Select the number pair in which the two numbers are related in the same way as 35 : 6. [#1130]
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Q1. Select the number pair in which the two numbers are related in the same way as 35 : 6.
Q1. Select the number pair in which the two numbers are related in the same way as 35 : 6.
(A) 85 : 9
(A) 85 : 9
(A) 85 : 9
(B) 64 : 8
(B) 64 : 8
(B) 64 : 8
(C) 26 : 5
(C) 26 : 5
(C) 26 : 5
(D) 120 : 11
(D) 120 : 11
(D) 120 : 11
Answer: (D) 120 : 11
Answer: (D) 120 : 11
Answer: (D) 120 : 11
62-1 : 6 = 35 : 6
112-1 : 11 = 120 : 11
62-1 : 6 = 35 : 6 112-1 : 11 = 120 : 11
62-1 : 6 = 35 : 6 112-1 : 11 = 120 : 11
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Related MCQ Quizzes
Q1. If ROBOTICS is coded as OROBITSC, then PROJECTS would be coded as
Q1. If ROBOTICS is coded as OROBITSC, then PROJECTS would be coded as
(A) ROPEJTSC
(A) ROPEJTSC
(A) ROPEJTSC
(B) RPJOCEST
(B) RPJOCEST
(B) RPJOCEST
(C) RPJOECST
(C) RPJOECST
(C) RPJOECST
(D) ROJPCEST
(D) ROJPCEST
(D) ROJPCEST
Answer: (B) RPJOCEST
Answer: (B) RPJOCEST
Answer: (B) RPJOCEST
ROBOTICS :: PROJECTS
OROBITSC :: RPJOCEST
ROBOTICS :: PROJECTS OROBITSC :: RPJOCEST
ROBOTICS :: PROJECTS OROBITSC :: RPJOCEST
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Q2. The sum of two numbers is 15 and the sum of their squares is 113. The numbers are
Q2. The sum of two numbers is 15 and the sum of their squares is 113. The numbers are
(A) 4 and 10
(A) 4 and 10
(A) 4 and 10
(B) 6 and 9
(B) 6 and 9
(B) 6 and 9
(C) 5 and 10
(C) 5 and 10
(C) 5 and 10
(D) 7 and 8
(D) 7 and 8
(D) 7 and 8
Answer: (D) 7 and 8
Answer: (D) 7 and 8
Answer: (D) 7 and 8
7 and 8
7 and 8
7 and 8
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Q3. How many prime numbers exist, which are less than 40?
Q3. How many prime numbers exist, which are less than 40?
(A) 10
(A) 10
(A) 10
(B) 11
(B) 11
(B) 11
(C) 12
(C) 12
(C) 12
(D) 13
(D) 13
(D) 13
Answer: (C) 12
Answer: (C) 12
Answer: (C) 12
12
12
12
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Q4. The least number by which 2450 must be multiplied to make it a perfect square, is
Q4. The least number by which 2450 must be multiplied to make it a perfect square, is
(A) 2
(A) 2
(A) 2
(B) 3
(B) 3
(B) 3
(C) 4
(C) 4
(C) 4
(D) 5
(D) 5
(D) 5
Answer: (A) 2
Answer: (A) 2
Answer: (A) 2
2
2
2
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Q5. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Q5. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
(A) 60 years
(A) 60 years
(A) 60 years
(B) 51 years
(B) 51 years
(B) 51 years
(C) 48 years
(C) 48 years
(C) 48 years
(D) 45 years
(D) 45 years
(D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
The son becomes 15 years old after 3 years.
Hence son's present age = 15 years - 3 years = 12 years
Man is four times as old as his son.
Hence Man's present age = 12 years * 4 = 48 years
Man is 3 years older than his wife.
Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
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Q6. Which of the following is a prime number?
Q6. Which of the following is a prime number?
81,33,71,93
81,33,71,93
81,33,71,93
(A) 93
(A) 93
(A) 93
(B) 33
(B) 33
(B) 33
(C) 71
(C) 71
(C) 71
(D) 81
(D) 81
(D) 81
Answer: (C) 71
Answer: (C) 71
Answer: (C) 71
71
71
71
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Q7. What is the value of x in the equation 2x + 5 = 11?
Q7. What is the value of x in the equation 2x + 5 = 11?
(A) 2
(A) 2
(A) 2
(B) 3
(B) 3
(B) 3
(C) 4
(C) 4
(C) 4
(D) 5
(D) 5
(D) 5
Answer: (B) 3
Answer: (B) 3
Answer: (B) 3
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
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Q8. If '÷' means ‘addition’, ‘+’ means ‘subtraction’, ‘–’ means ‘multiplication’ and ‘×’ means ‘division’, then the value of 18 ÷ 12 × 4 – 5 is
Q8. If '÷' means ‘addition’, ‘+’ means ‘subtraction’, ‘–’ means ‘multiplication’ and ‘×’ means ‘division’, then the value of 18 ÷ 12 × 4 – 5 is
(A) 25
(A) 25
(A) 25
(B) 35
(B) 35
(B) 35
(C) 40
(C) 40
(C) 40
(D) 33
(D) 33
(D) 33
Answer: (D) 33
Answer: (D) 33
Answer: (D) 33
33
33
33
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Q9. Find the value of the following expression
Q9. Find the value of the following expression
48÷12+4×25÷5
48÷12+4×25÷5
48÷12+4×25÷5
(A) 15
(A) 15
(A) 15
(B) 24
(B) 24
(B) 24
(C) 40
(C) 40
(C) 40
(D) 25
(D) 25
(D) 25
Answer: (B) 24
Answer: (B) 24
Answer: (B) 24
24
24
24
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Q10. If REAR = 42, TEAR = 44 and DEAR = 28, then which of the following sets is incorrectly paired?
Q10. If REAR = 42, TEAR = 44 and DEAR = 28, then which of the following sets is incorrectly paired?
(A) PEAR = 40
(A) PEAR = 40
(A) PEAR = 40
(B) FEAR = 32
(B) FEAR = 32
(B) FEAR = 32
(C) BEAR = 26
(C) BEAR = 26
(C) BEAR = 26
(D) GEAR = 31
(D) GEAR = 31
(D) GEAR = 31
Answer: (B) FEAR = 32
Answer: (B) FEAR = 32
Answer: (B) FEAR = 32
FEAR = 32
REAR = 18+5+1+18 = 42
TEAR = 20+5+1+18 = 44
DEAR = 4+5+1+18 = 28
FEAR = 6+5+1+18 = 30
FEAR = 32 REAR = 18+5+1+18 = 42 TEAR = 20+5+1+18 = 44 DEAR = 4+5+1+18 = 28 FEAR = 6+5+1+18 = 30
FEAR = 32 REAR = 18+5+1+18 = 42 TEAR = 20+5+1+18 = 44 DEAR = 4+5+1+18 = 28 FEAR = 6+5+1+18 = 30
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