A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be : [#1119]

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Q1. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :
Q1. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :

(A) 5,420
(A) 5,420

(B) 5,580
(B) 5,580

(D) 5,780
(D) 5,780

Answer: (B) 5,580
Answer: (B) 5,580

The formula for the sum of the first n terms of an arithmetic progression is

S_{n} = \frac{n}{2} (a + a n)

\frac{30}{2} (12 + 12 * 30)

= 15*(12+360) = 15 * 372 = 5580

The formula for the sum of the first n terms of an arithmetic progression is

S_{n} = \frac{n}{2} (a + a n)

\frac{30}{2} (12 + 12 * 30)

= 15*(12+360) = 15 * 372 = 5580

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