‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is : [#1122]
Q1. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is : Q1. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
(A) 1.5 km (A) 1.5 km
(B) 1.75 km (B) 1.75 km
(C) 1.2 km (C) 1.2 km
(D) 1.25 km (D) 1.25 km
Answer: (C) 1.2 km Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 kmA starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
Q1. At what speed should a car travel on a highway to reach a destination 12 km away in 15 minutes? Q1. At what speed should a car travel on a highway to reach a destination 12 km away in 15 minutes?
(A) 64 kmph (A) 64 kmph
(B) 84 kmph (B) 84 kmph
(C) 48 kmph (C) 48 kmph
(D) 36 kmph (D) 36 kmph
Answer: (C) 48 kmph Answer: (C) 48 kmph
12
---- x 60 = 48 KMPH
1512
---- x 60 = 48 KMPH
15
Q2. What is the formula to calculate the area of a circle? Q2. What is the formula to calculate the area of a circle?
(A) A = πr2 (A) A = πr2
(B) A = 2πr (B) A = 2πr
(C) A = πd (C) A = πd
(D) A = 1/2πr2 (D) A = 1/2πr2
Answer: (A) A = πr2 Answer: (A) A = πr2
The formula to calculate the area of a circle is A = πr2, where A is the area and r is the radius of the circle.The formula to calculate the area of a circle is A = πr2, where A is the area and r is the radius of the circle.
Q3. Select the number pair in which the two numbers are related in the same way as 35 : 6. Q3. Select the number pair in which the two numbers are related in the same way as 35 : 6.
Q4. What is the term for a line that divides a shape into two equal parts? Q4. What is the term for a line that divides a shape into two equal parts?
(A) Axis (A) Axis
(B) Median (B) Median
(C) Vertex (C) Vertex
(D) Bisector (D) Bisector
Answer: (D) Bisector Answer: (D) Bisector
A bisector is a line that divides a shape into two equal parts, like a line that cuts a triangle into two equal areas or a line that divides a circle into two equal parts (semi-circles).A bisector is a line that divides a shape into two equal parts, like a line that cuts a triangle into two equal areas or a line that divides a circle into two equal parts (semi-circles).
Q6. A person moves along a path such that he is always away from a given point by 7 m. After moving for some time, he again reaches his starting point. The approximate distance the person moved during the time is Q6. A person moves along a path such that he is always away from a given point by 7 m. After moving for some time, he again reaches his starting point. The approximate distance the person moved during the time is
Q8. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is Q8. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is
Q10. If the sum of five consecutive numbers is 190, then the lowest number amongst them is Q10. If the sum of five consecutive numbers is 190, then the lowest number amongst them is
