The value of $\sqrt[3]{8^{2}}$ is [#1694]

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Q1. The value of $\sqrt[3]{8^{2}}$ is
Q1. The value of $\sqrt[3]{8^{2}}$ is

(A) 1
(A) 1

(B) 3
(B) 3

(D) 4
(D) 4

Answer: (D) 4
Answer: (D) 4

\sqrt[3]{8^{2}}

\sqrt[3]{64}

\sqrt[3]{4^{3}}

= 4

\sqrt[3]{8^{2}}

\sqrt[3]{64}

\sqrt[3]{4^{3}}

= 4

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@1694

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2024-10-23

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34p5 -> 3+4+p+5 = 12+p 12+p = 9k 12+6 = 18 = 9k p = 6

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Q3. The product of two consecutive odd numbers is 19043. Which is the smaller number?
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137

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Q4. Consider the four numbers given numbers. If the digits of each number are arranged in ascending order, which new number would be the smallest?
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376 -> 367 629 -> 269 921 -> 129 * 397 -> 379

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A pentagon is a polygon with five sides, like the shape of the Pentagon building in Washington, D.C.

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Q7. 3/4 of a number is 19 less than the original number. The number is
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Q8. Find the value of $\sqrt{\frac{225}{729}} - \sqrt{\frac{25}{144}} - \sqrt{\frac{16}{81}}$
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(A)

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(A)

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\frac{- 11}{36}

Answer: (D)

\frac{- 11}{36}

Answer: (D)

\frac{- 11}{36}

\sqrt{\frac{225}{729}} - \sqrt{\frac{25}{144}} - \sqrt{\frac{16}{81}}

\sqrt{\frac{15 * 15}{27 * 27}} - \sqrt{\frac{5 * 5}{12 * 12}} - \sqrt{\frac{4 * 4}{9 * 9}}

\frac{15}{27} - \frac{5}{12} - \frac{4}{9}

\frac{60 - 45 - 48}{108}

\frac{- 33}{108}

\frac{- 11}{36}

\sqrt{\frac{225}{729}} - \sqrt{\frac{25}{144}} - \sqrt{\frac{16}{81}}

\sqrt{\frac{15 * 15}{27 * 27}} - \sqrt{\frac{5 * 5}{12 * 12}} - \sqrt{\frac{4 * 4}{9 * 9}}

\frac{15}{27} - \frac{5}{12} - \frac{4}{9}

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\frac{- 33}{108}

\frac{- 11}{36}

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The value of $\sqrt[3]{8^{2}}$ is [#1694]

Q1. The value of $\sqrt[3]{8^{2}}$ is
Q1. The value of $\sqrt[3]{8^{2}}$ is

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Q1. The least number by which 2450 must be multiplied to make it a perfect square, is

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Q3. The product of two consecutive odd numbers is 19043. Which is the smaller number?

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