The LCM of two numbers is 40 and their HCF is 4. If the difference between the two numbers is 12, then the sum of the numbers is [#1087]

X * (X-12) = 40 * 4 X = 20 X + (X-12) = 20 + 20 - 12 = 28

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X * (X-12) = 40 * 4 X = 20 X + (X-12) = 20 + 20 - 12 = 28

6*4 = 24 8*3 = 24 12*2 = 24

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6*4 = 24 8*3 = 24 12*2 = 24

5

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5

P * $8\frac{1}{3}\%$ * 12 = P * $\frac{25}{3}\%$ * 12 = P * $\frac{300}{3}\%$ = P * 100%

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P * $8\frac{1}{3}\%$ * 12 = P * $\frac{25}{3}\%$ * 12 = P * $\frac{300}{3}\%$ = P * 100%

The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.

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The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.

A : B = 3 => $\frac{A}{B}$ = 3 $\frac{144A}{36B}$ = $\frac{144}{36}\times \frac{A}{B}$ = $\frac{144}{36}$ x 3 = 4 x 3 = 12

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A : B = 3 => $\frac{A}{B}$ = 3 $\frac{144A}{36B}$ = $\frac{144}{36}\times \frac{A}{B}$ = $\frac{144}{36}$ x 3 = 4 x 3 = 12

42 - (4*3) = 16 - 12 = 4

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4^{2 - (4*3) = 16 - 12 = 4}

71

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71

12 ---- x 60 = 48 KMPH 15

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12 ---- x 60 = 48 KMPH 15

2 Because, Reminder must be positive and it should be less then the divisor

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2 Because, Reminder must be positive and it should be less then the divisor

20% = $\frac{25}{100+25} * 100$% $\frac{25}{125} * 100$% = 20%

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20% = $\frac{25}{100+25} * 100$% $\frac{25}{125} * 100$% = 20%