The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is [#1706]

X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23

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X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23

720

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720

47

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47

=> 2x * 3x = 96 => 6x² = 96 => x² = 96/6 => x² = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20

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=> 2x * 3x = 96 => 6x² = 96 => x² = 96/6 => x² = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20

12 ---- x 60 = 48 KMPH 15

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12 ---- x 60 = 48 KMPH 15

$\frac{3}{2}$ >$\frac{3}{2}\times \frac{4}{9}$ = $\frac{12}{18}$ = $\frac{2}{3}$

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$\frac{3}{2}$ >$\frac{3}{2}\times \frac{4}{9}$ = $\frac{12}{18}$ = $\frac{2}{3}$

4374

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4374

The result of multiplying a number by itself is called a square, such as 4 × 4 = 16, which is denoted as 4² (four squared).

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The result of multiplying a number by itself is called a square, such as 4 × 4 = 16, which is denoted as 4² (four squared).

The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.

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The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.

100 - 98 = 2

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100 - 98 = 2

100 * 100% + 200 * 200% = $100\times \frac{100}{100} + 200 \times \frac{200}{100}$ = $\frac{10000}{100} + \frac{40000}{100}$ = 100 + 400 = 500

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100 * 100% + 200 * 200% = $100\times \frac{100}{100} + 200 \times \frac{200}{100}$ = $\frac{10000}{100} + \frac{40000}{100}$ = 100 + 400 = 500