‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is : [#1122]
Q1. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is : Q1. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
(A) 1.5 km (A) 1.5 km
(B) 1.75 km (B) 1.75 km
(C) 1.2 km (C) 1.2 km
(D) 1.25 km (D) 1.25 km
Answer: (C) 1.2 km Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 kmA starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
Q1. A wheel can cover a distance of 22 km in 1000 rounds. The radius of the wheel is Q1. A wheel can cover a distance of 22 km in 1000 rounds. The radius of the wheel is
Q3. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is Q3. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is
Q5. What is the value of x in the equation 2x + 5 = 11? Q5. What is the value of x in the equation 2x + 5 = 11?
(A) 2 (A) 2
(B) 3 (B) 3
(C) 4 (C) 4
(D) 5 (D) 5
Answer: (B) 3 Answer: (B) 3
To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.To solve for x, subtract 5 from both sides of the equation, resulting in 2x = 6. Then, divide both sides by 2, giving x = 3.
Q6. Shyam stored Rs 35 in the form of 1 rupee coin and 50 paise coins in the ratio 2 : 3. The number of 50 paise coins are Q6. Shyam stored Rs 35 in the form of 1 rupee coin and 50 paise coins in the ratio 2 : 3. The number of 50 paise coins are
Q7. At what percentage of simple interest does an amount of money double in 12 years? Q7. At what percentage of simple interest does an amount of money double in 12 years?
(A) (A)
(B) (B)
(C) (C)
(D) (D)
Answer: (C) Answer: (C)
P * * 12
= P * * 12
= P *
= P * 100%P * * 12
= P * * 12
= P *
= P * 100%
Q10. What is the term for the distance around a shape? Q10. What is the term for the distance around a shape?
(A) Area (A) Area
(B) Perimeter (B) Perimeter
(C) Volume (C) Volume
(D) Surface area (D) Surface area
Answer: (B) Perimeter Answer: (B) Perimeter
The perimeter is the distance around a shape, like the distance around a rectangle, triangle, or circle.The perimeter is the distance around a shape, like the distance around a rectangle, triangle, or circle.
