In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is [#1699]

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Q1. In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is
Q1. In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is

(A) 35
(A) 35

(B) 42
(B) 42

(D) 56
(D) 56

Answer: (C) 49
Answer: (C) 49

1+3+5+7+9+11+13 = 49

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2024-10-23

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Q1. A 20 m long ladder is leaning on a vertical wall. It makes an angle of 30° with the ground. The height of the point the ladder touches wall is
Q1. A 20 m long ladder is leaning on a vertical wall. It makes an angle of 30° with the ground. The height of the point the ladder touches wall is

(A) 10 m
(A) 10 m

(B) 17.32 m
(B) 17.32 m

(D) 13 m
(D) 13 m

Answer: (A) 10 m
Answer: (A) 10 m

10 m

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Q2. The value of $\sqrt[3]{8^{2}}$ is
Q2. The value of $\sqrt[3]{8^{2}}$ is

(A) 1
(A) 1

(B) 3
(B) 3

(D) 4
(D) 4

Answer: (D) 4
Answer: (D) 4

\sqrt[3]{8^{2}}

\sqrt[3]{64}

\sqrt[3]{4^{3}}

= 4

\sqrt[3]{8^{2}}

\sqrt[3]{64}

\sqrt[3]{4^{3}}

= 4

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Q3. The smallest positive integer that is simultaneously divisible by 6, 8 and 12 is
Q3. The smallest positive integer that is simultaneously divisible by 6, 8 and 12 is

(A) 24
(A) 24

(B) 18
(B) 18

(D) 36
(D) 36

Answer: (A) 24
Answer: (A) 24

6*4 = 24 8*3 = 24 12*2 = 24

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Q4. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q4. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :

(A) 1.5 km
(A) 1.5 km

(B) 1.75 km
(B) 1.75 km

(D) 1.25 km
(D) 1.25 km

Answer: (C) 1.2 km
Answer: (C) 1.2 km

A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

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2024-05-15

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Q5. Select the number pair in which the two numbers are related in the same way as 35 : 6.
Q5. Select the number pair in which the two numbers are related in the same way as 35 : 6.

(A) 85 : 9
(A) 85 : 9

(B) 64 : 8
(B) 64 : 8

(D) 120 : 11
(D) 120 : 11

Answer: (D) 120 : 11
Answer: (D) 120 : 11

6²-1 : 6 = 35 : 6 11²-1 : 11 = 120 : 11

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2024-05-15

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Q6. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
Q6. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is

(A) 13
(A) 13

(B) 11
(B) 11

(D) 9
(D) 9

Answer: (A) 13
Answer: (A) 13

The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13

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2024-05-09

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Q7. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be
Q7. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be

(A) 3
(A) 3

(B) 25
(B) 25

(D) 33
(D) 33

Answer: (C) 5
Answer: (C) 5

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2024-04-19

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Q8. 3/4 of a number is 19 less than the original number. The number is
Q8. 3/4 of a number is 19 less than the original number. The number is

(A) 62
(A) 62

(B) 64
(B) 64

(D) 76
(D) 76

Answer: (D) 76
Answer: (D) 76

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2024-03-03

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Q9. When three times of a given number is subtracted from the square of the number, the result is the number itself. The number is
Q9. When three times of a given number is subtracted from the square of the number, the result is the number itself. The number is

(A) 4
(A) 4

(B) 2
(B) 2

(D) -4
(D) -4

Answer: (A) 4
Answer: (A) 4

4^{2 - (4*3)
= 16 - 12
= 4
4^{2 - (4*3)
= 16 - 12
= 4}}

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Q10. Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest?
Q10. Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest?

I. 376 II. 629 III. 921 IV. 397

I. 376 II. 629 III. 921 IV. 397

(A) III
(A) III

(B) II
(B) II

(D) IV
(D) IV

Answer: (A) III
Answer: (A) III

376 -> 367 629 -> 269 921 -> 129 * 397 -> 379

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In a range of consecutive numbers starting with 1, all the even numbers are removed. From the remaining, consider the first 7 numbers. The sum of these 7 numbers is [#1699]

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