Calculation Involved (Calculation is Required) | 287+ MCQ Quizzes | Category (R/R/M) - SPPMMC

Calculation Involved (Calculation is Required) | MCQ Quizzes | Category (R/R/M)

@15

57 quizzes

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2026-08-03 03:29:01

In this category calculation is involved.
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Category UID: 15

Label UID: 39

Category Name: Calculation Involved

Category Full Name: Calculation is Required

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Total Quizzes: 287

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Last Refreshed: 2026-08-03 03:29:01

Category Description: In this category calculation is involved.

Q1. Three numbers are in the ratio 3:4:5. The sum of the largest and the smallest equals the sum of the third and 52. The smallest number is
Q1. Three numbers are in the ratio 3:4:5. The sum of the largest and the smallest equals the sum of the third and 52. The smallest number is

(A) 48
(A) 48
(B) 36
(B) 36
(C) 39
(C) 39
(D) 30
(D) 30
Answer: (C) 39
Answer: (C) 39
39
39

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@899

2024-03-03

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Q2. If the sum of five consecutive numbers is 190, then the lowest number amongst them is
Q2. If the sum of five consecutive numbers is 190, then the lowest number amongst them is

(A) 40
(A) 40
(B) 19
(B) 19
(C) 38
(C) 38
(D) 36
(D) 36
Answer: (D) 36
Answer: (D) 36
36
36

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@1027

2024-04-19

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Q3. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
Q3. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was

(A) 5
(A) 5
(B) 7
(B) 7
(C) 10
(C) 10
(D) 14
(D) 14
Answer: (B) 7
Answer: (B) 7
7 => x * 2x = 98 => x2 = 982 => x2 = 49 => x = 7
7 => x * 2x = 98 => x2 = 982 => x2 = 49 => x = 7

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@1112

2024-05-09

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Q4. Three fourth of a number is more than two third of the number by 5. Then the number is
Q4. Three fourth of a number is more than two third of the number by 5. Then the number is

(A) 72
(A) 72
(B) 60
(B) 60
(C) 80
(C) 80
(D) 48
(D) 48
Answer: (B) 60
Answer: (B) 60
60
60

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@875

2024-03-03

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Q5. 5 : 27 :: 9 : ________
Q5. 5 : 27 :: 9 : ________

Fill the blank.

Fill the blank.
(A) 83
(A) 83
(B) 81
(B) 81
(C) 36
(C) 36
(D) 18
(D) 18
Answer: (A) 83
Answer: (A) 83
5 : (52 + 2) = 5 : 27 Hence 9 : (92 + 2) = 9 : 83
5 : (52 + 2) = 5 : 27 Hence 9 : (92 + 2) = 9 : 83

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@1134

2024-05-15

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Q6. A number is as much greater than 31 as is less 55. Then the number is
Q6. A number is as much greater than 31 as is less 55. Then the number is

(A) 39
(A) 39
(B) 32
(B) 32
(C) 43
(C) 43
(D) 47
(D) 47
Answer: (C) 43
Answer: (C) 43
43
43

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@874

2024-03-03

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Q7. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is
Q7. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is

(A) 25
(A) 25
(B) 41
(B) 41
(C) 13
(C) 13
(D) 11
(D) 11
Answer: (D) 11
Answer: (D) 11
11
11

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@1088

2024-05-01

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Q8. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :
Q8. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :

(A) 2 : 3
(A) 2 : 3
(B) 3 : 5
(B) 3 : 5
(C) 3 : 2
(C) 3 : 2
(D) 2 : 5
(D) 2 : 5
Answer: (A) 2 : 3
Answer: (A) 2 : 3
45100*X = 30100 * Y = XY = 30*100100*45 = XY = 23 = X:Y = 2:3
45100*X = 30100 * Y = XY = 30*100100*45 = XY = 23 = X:Y = 2:3

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@1118

2024-05-09

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Q9. A 100 metre long train moving in a uniform speed of 20 m/sec crosses a bridge of length 1 km. The time taken by the train to cross the bridge is
Q9. A 100 metre long train moving in a uniform speed of 20 m/sec crosses a bridge of length 1 km. The time taken by the train to cross the bridge is

(A) 45 seconds
(A) 45 seconds
(B) 50 seconds
(B) 50 seconds
(C) 55 seconds
(C) 55 seconds
(D) 60 seconds
(D) 60 seconds
Answer: (C) 55 seconds
Answer: (C) 55 seconds
(1000+100)m / (20m/s) = 55 seconds
(1000+100)m / (20m/s) = 55 seconds

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@1031

2024-04-20

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Q10. Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is
Q10. Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is

(A) 2 : 5
(A) 2 : 5
(B) 3 : 5
(B) 3 : 5
(C) 4 : 5
(C) 4 : 5
(D) 7 : 5
(D) 7 : 5
Answer: (C) 4 : 5
Answer: (C) 4 : 5
4 : 5
4 : 5

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@1018

2024-04-13

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Q11. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is
Q11. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is

(A) 8
(A) 8
(B) 12
(B) 12
(C) 20
(C) 20
(D) 36
(D) 36
Answer: (C) 20
Answer: (C) 20
=> 2x * 3x = 96 => 6x2 = 96 => x2 = 96/6 => x2 = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20
=> 2x * 3x = 96 => 6x2 = 96 => x2 = 96/6 => x2 = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20

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@1110

2024-05-09

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Q12. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is
Q12. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is

(A) 25
(A) 25
(B) 45
(B) 45
(C) 32
(C) 32
(D) 27
(D) 27
Answer: (D) 27
Answer: (D) 27
27
27

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@900

2024-03-03

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Q13. The value of 0.04 + 1.44 + 1.69 + 0.0009 is :
Q13. The value of 0.04 + 1.44 + 1.69 + 0.0009 is :

(A) 1.73
(A) 1.73
(B) 2.03
(B) 2.03
(C) 2.73
(C) 2.73
(D) 1.03
(D) 1.03
Answer: (C) 2.73
Answer: (C) 2.73
= 0.04 + 1.44 + 1.69 + 0.0009 = 0.02*0.02 + 1.2*1.2 + 1.3*1.3 + 0.03*0.03 = 0.2 + 1.2 + 1.3 + 0.03 = 2.73
= 0.04 + 1.44 + 1.69 + 0.0009 = 0.02*0.02 + 1.2*1.2 + 1.3*1.3 + 0.03*0.03 = 0.2 + 1.2 + 1.3 + 0.03 = 2.73

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@1117

2024-05-09

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Q14. The price of an article is first decreased by 40% and then increased by 20%. The net change in the price will be :
Q14. The price of an article is first decreased by 40% and then increased by 20%. The net change in the price will be :

(A) 20%
(A) 20%
(B) 40%
(B) 40%
(C) 24%
(C) 24%
(D) 28%
(D) 28%
Answer: (D) 28%
Answer: (D) 28%
Net change (-40 + 20 + (-40)*20100)% = (-20 + -800100)% = (-20 - 8)% = -28% = 28%
Net change (-40 + 20 + (-40)*20100)% = (-20 + -800100)% = (-20 - 8)% = -28% = 28%

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@1123

2024-05-15

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Q15. Find the median of the data set.
Q15. Find the median of the data set.

1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12

1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12
(A) 8
(A) 8
(B) 7
(B) 7
(C) 5
(C) 5
(D) 4
(D) 4
Answer: (C) 5
Answer: (C) 5
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12 = 1, 1, 1, 2, 4, 5, 5, 7, 8, 12, 12, 16, 17 Total numbers of values N = 13 Hence median value = (N + 1)/2 = (13 + 1)/2 = 7th 7th Number = 5
1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12 = 1, 1, 1, 2, 4, 5, 5, 7, 8, 12, 12, 16, 17 Total numbers of values N = 13 Hence median value = (N + 1)/2 = (13 + 1)/2 = 7th 7th Number = 5

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@1120

2024-05-09

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Q16. If the price of sugar increases by 20%, by what percentage should a household reduce its consumption of sugar so that the budget remains the same?
Q16. If the price of sugar increases by 20%, by what percentage should a household reduce its consumption of sugar so that the budget remains the same?

(A) 1323%
(A) 1323%
(B) 1423%
(B) 1423%
(C) 1523%
(C) 1523%
(D) 1623%
(D) 1623%
Answer: (D) 1623%
Answer: (D) 1623%
1623%
1623%

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@1029

2024-04-20

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Q17. The sum of two numbers is 15 and the sum of their squares is 113. The numbers are
Q17. The sum of two numbers is 15 and the sum of their squares is 113. The numbers are

(A) 4 and 10
(A) 4 and 10
(B) 6 and 9
(B) 6 and 9
(C) 5 and 10
(C) 5 and 10
(D) 7 and 8
(D) 7 and 8
Answer: (D) 7 and 8
Answer: (D) 7 and 8
7 and 8
7 and 8

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@674

2024-03-03

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Q18. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Q18. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :

(A) 60 years
(A) 60 years
(B) 51 years
(B) 51 years
(C) 48 years
(C) 48 years
(D) 45 years
(D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.

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@1127

2024-05-15

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Q19. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?
Q19. Two trains of 200 m and 100 m long are running parallel at the rate of 20 m/sec. and 22 m/sec. respectively. How much time will they take to cross each other, if the trains are running along the same direction?

(A) 120 sec
(A) 120 sec
(B) 100 sec
(B) 100 sec
(C) 60 sec
(C) 60 sec
(D) 50 sec
(D) 50 sec
Answer: (D) 50 sec
Answer: (D) 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec
The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec

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@1132

2024-05-15

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Q20. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
Q20. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is

(A) 13
(A) 13
(B) 11
(B) 11
(C) 16
(C) 16
(D) 9
(D) 9
Answer: (A) 13
Answer: (A) 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13

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24462 views

@1109

2024-05-09

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