A ladder of length 13 m is leaning against a vertical wall with the upper end at the height of 5 m. The horizontal distance between the foot of the wall and the lower end of the ladder is [#1711]

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Q1. A ladder of length 13 m is leaning against a vertical wall with the upper end at the height of 5 m. The horizontal distance between the foot of the wall and the lower end of the ladder is
Q1. A ladder of length 13 m is leaning against a vertical wall with the upper end at the height of 5 m. The horizontal distance between the foot of the wall and the lower end of the ladder is

(A) 9m
(A) 9m

(B) 5m
(B) 5m

(D) 12m
(D) 12m

Answer: (D) 12m
Answer: (D) 12m

5² + X² = 13² => 25 + X² = 169 => X² = 196 - 25 => X² = 144 => X = 12

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Q1. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is
Q1. A certain amount invested in a firm would become double at the end of one month, but it deducts an amount of ₹120 on every doubling. A person invests an amount of ₹105 and continues for 3 months without investing any additional amount. At the end of 3 months, his net income is

(A) 55
(A) 55

(B) 0
(B) 0

(D) 45
(D) 45

Answer: (B) 0
Answer: (B) 0

1st Month -> (105 * 2) - 120 = 210 - 120 = 90 2nd Month -> (90 * 2) - 120 = 180 - 120 = 60 3rd Month -> (60 * 2) - 120 = 120 - 120 = 0

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Q2. The sum of first 6 prime numbers is
Q2. The sum of first 6 prime numbers is

(A) 40
(A) 40

(B) 43
(B) 43

(D) 42
(D) 42

Answer: (C) 41
Answer: (C) 41

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Q3. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is
Q3. Two numbers are in the ratio of 2 : 3 and the product of their LCM and HCF is 96. The sum of the numbers is

(A) 8
(A) 8

(B) 12
(B) 12

(D) 36
(D) 36

Answer: (C) 20
Answer: (C) 20

=> 2x * 3x = 96 => 6x² = 96 => x² = 96/6 => x² = 16 => x = 4 2x + 3x = 5x = 5 * 4 = 20

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Q4. If '÷' means ‘addition’, ‘+’ means ‘subtraction’, ‘–’ means ‘multiplication’ and ‘×’ means ‘division’, then the value of 18 ÷ 12 × 4 – 5 is
Q4. If '÷' means ‘addition’, ‘+’ means ‘subtraction’, ‘–’ means ‘multiplication’ and ‘×’ means ‘division’, then the value of 18 ÷ 12 × 4 – 5 is

(A) 25
(A) 25

(B) 35
(B) 35

(D) 33
(D) 33

Answer: (D) 33
Answer: (D) 33

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2024-04-13

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Q5. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be
Q5. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be

(A) 3
(A) 3

(B) 25
(B) 25

(D) 33
(D) 33

Answer: (C) 5
Answer: (C) 5

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Q6. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :
Q6. 45% of a number is same as 30% of another number. The ratio of the first number to the second number is :

(A) 2 : 3
(A) 2 : 3

(B) 3 : 5
(B) 3 : 5

(D) 2 : 5
(D) 2 : 5

Answer: (A) 2 : 3
Answer: (A) 2 : 3

\frac{45}{100} * X = \frac{30}{100} * Y

\frac{X}{Y} = \frac{30 * 100}{100 * 45}

\frac{X}{Y} = \frac{2}{3}

= X:Y = 2:3

\frac{45}{100} * X = \frac{30}{100} * Y

\frac{X}{Y} = \frac{30 * 100}{100 * 45}

\frac{X}{Y} = \frac{2}{3}

= X:Y = 2:3

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Q7. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :
Q7. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :

(A) 5,420
(A) 5,420

(B) 5,580
(B) 5,580

(D) 5,780
(D) 5,780

Answer: (B) 5,580
Answer: (B) 5,580

The formula for the sum of the first n terms of an arithmetic progression is

S_{n} = \frac{n}{2} (a + a n)

\frac{30}{2} (12 + 12 * 30)

= 15*(12+360) = 15 * 372 = 5580

The formula for the sum of the first n terms of an arithmetic progression is

S_{n} = \frac{n}{2} (a + a n)

\frac{30}{2} (12 + 12 * 30)

= 15*(12+360) = 15 * 372 = 5580

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Q8. The conversion of $0.0 \bar{37}$ in the fractional form is
Q8. The conversion of $0.0 \bar{37}$ in the fractional form is

(A)

\frac{37}{100}

(A)

\frac{37}{100}

(B)

\frac{37}{999}

(B)

\frac{37}{999}

(C)

\frac{37}{990}

(C)

\frac{37}{990}

(D)

\frac{37}{1000}

(D)

\frac{37}{1000}

Answer: (C)

\frac{37}{990}

Answer: (C)

\frac{37}{990}

\frac{37}{990}

\frac{37}{990}

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Q9. The value of $\sqrt{0.04} + \sqrt{1.44} + \sqrt{1.69} + \sqrt{0.0009}$ is :
Q9. The value of $\sqrt{0.04} + \sqrt{1.44} + \sqrt{1.69} + \sqrt{0.0009}$ is :

(A) 1.73
(A) 1.73

(B) 2.03
(B) 2.03

(D) 1.03
(D) 1.03

Answer: (C) 2.73
Answer: (C) 2.73

\sqrt{0.04} + \sqrt{1.44} + \sqrt{1.69} + \sqrt{0.0009}

\sqrt{0.02*0.02} + \sqrt{1.2*1.2} + \sqrt{1.3*1.3} + \sqrt{0.03*0.03}

= 0.2 + 1.2 + 1.3 + 0.03 = 2.73

\sqrt{0.04} + \sqrt{1.44} + \sqrt{1.69} + \sqrt{0.0009}

\sqrt{0.02*0.02} + \sqrt{1.2*1.2} + \sqrt{1.3*1.3} + \sqrt{0.03*0.03}

= 0.2 + 1.2 + 1.3 + 0.03 = 2.73

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Q10. A person moves along a path such that he is always away from a given point by 7 m. After moving for some time, he again reaches his starting point. The approximate distance the person moved during the time is
Q10. A person moves along a path such that he is always away from a given point by 7 m. After moving for some time, he again reaches his starting point. The approximate distance the person moved during the time is

(A) 22 m
(A) 22 m

(B) 44 m
(B) 44 m

(D) 144 m
(D) 144 m

Answer: (B) 44 m
Answer: (B) 44 m

2 *

\frac{22}{7}

* 7 = 2 * 22 = 44

2 *

\frac{22}{7}

* 7 = 2 * 22 = 44

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A ladder of length 13 m is leaning against a vertical wall with the upper end at the height of 5 m. The horizontal distance between the foot of the wall and the lower end of the ladder is [#1711]

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Q2. The sum of first 6 prime numbers is

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