ADRE Exam 2024 - Part 29 - 592+ MCQ Quizzes | QuizList (S/P/P) - SPPMMC

ADRE Exam 2024 - Part 29 - 592+ MCQ Quizzes | QuizList (S/P/P)

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592 quizzes

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2025-05-01 00:36:43

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QuizList Name: ADRE Exam 2024

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Total Quizzes: 592

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QuizList Published Date: 2024-07-12

QuizList Last Update: 2025-05-01 00:36:43

QuizList Description: The State-Level Recruitment Commission, Assam conducts the Assam Direct Recruitment Examination (ADRE) the written examination for Grade III positions across various departments in the state government administration.

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Q561. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is
Q561. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is

(A) 25
(A) 25
(B) 41
(B) 41
(C) 13
(C) 13
(D) 11
(D) 11
Answer: (D) 11
Answer: (D) 11
11
11

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@1088

2024-05-01

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Q562. When the numerator of a fraction increases by 3, the fraction increases by its three-fourth. The numerator of the fraction is
Q562. When the numerator of a fraction increases by 3, the fraction increases by its three-fourth. The numerator of the fraction is

(A) 3
(A) 3
(B) 4
(B) 4
(C) 5
(C) 5
(D) 6
(D) 6
Answer: (B) 4
Answer: (B) 4
4
4

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@1089

2024-05-01

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Q563. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
Q563. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is

(A) 13
(A) 13
(B) 11
(B) 11
(C) 16
(C) 16
(D) 9
(D) 9
Answer: (A) 13
Answer: (A) 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13

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@1109

2024-05-09

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Q564. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is
Q564. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is

(A) 8
(A) 8
(B) 12
(B) 12
(C) 20
(C) 20
(D) 36
(D) 36
Answer: (C) 20
Answer: (C) 20
=> 2x * 3x = 96 => 6x2 = 96 => x2 = 96/6 => x2 = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20
=> 2x * 3x = 96 => 6x2 = 96 => x2 = 96/6 => x2 = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20

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@1110

2024-05-09

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Q565. If the salary of A is 25% more than that of B, how much percentage is the salary of B lower than that of A?
Q565. If the salary of A is 25% more than that of B, how much percentage is the salary of B lower than that of A?

(A) 20%
(A) 20%
(B) 25%
(B) 25%
(C) 1212%
(C) 1212%
(D) 1612%
(D) 1612%
Answer: (A) 20%
Answer: (A) 20%
20% = 25100+25 =  * 100% 25125 * 100% = 20%
20% = 25100+25 =  * 100% 25125 * 100% = 20%

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@1111

2024-05-09

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Q566. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
Q566. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was

(A) 5
(A) 5
(B) 7
(B) 7
(C) 10
(C) 10
(D) 14
(D) 14
Answer: (B) 7
Answer: (B) 7
7 => x * 2x = 98 => x2 = 982 => x2 = 49 => x = 7
7 => x * 2x = 98 => x2 = 982 => x2 = 49 => x = 7

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@1112

2024-05-09

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Q567. The value of 0.04 + 1.44 + 1.69 + 0.0009 is :
Q567. The value of 0.04 + 1.44 + 1.69 + 0.0009 is :

(A) 1.73
(A) 1.73
(B) 2.03
(B) 2.03
(C) 2.73
(C) 2.73
(D) 1.03
(D) 1.03
Answer: (C) 2.73
Answer: (C) 2.73
= 0.04 + 1.44 + 1.69 + 0.0009 = 0.02*0.02 + 1.2*1.2 + 1.3*1.3 + 0.03*0.03 = 0.2 + 1.2 + 1.3 + 0.03 = 2.73
= 0.04 + 1.44 + 1.69 + 0.0009 = 0.02*0.02 + 1.2*1.2 + 1.3*1.3 + 0.03*0.03 = 0.2 + 1.2 + 1.3 + 0.03 = 2.73

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@1117

2024-05-09

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Q568. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :
Q568. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :

(A) 2 : 3
(A) 2 : 3
(B) 3 : 5
(B) 3 : 5
(C) 3 : 2
(C) 3 : 2
(D) 2 : 5
(D) 2 : 5
Answer: (A) 2 : 3
Answer: (A) 2 : 3
45100*X = 30100 * Y = XY = 30*100100*45 = XY = 23 = X:Y = 2:3
45100*X = 30100 * Y = XY = 30*100100*45 = XY = 23 = X:Y = 2:3

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@1118

2024-05-09

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Q569. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :
Q569. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :

(A) 5,420
(A) 5,420
(B) 5,580
(B) 5,580
(C) 5,620
(C) 5,620
(D) 5,780
(D) 5,780
Answer: (B) 5,580
Answer: (B) 5,580
The formula for the sum of the first n terms of an arithmetic progression is Sn = n2(a+an) 302(12+12*30) = 15*(12+360) = 15 * 372 = 5580
The formula for the sum of the first n terms of an arithmetic progression is Sn = n2(a+an) 302(12+12*30) = 15*(12+360) = 15 * 372 = 5580

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@1119

2024-05-09

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Q570. Find the median of the data set.
Q570. Find the median of the data set.

1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12

1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12
(A) 8
(A) 8
(B) 7
(B) 7
(C) 5
(C) 5
(D) 4
(D) 4
Answer: (C) 5
Answer: (C) 5
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12 = 1, 1, 1, 2, 4, 5, 5, 7, 8, 12, 12, 16, 17 Total numbers of values N = 13 Hence median value = (N + 1)/2 = (13 + 1)/2 = 7th 7th Number = 5
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12 = 1, 1, 1, 2, 4, 5, 5, 7, 8, 12, 12, 16, 17 Total numbers of values N = 13 Hence median value = (N + 1)/2 = (13 + 1)/2 = 7th 7th Number = 5

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@1120

2024-05-09

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Q571. Find the value of 225729-25144-1681
Q571. Find the value of 225729-25144-1681

(A) -59
(A) -59
(B) -712
(B) -712
(C) -2027
(C) -2027
(D) -1136
(D) -1136
Answer: (D) -1136
Answer: (D) -1136
225729-25144-1681 = 15*1527*27-5*512*12-4*49*9 = 1527-512-49 = 60-45-48108 = -33108 = -1136
225729-25144-1681 = 15*1527*27-5*512*12-4*49*9 = 1527-512-49 = 60-45-48108 = -33108 = -1136

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@1121

2024-05-09

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Q572. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q572. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :

(A) 1.5 km
(A) 1.5 km
(B) 1.75 km
(B) 1.75 km
(C) 1.2 km
(C) 1.2 km
(D) 1.25 km
(D) 1.25 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

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@1122

2024-05-15

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Q573. The price of an article is first decreased by 40% and then increased by 20%. The net change in the price will be :
Q573. The price of an article is first decreased by 40% and then increased by 20%. The net change in the price will be :

(A) 20%
(A) 20%
(B) 40%
(B) 40%
(C) 24%
(C) 24%
(D) 28%
(D) 28%
Answer: (D) 28%
Answer: (D) 28%
Net change (-40 + 20 + (-40)*20100)% = (-20 + -800100)% = (-20 - 8)% = -28% = 28%
Net change (-40 + 20 + (-40)*20100)% = (-20 + -800100)% = (-20 - 8)% = -28% = 28%

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@1123

2024-05-15

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Q574. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Q574. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :

(A) 60 years
(A) 60 years
(B) 51 years
(B) 51 years
(C) 48 years
(C) 48 years
(D) 45 years
(D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.

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@1127

2024-05-15

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Q575. If 20% of a is b, then b% of 20 is the same as :
Q575. If 20% of a is b, then b% of 20 is the same as :

(A) 4% of a
(A) 4% of a
(B) 8% of a
(B) 8% of a
(C) 6% of a
(C) 6% of a
(D) 10% of a
(D) 10% of a
Answer: (A) 4% of a
Answer: (A) 4% of a
20% of a is b Hence b = 20% of a = 20a/100 b% of 20 = 20% of b = (20/100) * 20a/100 = (20*20*a)/(100*100) = 4a/100 = (4/100) * a = 4% of a
20% of a is b Hence b = 20% of a = 20a/100 b% of 20 = 20% of b = (20/100) * 20a/100 = (20*20*a)/(100*100) = 4a/100 = (4/100) * a = 4% of a

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@1129

2024-05-15

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Q576. Select the number pair in which the two numbers are related in the same way as 35 : 6.
Q576. Select the number pair in which the two numbers are related in the same way as 35 : 6.

(A) 85 : 9
(A) 85 : 9
(B) 64 : 8
(B) 64 : 8
(C) 26 : 5
(C) 26 : 5
(D) 120 : 11
(D) 120 : 11
Answer: (D) 120 : 11
Answer: (D) 120 : 11
62-1 : 6 = 35 : 6 112-1 : 11 = 120 : 11
62-1 : 6 = 35 : 6 112-1 : 11 = 120 : 11

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@1130

2024-05-15

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Q577. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?
Q577. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?

(A) 120 sec
(A) 120 sec
(B) 100 sec
(B) 100 sec
(C) 60 sec
(C) 60 sec
(D) 50 sec
(D) 50 sec
Answer: (D) 50 sec
Answer: (D) 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec

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@1132

2024-05-15

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Q578. 5 : 27 :: 9 : ________
Q578. 5 : 27 :: 9 : ________

Fill the blank.

Fill the blank.
(A) 83
(A) 83
(B) 81
(B) 81
(C) 36
(C) 36
(D) 18
(D) 18
Answer: (A) 83
Answer: (A) 83
5 : (52 + 2) = 5 : 27 Hence 9 : (92 + 2) = 9 : 83
5 : (52 + 2) = 5 : 27 Hence 9 : (92 + 2) = 9 : 83

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@1134

2024-05-15

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Q579. What is the value of x in the equation 2x + 5 = 11?
Q579. What is the value of x in the equation 2x + 5 = 11?

(A) 2
(A) 2
(B) 3
(B) 3
(C) 4
(C) 4
(D) 5
(D) 5
Answer: (B) 3
Answer: (B) 3
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.

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@1256

2024-07-02

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Q580. What is the formula to calculate the area of a circle?
Q580. What is the formula to calculate the area of a circle?

(A) A = πr2
(A) A = πr2
(B) A = 2πr
(B) A = 2πr
(C) A = πd
(C) A = πd
(D) A = 1/2πr2
(D) A = 1/2πr2
Answer: (A) A = πr2
Answer: (A) A = πr2
The formula to calculate the area of a circle is A = πr2, where A is the area and r is the radius of the circle.
The formula to calculate the area of a circle is A = πr2, where A is the area and r is the radius of the circle.

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@1257

2024-07-02

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