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In this category calculation is involved.

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Q1. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
Q1. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was

(A) 5
(A) 5

(B) 7
(B) 7

(D) 14
(D) 14

Answer: (B) 7
Answer: (B) 7

7 => x * 2x = 98 => x² =

\frac{98}{2}

=> x² = 49 => x = 7

7 => x * 2x = 98 => x² =

\frac{98}{2}

=> x² = 49 => x = 7

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@1112

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2024-05-09

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Q2. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?
Q2. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?

(A) 60
(A) 60

(B) 120
(B) 120

(D) 240
(D) 240

Answer: (B) 120
Answer: (B) 120

120

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@1025

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2024-04-19

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Q3. Find the value of $\sqrt{\frac{225}{729}} - \sqrt{\frac{25}{144}} - \sqrt{\frac{16}{81}}$
Q3. Find the value of $\sqrt{\frac{225}{729}} - \sqrt{\frac{25}{144}} - \sqrt{\frac{16}{81}}$

(A)

\frac{- 5}{9}

(A)

\frac{- 5}{9}

(B)

\frac{- 7}{12}

(B)

\frac{- 7}{12}

(C)

\frac{- 20}{27}

(C)

\frac{- 20}{27}

(D)

\frac{- 11}{36}

(D)

\frac{- 11}{36}

Answer: (D)

\frac{- 11}{36}

Answer: (D)

\frac{- 11}{36}

\sqrt{\frac{225}{729}} - \sqrt{\frac{25}{144}} - \sqrt{\frac{16}{81}}

\sqrt{\frac{15 * 15}{27 * 27}} - \sqrt{\frac{5 * 5}{12 * 12}} - \sqrt{\frac{4 * 4}{9 * 9}}

\frac{15}{27} - \frac{5}{12} - \frac{4}{9}

\frac{60 - 45 - 48}{108}

\frac{- 33}{108}

\frac{- 11}{36}

\sqrt{\frac{225}{729}} - \sqrt{\frac{25}{144}} - \sqrt{\frac{16}{81}}

\sqrt{\frac{15 * 15}{27 * 27}} - \sqrt{\frac{5 * 5}{12 * 12}} - \sqrt{\frac{4 * 4}{9 * 9}}

\frac{15}{27} - \frac{5}{12} - \frac{4}{9}

\frac{60 - 45 - 48}{108}

\frac{- 33}{108}

\frac{- 11}{36}

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@1121

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2024-05-09

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Q4. In a school with 10 teachers, one retires and immediately a new teacher of age 25 years joins. As a result, the average age of the teacher reduces by 3. The age of the retired teacher is
Q4. In a school with 10 teachers, one retires and immediately a new teacher of age 25 years joins. As a result, the average age of the teacher reduces by 3. The age of the retired teacher is

(A) 55 years
(A) 55 years

(B) 65 years
(B) 65 years

(D) 60 years
(D) 60 years

Answer: (A) 55 years
Answer: (A) 55 years

25 years + (3*10) years = 55 years

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@1024

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2024-04-19

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Q5. The LCM of two numbers is 40 and their HCF is 4. If the difference between the two numbers is 12, then the sum of the numbers is
Q5. The LCM of two numbers is 40 and their HCF is 4. If the difference between the two numbers is 12, then the sum of the numbers is

(A) 20
(A) 20

(B) 24
(B) 24

(D) 32
(D) 32

Answer: (C) 28
Answer: (C) 28

X * (X-12) = 40 * 4 X = 20 X + (X-12) = 20 + 20 - 12 = 28

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@1087

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2024-05-01

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Q6. The conversion of $0.0 \bar{37}$ in the fractional form is
Q6. The conversion of $0.0 \bar{37}$ in the fractional form is

(A)

\frac{37}{100}

(A)

\frac{37}{100}

(B)

\frac{37}{999}

(B)

\frac{37}{999}

(C)

\frac{37}{990}

(C)

\frac{37}{990}

(D)

\frac{37}{1000}

(D)

\frac{37}{1000}

Answer: (C)

\frac{37}{990}

Answer: (C)

\frac{37}{990}

\frac{37}{990}

\frac{37}{990}

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@1032

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2024-04-20

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Q7. The sum of first 6 prime numbers is
Q7. The sum of first 6 prime numbers is

(A) 40
(A) 40

(B) 43
(B) 43

(D) 42
(D) 42

Answer: (C) 41
Answer: (C) 41

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@661

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2024-03-03

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Q8. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is
Q8. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is

(A) 25
(A) 25

(B) 41
(B) 41

(D) 11
(D) 11

Answer: (D) 11
Answer: (D) 11

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@1088

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2024-05-01

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Q9. A 100 metre long train moving in a uniform speed of 20 m/sec crosses a bridge of length 1 km. The time taken by the train to cross the bridge is
Q9. A 100 metre long train moving in a uniform speed of 20 m/sec crosses a bridge of length 1 km. The time taken by the train to cross the bridge is

(A) 45 seconds
(A) 45 seconds

(B) 50 seconds
(B) 50 seconds

(D) 60 seconds
(D) 60 seconds

Answer: (C) 55 seconds
Answer: (C) 55 seconds

(1000+100)m / (20m/s) = 55 seconds

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@1031

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2024-04-20

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Q10. A number is as much greater than 31 as is less 55. Then the number is
Q10. A number is as much greater than 31 as is less 55. Then the number is

(A) 39
(A) 39

(B) 32
(B) 32

(D) 47
(D) 47

Answer: (C) 43
Answer: (C) 43

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@874

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2024-03-03

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Q11. Three fourth of a number is more than two third of the number by 5. Then the number is
Q11. Three fourth of a number is more than two third of the number by 5. Then the number is

(A) 72
(A) 72

(B) 60
(B) 60

(D) 48
(D) 48

Answer: (B) 60
Answer: (B) 60

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@875

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2024-03-03

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Q12. The least number by which 2450 must be multiplied to make it a perfect square, is
Q12. The least number by which 2450 must be multiplied to make it a perfect square, is

(A) 2
(A) 2

(B) 3
(B) 3

(D) 5
(D) 5

Answer: (A) 2
Answer: (A) 2

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@1028

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2024-04-19

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Q13. The 8th term of the sequence 2, 6, 18, 54, ...... is
Q13. The 8th term of the sequence 2, 6, 18, 54, ...... is

(A) 4370
(A) 4370

(B) 4374
(B) 4374

(D) 7434
(D) 7434

Answer: (B) 4374
Answer: (B) 4374

4374

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@1017

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2024-04-13

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Q14. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :
Q14. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :

(A) 5,420
(A) 5,420

(B) 5,580
(B) 5,580

(D) 5,780
(D) 5,780

Answer: (B) 5,580
Answer: (B) 5,580

The formula for the sum of the first n terms of an arithmetic progression is

S_{n} = \frac{n}{2} (a + a n)

\frac{30}{2} (12 + 12 * 30)

= 15*(12+360) = 15 * 372 = 5580

The formula for the sum of the first n terms of an arithmetic progression is

S_{n} = \frac{n}{2} (a + a n)

\frac{30}{2} (12 + 12 * 30)

= 15*(12+360) = 15 * 372 = 5580

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@1119

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2024-05-09

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Q15. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will be
Q15. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will be

(A) q
(A) q

(B) r
(B) r

(D) pqr
(D) pqr

Answer: (B) r
Answer: (B) r

LCM will be r. px= q and qy = r, hence r = pxy.

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@1030

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2024-04-20

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Q16. The remainder when –76 is divided by 3, is
Q16. The remainder when –76 is divided by 3, is

(A) -1
(A) -1

(B) 1
(B) 1

(D) -2
(D) -2

Answer: (C) 2
Answer: (C) 2

2 Because, Reminder must be positive and it should be less then the divisor

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@1033

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2024-04-20

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Q17. 4/5 of a number is 64. Then half of the number is
Q17. 4/5 of a number is 64. Then half of the number is

(A) 16
(A) 16

(B) 80
(B) 80

(D) 40
(D) 40

Answer: (D) 40
Answer: (D) 40

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@876

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2024-03-03

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Q18. A hostel has 120 students and food supplies are for 45 days. If 30 more students joined the hostel, then how many days the hostel will run with the existing food?
Q18. A hostel has 120 students and food supplies are for 45 days. If 30 more students joined the hostel, then how many days the hostel will run with the existing food?

(A) 40 days
(A) 40 days

(B) 38 days
(B) 38 days

(D) 32 days
(D) 32 days

Answer: (C) 36 days
Answer: (C) 36 days

36 days

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@1021

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2024-04-19

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Q19. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Q19. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :

(A) 60 years
(A) 60 years

(B) 51 years
(B) 51 years

(D) 45 years
(D) 45 years

Answer: (D) 45 years
Answer: (D) 45 years

The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.

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@1127

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2024-05-15

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Q20. Find the median of the data set.
Q20. Find the median of the data set.

1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12

1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12

(A) 8
(A) 8

(B) 7
(B) 7

(D) 4
(D) 4

Answer: (C) 5
Answer: (C) 5

1, 2, 4, 1, 5, 12, 7, 8, 5, 1, 16, 17, 12 = 1, 1, 1, 2, 4, 5, 5, 7, 8, 12, 12, 16, 17 Total numbers of values N = 13 Hence median value = (N + 1)/2 = (13 + 1)/2 = 7th 7th Number = 5

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2024-05-09

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This category is for the informations where no calculation is involved.

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Calculation Involved (Calculation is Required) | MCQ Quizzes | Category (R/R/M)

Q2. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?Q2. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?

Q3. Find the value of 225729-25144-1681Q3. Find the value of 225729-25144-1681

Q5. The LCM of two numbers is 40 and their HCF is 4. If the difference between the two numbers is 12, then the sum of the numbers isQ5. The LCM of two numbers is 40 and their HCF is 4. If the difference between the two numbers is 12, then the sum of the numbers is

Q6. The conversion of 0.037− in the fractional form isQ6. The conversion of 0.037− in the fractional form is

Q7. The sum of first 6 prime numbers isQ7. The sum of first 6 prime numbers is

Q8. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, isQ8. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is

Q9. A 100 metre long train moving in a uniform speed of 20 m/sec crosses a bridge of length 1 km. The time taken by the train to cross the bridge isQ9. A 100 metre long train moving in a uniform speed of 20 m/sec crosses a bridge of length 1 km. The time taken by the train to cross the bridge is

Q10. A number is as much greater than 31 as is less 55. Then the number isQ10. A number is as much greater than 31 as is less 55. Then the number is

Q11. Three fourth of a number is more than two third of the number by 5. Then the number isQ11. Three fourth of a number is more than two third of the number by 5. Then the number is

Q12. The least number by which 2450 must be multiplied to make it a perfect square, isQ12. The least number by which 2450 must be multiplied to make it a perfect square, is

Q13. The 8th term of the sequence 2, 6, 18, 54, ...... isQ13. The 8th term of the sequence 2, 6, 18, 54, ...... is

Q15. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will beQ15. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will be

Q16. The remainder when –76 is divided by 3, isQ16. The remainder when –76 is divided by 3, is

Q17. 4/5 of a number is 64. Then half of the number isQ17. 4/5 of a number is 64. Then half of the number is

Q20. Find the median of the data set.Q20. Find the median of the data set.

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Related Categories

1. Calculation Not Involved (Calculation is Not Required)

2. Calculation Involved (Calculation is Required)

Q2. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?
Q2. The ratio of the number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1?

Q3. Find the value of $\sqrt{\frac{225}{729}} - \sqrt{\frac{25}{144}} - \sqrt{\frac{16}{81}}$
Q3. Find the value of $\sqrt{\frac{225}{729}} - \sqrt{\frac{25}{144}} - \sqrt{\frac{16}{81}}$

Q5. The LCM of two numbers is 40 and their HCF is 4. If the difference between the two numbers is 12, then the sum of the numbers is
Q5. The LCM of two numbers is 40 and their HCF is 4. If the difference between the two numbers is 12, then the sum of the numbers is

Q6. The conversion of $0.0 \bar{37}$ in the fractional form is
Q6. The conversion of $0.0 \bar{37}$ in the fractional form is

Q7. The sum of first 6 prime numbers is
Q7. The sum of first 6 prime numbers is

Q8. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is
Q8. The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is

Q9. A 100 metre long train moving in a uniform speed of 20 m/sec crosses a bridge of length 1 km. The time taken by the train to cross the bridge is
Q9. A 100 metre long train moving in a uniform speed of 20 m/sec crosses a bridge of length 1 km. The time taken by the train to cross the bridge is

Q10. A number is as much greater than 31 as is less 55. Then the number is
Q10. A number is as much greater than 31 as is less 55. Then the number is

Q11. Three fourth of a number is more than two third of the number by 5. Then the number is
Q11. Three fourth of a number is more than two third of the number by 5. Then the number is

Q12. The least number by which 2450 must be multiplied to make it a perfect square, is
Q12. The least number by which 2450 must be multiplied to make it a perfect square, is

Q13. The 8th term of the sequence 2, 6, 18, 54, ...... is
Q13. The 8th term of the sequence 2, 6, 18, 54, ...... is

Q15. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will be
Q15. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will be

Q16. The remainder when –76 is divided by 3, is
Q16. The remainder when –76 is divided by 3, is

Q17. 4/5 of a number is 64. Then half of the number is
Q17. 4/5 of a number is 64. Then half of the number is

Q20. Find the median of the data set.
Q20. Find the median of the data set.