The smallest among $\sqrt{\frac{1}{2}}, \sqrt{\frac{1}{3}}, \sqrt{\frac{1}{4}} and \sqrt{\frac{2}{3}}$ is [#1691]

Net change (-40 + 20 + $\frac{(-40)*20}{100}$)% = (-20 + $\frac{-800}{100}$)% = (-20 - 8)% = -28% = 28%

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Net change (-40 + 20 + $\frac{(-40)*20}{100}$)% = (-20 + $\frac{-800}{100}$)% = (-20 - 8)% = -28% = 28%

6*4 = 24 8*3 = 24 12*2 = 24

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6*4 = 24 8*3 = 24 12*2 = 24

2⁵ = 2*2*2*2*2 = 32

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2⁵ = 2*2*2*2*2 = 32

A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

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A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

In ascending order = -2, -1, 1, 2, 3, 5, 6 median = $\frac{7+1}{2}$th term = 4th term = 2

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In ascending order = -2, -1, 1, 2, 3, 5, 6 median = $\frac{7+1}{2}$th term = 4th term = 2

=> 2x * 3x = 96 => 6x² = 96 => x² = 96/6 => x² = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20

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=> 2x * 3x = 96 => 6x² = 96 => x² = 96/6 => x² = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20

36

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36

4

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4

Area = πr² π1² : π3² = π1 : π9 = 1:9

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Area = πr² π1² : π3² = π1 : π9 = 1:9