‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is : [#1122]
Q1. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is : Q1. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
(A) 1.5 km (A) 1.5 km
(B) 1.75 km (B) 1.75 km
(C) 1.2 km (C) 1.2 km
(D) 1.25 km (D) 1.25 km
Answer: (C) 1.2 km Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 kmA starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
Q1. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was Q1. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
(A) 5 (A) 5
(B) 7 (B) 7
(C) 10 (C) 10
(D) 14 (D) 14
Answer: (B) 7 Answer: (B) 7
7
=> x * 2x = 98
=> x2 =
=> x2 = 49
=> x = 77
=> x * 2x = 98
=> x2 =
=> x2 = 49
=> x = 7
Q2. If 20% of a is b, then b% of 20 is the same as : Q2. If 20% of a is b, then b% of 20 is the same as :
(A) 4% of a (A) 4% of a
(B) 8% of a (B) 8% of a
(C) 6% of a (C) 6% of a
(D) 10% of a (D) 10% of a
Answer: (A) 4% of a Answer: (A) 4% of a
20% of a is b
Hence b = 20% of a = 20a/100
b% of 20
= 20% of b
= (20/100) * 20a/100
= (20*20*a)/(100*100)
= 4a/100
= (4/100) * a
= 4% of a20% of a is b
Hence b = 20% of a = 20a/100
b% of 20
= 20% of b
= (20/100) * 20a/100
= (20*20*a)/(100*100)
= 4a/100
= (4/100) * a
= 4% of a
Q3. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now. Q3. If the average age of A, B and C is 22 years and the average age of B and C is 25 years, then find the age of A after 9 years from now.
(A) 25 years (A) 25 years
(B) 35 years (B) 35 years
(C) 50 years (C) 50 years
(D) 45 years (D) 45 years
Answer: (A) 25 years Answer: (A) 25 years
25 years
=> A+B+C = 22*3
=> A+(B+C) = 66
=> A+(25*2) = 66
=> A = 66-50
=> A = 16
After 9 years A = 16+9 = 25 years25 years
=> A+B+C = 22*3
=> A+(B+C) = 66
=> A+(25*2) = 66
=> A = 66-50
=> A = 16
After 9 years A = 16+9 = 25 years
Q4. The smallest positive integer that is simultaneously divisible by 6, 8 and 12 is Q4. The smallest positive integer that is simultaneously divisible by 6, 8 and 12 is
Q5. At what percentage of simple interest does an amount of money double in 12 years? Q5. At what percentage of simple interest does an amount of money double in 12 years?
(A) (A)
(B) (B)
(C) (C)
(D) (D)
Answer: (C) Answer: (C)
P * * 12
= P * * 12
= P *
= P * 100%P * * 12
= P * * 12
= P *
= P * 100%
Q6. At what speed should a car travel on a highway to reach a destination 12 km away in 15 minutes? Q6. At what speed should a car travel on a highway to reach a destination 12 km away in 15 minutes?
(A) 64 kmph (A) 64 kmph
(B) 84 kmph (B) 84 kmph
(C) 48 kmph (C) 48 kmph
(D) 36 kmph (D) 36 kmph
Answer: (C) 48 kmph Answer: (C) 48 kmph
12
---- x 60 = 48 KMPH
1512
---- x 60 = 48 KMPH
15
Q7. The count of prime numbers between 80 and 100 is Q7. The count of prime numbers between 80 and 100 is
(A) 2 (A) 2
(B) 5 (B) 5
(C) 3 (C) 3
(D) 4 (D) 4
Answer: (C) 3 Answer: (C) 3
Prime numbers are numbers that are only divisible by 1 and themselves. Between 80 and 100, the prime numbers are 83, 89, and 97. Therefore, there are 3 prime numbers in this range.Prime numbers are numbers that are only divisible by 1 and themselves. Between 80 and 100, the prime numbers are 83, 89, and 97. Therefore, there are 3 prime numbers in this range.
Q8. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be Q8. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be
Q10. A wheel can cover a distance of 22 km in 1000 rounds. The radius of the wheel is Q10. A wheel can cover a distance of 22 km in 1000 rounds. The radius of the wheel is
