MCQ Quizzes of the Day - 2024-05-15
@2024-05-15
•14 quizzes
•
Q1. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?
Q1. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?
Answer: (D) 50 sec
Answer: (D) 50 sec
Answer: (D) 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s
As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely.
Hence This train will be ahead of 100m with a speed of 2m/s.
Hence The time to cross each other will take = 100m / (2m/s)
= 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec
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Q2. Select the number pair in which the two numbers are related in the same way as 35 : 6.
Q2. Select the number pair in which the two numbers are related in the same way as 35 : 6.
Answer: (D) 120 : 11
Answer: (D) 120 : 11
Answer: (D) 120 : 11
62-1 : 6 = 35 : 6
112-1 : 11 = 120 : 11
62-1 : 6 = 35 : 6 112-1 : 11 = 120 : 11
62-1 : 6 = 35 : 6 112-1 : 11 = 120 : 11
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Q3. Sarita and Savita were coming to each other in the garden in the morning. Savita saw that Sarita’s shadow was at Sarita’s left side. Which direction was Savita facing to?
Q3. Sarita and Savita were coming to each other in the garden in the morning. Savita saw that Sarita’s shadow was at Sarita’s left side. Which direction was Savita facing to?
Answer: (A) South
Answer: (A) South
Answer: (A) South
Sarita was facing to North and Savita was facing to South.
In the morning the sun was in the East and the shadow was in the west.
As Sarita was facing to North his shadow was in the west and west was in left side of her.
Sarita was facing to North and Savita was facing to South. In the morning the sun was in the East and the shadow was in the west. As Sarita was facing to North his shadow was in the west and west was in left side of her.
Sarita was facing to North and Savita was facing to South. In the morning the sun was in the East and the shadow was in the west. As Sarita was facing to North his shadow was in the west and west was in left side of her.
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Q4. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q4. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Answer: (C) 1.2 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
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Q5. Priya booked a ticket for a movie whose trailer was released 20 days before she booked the ticket. She watched the movie 45 days after the trailer was released. The movie was released 16 day before the day on which Priya watched the movie. On which day of the week was the movie released if she booked the ticket on Sunday?
Q5. Priya booked a ticket for a movie whose trailer was released 20 days before she booked the ticket. She watched the movie 45 days after the trailer was released. The movie was released 16 day before the day on which Priya watched the movie. On which day of the week was the movie released if she booked the ticket on Sunday?
Answer: (D) Tuesday
Answer: (D) Tuesday
Answer: (D) Tuesday
Priya booked the ticket after 20 days of the trailer was released.
She watched the movie 45 days after the trailer was released.
Hence She watched the movie (45-20) = 25 days after booking the ticket.
The movie was released 16 day before the day on which Priya watched the movie.
Hence the movie was released (45-16) = 29 days after the trailer was released.
Hence the movie was released (29-20) = 9 days after booking the ticket.
If she booked the ticket on Sunday then the movie released on Tuesday
Priya booked the ticket after 20 days of the trailer was released. She watched the movie 45 days after the trailer was released. Hence She watched the movie (45-20) = 25 days after booking the ticket. The movie was released 16 day before the day on which Priya watched the movie. Hence the movie was released (45-16) = 29 days after the trailer was released. Hence the movie was released (29-20) = 9 days after booking the ticket. If she booked the ticket on Sunday then the movie released on Tuesday
Priya booked the ticket after 20 days of the trailer was released. She watched the movie 45 days after the trailer was released. Hence She watched the movie (45-20) = 25 days after booking the ticket. The movie was released 16 day before the day on which Priya watched the movie. Hence the movie was released (45-16) = 29 days after the trailer was released. Hence the movie was released (29-20) = 9 days after booking the ticket. If she booked the ticket on Sunday then the movie released on Tuesday
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Q6. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Q6. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Answer: (D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
The son becomes 15 years old after 3 years.
Hence son's present age = 15 years - 3 years = 12 years
Man is four times as old as his son.
Hence Man's present age = 12 years * 4 = 48 years
Man is 3 years older than his wife.
Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
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Q7. AQRD : BRSE :: LMTJ : ________
Q7. AQRD : BRSE :: LMTJ : ________
Answer: (D) MMUK
Answer: (D) MMUK
Answer: (D) MMUK
AQRD : (A+1)(Q+1)(R+1)(D+1) = AQRD : BRSE
LMTJ = (L+1)(M+1)(T+1)(J+1) = LMTJ : MMUK
AQRD : (A+1)(Q+1)(R+1)(D+1) = AQRD : BRSE LMTJ = (L+1)(M+1)(T+1)(J+1) = LMTJ : MMUK
AQRD : (A+1)(Q+1)(R+1)(D+1) = AQRD : BRSE LMTJ = (L+1)(M+1)(T+1)(J+1) = LMTJ : MMUK
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Q8. The price of an article is first decreased by 40% and then increased by 20%. The net change in the price will be :
Q8. The price of an article is first decreased by 40% and then increased by 20%. The net change in the price will be :
Answer: (D) 28%
Answer: (D) 28%
Answer: (D) 28%
Net change (-40 + 20 + )%
= (-20 + )%
= (-20 - 8)%
= -28%
= 28%
Net change (-40 + 20 + )% = (-20 + )% = (-20 - 8)% = -28% = 28%
Net change (-40 + 20 + )% = (-20 + )% = (-20 - 8)% = -28% = 28%
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Q9. Which letter of the English Alphabet is the seventh from left of sixteenth from right?
Q9. Which letter of the English Alphabet is the seventh from left of sixteenth from right?
Answer: (C) R
Answer: (C) R
Answer: (C) R
K is the 19th from right
R is the 7th from left of K.
K is the 19th from right R is the 7th from left of K.
K is the 19th from right R is the 7th from left of K.
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Q10. Five boys are sitting in a circle facing inward. Ajay is between Rohit and Doljit. Suman is at the left of Shyamal, Rohit is at the left of Suman. Who is sitting at the immediate right of Ajay?
Q10. Five boys are sitting in a circle facing inward. Ajay is between Rohit and Doljit. Suman is at the left of Shyamal, Rohit is at the left of Suman. Who is sitting at the immediate right of Ajay?
Answer: (C) Rohit
Answer: (C) Rohit
Answer: (C) Rohit
Rohit
Rohit
Rohit
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