Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest? [#1669]

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Q1. Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest?
Q1. Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest?

I. 376 II. 629 III. 921 IV. 397

I. 376 II. 629 III. 921 IV. 397

(A) III
(A) III

(B) II
(B) II

(D) IV
(D) IV

Answer: (A) III
Answer: (A) III

376 -> 367 629 -> 269 921 -> 129 * 397 -> 379

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Q1. The difference between the smallest 3-digit even natural number and the largest 2-digit even natural number is
Q1. The difference between the smallest 3-digit even natural number and the largest 2-digit even natural number is

(A) 1
(A) 1

(B) 2
(B) 2

(D) 4
(D) 4

Answer: (B) 2
Answer: (B) 2

100 - 98 = 2

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Q2. The smallest positive integer that is simultaneously divisible by 6, 8 and 12 is
Q2. The smallest positive integer that is simultaneously divisible by 6, 8 and 12 is

(A) 24
(A) 24

(B) 18
(B) 18

(D) 36
(D) 36

Answer: (A) 24
Answer: (A) 24

6*4 = 24 8*3 = 24 12*2 = 24

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Q3. The value of $\sqrt[3]{8^{2}}$ is
Q3. The value of $\sqrt[3]{8^{2}}$ is

(A) 1
(A) 1

(B) 3
(B) 3

(D) 4
(D) 4

Answer: (D) 4
Answer: (D) 4

\sqrt[3]{8^{2}}

\sqrt[3]{64}

\sqrt[3]{4^{3}}

= 4

\sqrt[3]{8^{2}}

\sqrt[3]{64}

\sqrt[3]{4^{3}}

= 4

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Q4. Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest?
Q4. Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest?

I. 376 II. 629 III. 921 IV. 397

I. 376 II. 629 III. 921 IV. 397

(A) III
(A) III

(B) II
(B) II

(D) IV
(D) IV

Answer: (A) III
Answer: (A) III

376 -> 367 629 -> 269 921 -> 129 * 397 -> 379

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Q5. 100% of 100 when added to 200% of 200 would result
Q5. 100% of 100 when added to 200% of 200 would result

(A) 300
(A) 300

(B) 400
(B) 400

(D) 600
(D) 600

Answer: (C) 500
Answer: (C) 500

100 * 100% + 200 * 200% =

100 \times \frac{100}{100} + 200 \times \frac{200}{100}

\frac{10000}{100} + \frac{40000}{100}

= 100 + 400 = 500

100 * 100% + 200 * 200% =

100 \times \frac{100}{100} + 200 \times \frac{200}{100}

\frac{10000}{100} + \frac{40000}{100}

= 100 + 400 = 500

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Q6. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is
Q6. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is

(A) 1
(A) 1

(B) -1
(B) -1

(D) 3
(D) 3

Answer: (C) 2
Answer: (C) 2

In ascending order = -2, -1, 1, 2, 3, 5, 6 median =

\frac{7 + 1}{2}

th term = 4th term = 2

In ascending order = -2, -1, 1, 2, 3, 5, 6 median =

\frac{7 + 1}{2}

th term = 4th term = 2

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Q7. The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is
Q7. The sum of 5 consecutive odd numbers is found to be 95. The largest of the numbers is

(A) 17
(A) 17

(B) 21
(B) 21

(D) 19
(D) 19

Answer: (C) 23
Answer: (C) 23

X + (X+2) + (X+4) + (X+6) + (X+8) = 95 => 5X + 20 = 95 => 5X = 95-20 => 5X = 75 => X = 15 Hence (X+8) = 15+8 = 23

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Q8. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to
Q8. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to

(A) 2
(A) 2

(B) 3
(B) 3

(D) 5
(D) 5

Answer: (A) 2
Answer: (A) 2

\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}

Hence, X:Y:Z = 3:4:7

\frac{X + Y + Z}{Z}

\frac{3 + 4 + 7}{7}

\frac{14}{7}

= 2

\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}

Hence, X:Y:Z = 3:4:7

\frac{X + Y + Z}{Z}

\frac{3 + 4 + 7}{7}

\frac{14}{7}

= 2

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Q9. If A : B = 3, then 144A : 36B is
Q9. If A : B = 3, then 144A : 36B is

(A) 4
(A) 4

(B) 12
(B) 12

(D) 16
(D) 16

Answer: (B) 12
Answer: (B) 12

A : B = 3 =>

\frac{A}{B}

= 3

\frac{144 A}{36 B}

\frac{144}{36} \times \frac{A}{B}

\frac{144}{36}

x 3 = 4 x 3 = 12

A : B = 3 =>

\frac{A}{B}

= 3

\frac{144 A}{36 B}

\frac{144}{36} \times \frac{A}{B}

\frac{144}{36}

x 3 = 4 x 3 = 12

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Q10. Find the least number by which 1250 must be multiplied to make it a perfect square.
Q10. Find the least number by which 1250 must be multiplied to make it a perfect square.

(A) 4
(A) 4

(B) 3
(B) 3

(D) 2
(D) 2

Answer: (D) 2
Answer: (D) 2

1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500

\sqrt{2500}

= 2*5*5 = 50

1250 = 2*5*5*5*5 1250*2 = 2*2*5*5*5*5 = 2500

\sqrt{2500}

= 2*5*5 = 50

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Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest? [#1669]

Q1. Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest?Q1. Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest?

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