98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was [#1112]
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Q1. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
Q1. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
(A) 5
(A) 5
(A) 5
(B) 7
(B) 7
(B) 7
(C) 10
(C) 10
(C) 10
(D) 14
(D) 14
(D) 14
Answer: (B) 7
Answer: (B) 7
Answer: (B) 7
7
=> x * 2x = 98
=> x2 =
=> x2 = 49
=> x = 7
7 => x * 2x = 98 => x2 = => x2 = 49 => x = 7
7 => x * 2x = 98 => x2 = => x2 = 49 => x = 7
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Related MCQ Quizzes
Q1. If 20% of a is b, then b% of 20 is the same as :
Q1. If 20% of a is b, then b% of 20 is the same as :
(A) 4% of a
(A) 4% of a
(A) 4% of a
(B) 8% of a
(B) 8% of a
(B) 8% of a
(C) 6% of a
(C) 6% of a
(C) 6% of a
(D) 10% of a
(D) 10% of a
(D) 10% of a
Answer: (A) 4% of a
Answer: (A) 4% of a
Answer: (A) 4% of a
20% of a is b
Hence b = 20% of a = 20a/100
b% of 20
= 20% of b
= (20/100) * 20a/100
= (20*20*a)/(100*100)
= 4a/100
= (4/100) * a
= 4% of a
20% of a is b Hence b = 20% of a = 20a/100 b% of 20 = 20% of b = (20/100) * 20a/100 = (20*20*a)/(100*100) = 4a/100 = (4/100) * a = 4% of a
20% of a is b Hence b = 20% of a = 20a/100 b% of 20 = 20% of b = (20/100) * 20a/100 = (20*20*a)/(100*100) = 4a/100 = (4/100) * a = 4% of a
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Q2. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is
Q2. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is
(A) 1
(A) 1
(A) 1
(B) -1
(B) -1
(B) -1
(C) 2
(C) 2
(C) 2
(D) 3
(D) 3
(D) 3
Answer: (C) 2
Answer: (C) 2
Answer: (C) 2
In ascending order = -2, -1, 1, 2, 3, 5, 6
median = th term
= 4th term
= 2
In ascending order = -2, -1, 1, 2, 3, 5, 6 median = th term = 4th term = 2
In ascending order = -2, -1, 1, 2, 3, 5, 6 median = th term = 4th term = 2
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Q3. What is the formula to calculate the area of a circle?
Q3. What is the formula to calculate the area of a circle?
(A) A = πr2
(A) A = πr2
(A) A = πr2
(B) A = 2πr
(B) A = 2πr
(B) A = 2πr
(C) A = πd
(C) A = πd
(C) A = πd
(D) A = 1/2πr2
(D) A = 1/2πr2
(D) A = 1/2πr2
Answer: (A) A = πr2
Answer: (A) A = πr2
Answer: (A) A = πr2
The formula to calculate the area of a circle is A = πr2, where A is the area and r is the radius of the circle.
The formula to calculate the area of a circle is A = πr2, where A is the area and r is the radius of the circle.
The formula to calculate the area of a circle is A = πr2, where A is the area and r is the radius of the circle.
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Q4. The least number by which 2450 must be multiplied to make it a perfect square, is
Q4. The least number by which 2450 must be multiplied to make it a perfect square, is
(A) 2
(A) 2
(A) 2
(B) 3
(B) 3
(B) 3
(C) 4
(C) 4
(C) 4
(D) 5
(D) 5
(D) 5
Answer: (A) 2
Answer: (A) 2
Answer: (A) 2
2
2
2
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Q5. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is
Q5. A number was increased by 40% and thereafter decreased by 40%. The net change in the number in percentage is
(A) 16% increase
(A) 16% increase
(A) 16% increase
(B) 16% decrease
(B) 16% decrease
(B) 16% decrease
(C) 32% decrease
(C) 32% decrease
(C) 32% decrease
(D) No change
(D) No change
(D) No change
Answer: (B) 16% decrease
Answer: (B) 16% decrease
Answer: (B) 16% decrease
16% decrease
= 40-40-%
= -%
= -16%
16% decrease = 40-40-% = -% = -16%
16% decrease = 40-40-% = -% = -16%
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Q6. The product of two consecutive odd numbers is 19043. Which is the smaller number?
Q6. The product of two consecutive odd numbers is 19043. Which is the smaller number?
(A) 133
(A) 133
(A) 133
(B) 131
(B) 131
(B) 131
(C) 137
(C) 137
(C) 137
(D) 129
(D) 129
(D) 129
Answer: (C) 137
Answer: (C) 137
Answer: (C) 137
137
137
137
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Q7. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is
Q7. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is
(A) 25
(A) 25
(A) 25
(B) 45
(B) 45
(B) 45
(C) 32
(C) 32
(C) 32
(D) 27
(D) 27
(D) 27
Answer: (D) 27
Answer: (D) 27
Answer: (D) 27
27
27
27
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Q8. Three numbers are in the ratio 3:4:5. The sum of the largest and the smallest equals the sum of the third and 52. The smallest number is
Q8. Three numbers are in the ratio 3:4:5. The sum of the largest and the smallest equals the sum of the third and 52. The smallest number is
(A) 48
(A) 48
(A) 48
(B) 36
(B) 36
(B) 36
(C) 39
(C) 39
(C) 39
(D) 30
(D) 30
(D) 30
Answer: (C) 39
Answer: (C) 39
Answer: (C) 39
39
39
39
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Q9. The sum of first 6 prime numbers is
Q9. The sum of first 6 prime numbers is
(A) 40
(A) 40
(A) 40
(B) 43
(B) 43
(B) 43
(C) 41
(C) 41
(C) 41
(D) 42
(D) 42
(D) 42
Answer: (C) 41
Answer: (C) 41
Answer: (C) 41
41
41
41
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Q10. A number is as much greater than 22 as is less than 72. Then the number is
Q10. A number is as much greater than 22 as is less than 72. Then the number is
(A) 44
(A) 44
(A) 44
(B) 50
(B) 50
(B) 50
(C) 52
(C) 52
(C) 52
(D) 47
(D) 47
(D) 47
Answer: (D) 47
Answer: (D) 47
Answer: (D) 47
47
47
47
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