The remainder when –76 is divided by 3, is [#1033]

2 Because, Reminder must be positive and it should be less then the divisor

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2 Because, Reminder must be positive and it should be less then the divisor

An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.

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An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.

125

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125

The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec

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The difference of speed = 22m/s - 20m/s = 2m/s As the train with speed 22m/s will cross the other, hence this train have to go the smallest length of the trains distance ahead of the other to cross completely. Hence This train will be ahead of 100m with a speed of 2m/s. Hence The time to cross each other will take = 100m / (2m/s) = 50 sec

1+3+5+7+9+11+13 = 49

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1+3+5+7+9+11+13 = 49

1

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1

48

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48

(360°/15) * (7-1) = 144°

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(360°/15) * (7-1) = 144°

Integers

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Integers

$\sqrt{\frac{225}{729}}-\sqrt{\frac{25}{144}}-\sqrt{\frac{16}{81}}$ = $\sqrt{\frac{15*15}{27*27}}-\sqrt{\frac{5*5}{12*12}}-\sqrt{\frac{4*4}{9*9}}$ = $\frac{15}{27}-\frac{5}{12}-\frac{4}{9}$ = $\frac{60-45-48}{108}$ = $\frac{-33}{108}$ = $\frac{-11}{36}$

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$\sqrt{\frac{225}{729}}-\sqrt{\frac{25}{144}}-\sqrt{\frac{16}{81}}$ = $\sqrt{\frac{15*15}{27*27}}-\sqrt{\frac{5*5}{12*12}}-\sqrt{\frac{4*4}{9*9}}$ = $\frac{15}{27}-\frac{5}{12}-\frac{4}{9}$ = $\frac{60-45-48}{108}$ = $\frac{-33}{108}$ = $\frac{-11}{36}$

In ascending order = -2, -1, 1, 2, 3, 5, 6 median = $\frac{7+1}{2}$th term = 4th term = 2

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In ascending order = -2, -1, 1, 2, 3, 5, 6 median = $\frac{7+1}{2}$th term = 4th term = 2