(C) 49
(C) 49
(C) 49
(D) 56
(D) 56
(D) 56
Answer: (C) 49
Answer: (C) 49
Answer: (C) 49
1+3+5+7+9+11+13 = 49
1+3+5+7+9+11+13 = 49
1+3+5+7+9+11+13 = 49
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Related MCQ Quizzes
Q1. If the decimal number 34p5 is divisible by 9, then the value of p is
Q1. If the decimal number 34p5 is divisible by 9, then the value of p is
(A) 8
(A) 8
(A) 8
(B) 7
(B) 7
(B) 7
(C) 4
(C) 4
(C) 4
(D) 6
(D) 6
(D) 6
Answer: (D) 6
Answer: (D) 6
Answer: (D) 6
34p5 -> 3+4+p+5 = 12+p
12+p = 9k
12+6 = 18 = 9k
p = 6
34p5 -> 3+4+p+5 = 12+p 12+p = 9k 12+6 = 18 = 9k p = 6
34p5 -> 3+4+p+5 = 12+p 12+p = 9k 12+6 = 18 = 9k p = 6
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Q2. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?
Q2. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?
(A) 120 sec
(A) 120 sec
(A) 120 sec
(B) 100 sec
(B) 100 sec
(B) 100 sec
(C) 60 sec
(C) 60 sec
(C) 60 sec
(D) 50 sec
(D) 50 sec
(D) 50 sec
Answer: (D) 50 sec
Answer: (D) 50 sec
Answer: (D) 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s
As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely.
Hence This train will be ahead of 100m with a speed of 2m/s.
Hence The time to cross each other will take = 100m / (2m/s)
= 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec
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Q3. What is the term for a angle greater than 90 degrees but less than 180 degrees?
Q3. What is the term for a angle greater than 90 degrees but less than 180 degrees?
(A) Acute angle
(A) Acute angle
(A) Acute angle
(B) Right angle
(B) Right angle
(B) Right angle
(C) Obtuse angle
(C) Obtuse angle
(C) Obtuse angle
(D) Straight angle
(D) Straight angle
(D) Straight angle
Answer: (C) Obtuse angle
Answer: (C) Obtuse angle
Answer: (C) Obtuse angle
An obtuse angle is an angle greater than 90 degrees but less than 180 degrees, like the angle formed by two walls that meet at a corner.
An obtuse angle is an angle greater than 90 degrees but less than 180 degrees, like the angle formed by two walls that meet at a corner.
An obtuse angle is an angle greater than 90 degrees but less than 180 degrees, like the angle formed by two walls that meet at a corner.
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Q4. What is the term for the point where two or more lines intersect?
Q4. What is the term for the point where two or more lines intersect?
(A) Vertex
(A) Vertex
(A) Vertex
(B) Edge
(B) Edge
(B) Edge
(C) Face
(C) Face
(C) Face
(D) Intersection
(D) Intersection
(D) Intersection
Answer: (A) Vertex
Answer: (A) Vertex
Answer: (A) Vertex
In geometry, a vertex (plural: vertices) is the point where two or more lines, rays, or edges meet, like the corner of a triangle or the point where two streets intersect.
In geometry, a vertex (plural: vertices) is the point where two or more lines, rays, or edges meet, like the corner of a triangle or the point where two streets intersect.
In geometry, a vertex (plural: vertices) is the point where two or more lines, rays, or edges meet, like the corner of a triangle or the point where two streets intersect.
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Q5. What is the term for all positive and negative numbers as a whole including zero?
Q5. What is the term for all positive and negative numbers as a whole including zero?
(A) Real Numbers
(A) Real Numbers
(A) Real Numbers
(B) Natural Numbers
(B) Natural Numbers
(B) Natural Numbers
(C) Whole Numbers
(C) Whole Numbers
(C) Whole Numbers
(D) Integer Numbers
(D) Integer Numbers
(D) Integer Numbers
Answer: (D) Integer Numbers
Answer: (D) Integer Numbers
Answer: (D) Integer Numbers
Integers
Integers
Integers
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Q6. A number when divided by 6 is diminished by 40. The number is
Q6. A number when divided by 6 is diminished by 40. The number is
(A) 72
(A) 72
(A) 72
(B) 48
(B) 48
(B) 48
(C) 60
(C) 60
(C) 60
(D) 84
(D) 84
(D) 84
Answer: (B) 48
Answer: (B) 48
Answer: (B) 48
48
48
48
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Q7. What is the formula to calculate the area of a circle?
Q7. What is the formula to calculate the area of a circle?
(A) A = πr2
(A) A = πr2
(A) A = πr2
(B) A = 2πr
(B) A = 2πr
(B) A = 2πr
(C) A = πd
(C) A = πd
(C) A = πd
(D) A = 1/2πr2
(D) A = 1/2πr2
(D) A = 1/2πr2
Answer: (A) A = πr2
Answer: (A) A = πr2
Answer: (A) A = πr2
The formula to calculate the area of a circle is A = πr2, where A is the area and r is the radius of the circle.
The formula to calculate the area of a circle is A = πr2, where A is the area and r is the radius of the circle.
The formula to calculate the area of a circle is A = πr2, where A is the area and r is the radius of the circle.
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Q8. Find the least number by which 1250 must be multiplied to make it a perfect square.
Q8. Find the least number by which 1250 must be multiplied to make it a perfect square.
(A) 4
(A) 4
(A) 4
(B) 3
(B) 3
(B) 3
(C) 5
(C) 5
(C) 5
(D) 2
(D) 2
(D) 2
Answer: (D) 2
Answer: (D) 2
Answer: (D) 2
1250 = 2*5*5*5*5
1250*2 = 2*2*5*5*5*5 = 2500
= 2*5*5 = 50
1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 = 2*5*5 = 50
1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500 = 2*5*5 = 50
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Q9. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q9. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
(A) 1.5 km
(A) 1.5 km
(A) 1.5 km
(B) 1.75 km
(B) 1.75 km
(B) 1.75 km
(C) 1.2 km
(C) 1.2 km
(C) 1.2 km
(D) 1.25 km
(D) 1.25 km
(D) 1.25 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
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Q10. The count of prime numbers between 80 and 100 is
Q10. The count of prime numbers between 80 and 100 is
(A) 2
(A) 2
(A) 2
(B) 5
(B) 5
(B) 5
(C) 3
(C) 3
(C) 3
(D) 4
(D) 4
(D) 4
Answer: (C) 3
Answer: (C) 3
Answer: (C) 3
Prime numbers are numbers that are only divisible by 1 and themselves. Between 80 and 100, the prime numbers are 83, 89, and 97. Therefore, there are 3 prime numbers in this range.
Prime numbers are numbers that are only divisible by 1 and themselves. Between 80 and 100, the prime numbers are 83, 89, and 97. Therefore, there are 3 prime numbers in this range.
Prime numbers are numbers that are only divisible by 1 and themselves. Between 80 and 100, the prime numbers are 83, 89, and 97. Therefore, there are 3 prime numbers in this range.
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