The 8th term of the sequence 2, 6, 18, 54, ...... is [#1017]
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Q1. The 8th term of the sequence 2, 6, 18, 54, ...... is
Q1. The 8th term of the sequence 2, 6, 18, 54, ...... is
(A) 4370
(A) 4370
(A) 4370
(B) 4374
(B) 4374
(B) 4374
(C) 7443
(C) 7443
(C) 7443
(D) 7434
(D) 7434
(D) 7434
Answer: (B) 4374
Answer: (B) 4374
Answer: (B) 4374
4374
4374
4374
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Related MCQ Quizzes
Q1. Five boys are sitting in a circle facing inward. Ajay is between Rohit and Doljit. Suman is at the left of Shyamal, Rohit is at the left of Suman. Who is sitting at the immediate right of Ajay?
Q1. Five boys are sitting in a circle facing inward. Ajay is between Rohit and Doljit. Suman is at the left of Shyamal, Rohit is at the left of Suman. Who is sitting at the immediate right of Ajay?
(A) Suman
(A) Suman
(A) Suman
(B) Shyamal
(B) Shyamal
(B) Shyamal
(C) Rohit
(C) Rohit
(C) Rohit
(D) Doljit
(D) Doljit
(D) Doljit
Answer: (C) Rohit
Answer: (C) Rohit
Answer: (C) Rohit
Rohit
Rohit
Rohit
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Q2. Find the best option to fill in the last term: CIRCLE : GEOMETRY :: POETRY : ?
Q2. Find the best option to fill in the last term: CIRCLE : GEOMETRY :: POETRY : ?
(A) CHAPTER
(A) CHAPTER
(A) CHAPTER
(B) BOOKS
(B) BOOKS
(B) BOOKS
(C) PROSE
(C) PROSE
(C) PROSE
(D) LANGUAGE
(D) LANGUAGE
(D) LANGUAGE
Answer: (B) BOOKS
Answer: (B) BOOKS
Answer: (B) BOOKS
BOOKS
BOOKS
BOOKS
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Q3. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
Q3. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
(A) 13
(A) 13
(A) 13
(B) 11
(B) 11
(B) 11
(C) 16
(C) 16
(C) 16
(D) 9
(D) 9
(D) 9
Answer: (A) 13
Answer: (A) 13
Answer: (A) 13
The smallest number amongst them is 13
=> X + (X+2) + (X+4) + (X+6) = 64
=> 4X + 12 = 64
=> 4X = 64 - 12
=> 4X = 52
=> X = 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13
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Q4. What is the name of the mathematical concept that describes a value that never changes, like the ratio of a circle's circumference to its diameter?
Q4. What is the name of the mathematical concept that describes a value that never changes, like the ratio of a circle's circumference to its diameter?
(A) Variable
(A) Variable
(A) Variable
(B) Constant
(B) Constant
(B) Constant
(C) Fraction
(C) Fraction
(C) Fraction
(D) Decimal
(D) Decimal
(D) Decimal
Answer: (B) Constant
Answer: (B) Constant
Answer: (B) Constant
A constant is a mathematical concept that represents a value that remains unchanged, like pi (π), which is approximately 3.14 and never changes.
A constant is a mathematical concept that represents a value that remains unchanged, like pi (π), which is approximately 3.14 and never changes.
A constant is a mathematical concept that represents a value that remains unchanged, like pi (π), which is approximately 3.14 and never changes.
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Q5. If ROBOTICS is coded as OROBITSC, then PROJECTS would be coded as
Q5. If ROBOTICS is coded as OROBITSC, then PROJECTS would be coded as
(A) ROPEJTSC
(A) ROPEJTSC
(A) ROPEJTSC
(B) RPJOCEST
(B) RPJOCEST
(B) RPJOCEST
(C) RPJOECST
(C) RPJOECST
(C) RPJOECST
(D) ROJPCEST
(D) ROJPCEST
(D) ROJPCEST
Answer: (B) RPJOCEST
Answer: (B) RPJOCEST
Answer: (B) RPJOCEST
ROBOTICS :: PROJECTS
OROBITSC :: RPJOCEST
ROBOTICS :: PROJECTS OROBITSC :: RPJOCEST
ROBOTICS :: PROJECTS OROBITSC :: RPJOCEST
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Q6. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Q6. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
(A) 60 years
(A) 60 years
(A) 60 years
(B) 51 years
(B) 51 years
(B) 51 years
(C) 48 years
(C) 48 years
(C) 48 years
(D) 45 years
(D) 45 years
(D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
The son becomes 15 years old after 3 years.
Hence son's present age = 15 years - 3 years = 12 years
Man is four times as old as his son.
Hence Man's present age = 12 years * 4 = 48 years
Man is 3 years older than his wife.
Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
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Q7. A number is as much greater than 31 as is less 55. Then the number is
Q7. A number is as much greater than 31 as is less 55. Then the number is
(A) 39
(A) 39
(A) 39
(B) 32
(B) 32
(B) 32
(C) 43
(C) 43
(C) 43
(D) 47
(D) 47
(D) 47
Answer: (C) 43
Answer: (C) 43
Answer: (C) 43
43
43
43
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Q8. What is the term for the result of multiplying a number by itself?
Q8. What is the term for the result of multiplying a number by itself?
(A) Factor
(A) Factor
(A) Factor
(B) Product
(B) Product
(B) Product
(C) Quotient
(C) Quotient
(C) Quotient
(D) Square
(D) Square
(D) Square
Answer: (D) Square
Answer: (D) Square
Answer: (D) Square
The result of multiplying a number by itself is called a square, such as 4 × 4 = 16, which is denoted as 42 (four squared).
The result of multiplying a number by itself is called a square, such as 4 × 4 = 16, which is denoted as 42 (four squared).
The result of multiplying a number by itself is called a square, such as 4 × 4 = 16, which is denoted as 42 (four squared).
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Q9. What is the term for a number that can be divided by 2?
Q9. What is the term for a number that can be divided by 2?
(A) Prime number
(A) Prime number
(A) Prime number
(B) Odd number
(B) Odd number
(B) Odd number
(C) Even number
(C) Even number
(C) Even number
(D) Fraction
(D) Fraction
(D) Fraction
Answer: (C) Even number
Answer: (C) Even number
Answer: (C) Even number
An even number is a whole number that is divisible by 2, such as 4, 6, or 8.
An even number is a whole number that is divisible by 2, such as 4, 6, or 8.
An even number is a whole number that is divisible by 2, such as 4, 6, or 8.
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Q10. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q10. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
(A) 1.5 km
(A) 1.5 km
(A) 1.5 km
(B) 1.75 km
(B) 1.75 km
(B) 1.75 km
(C) 1.2 km
(C) 1.2 km
(C) 1.2 km
(D) 1.25 km
(D) 1.25 km
(D) 1.25 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
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