The missing term in the sequence 7, 11, 19, 31, ______, 67 is [#1015]
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Q1. The missing term in the sequence 7, 11, 19, 31, ______, 67 is
Q1. The missing term in the sequence 7, 11, 19, 31, ______, 67 is
(A) 43
(A) 43
(A) 43
(B) 47
(B) 47
(B) 47
(C) 51
(C) 51
(C) 51
(D) 45
(D) 45
(D) 45
Answer: (B) 47
Answer: (B) 47
Answer: (B) 47
47
47
47
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Related MCQ Quizzes
Q1. The simple interest earned by 4,000 in 18 months at 12% per annum is
Q1. The simple interest earned by 4,000 in 18 months at 12% per annum is
(A) 216
(A) 216
(A) 216
(B) 720
(B) 720
(B) 720
(C) 360
(C) 360
(C) 360
(D) 960
(D) 960
(D) 960
Answer: (B) 720
Answer: (B) 720
Answer: (B) 720
720
720
720
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Q2. A wheel can cover a distance of 22 km in 1000 rounds. The radius of the wheel is
Q2. A wheel can cover a distance of 22 km in 1000 rounds. The radius of the wheel is
(A) 4.5 m
(A) 4.5 m
(A) 4.5 m
(B) 2.1 m
(B) 2.1 m
(B) 2.1 m
(C) 2.8 m
(C) 2.8 m
(C) 2.8 m
(D) 3.5 m
(D) 3.5 m
(D) 3.5 m
Answer: (D) 3.5 m
Answer: (D) 3.5 m
Answer: (D) 3.5 m
3.5 m
3.5 m
3.5 m
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Q3. What is the term for a angle greater than 90 degrees but less than 180 degrees?
Q3. What is the term for a angle greater than 90 degrees but less than 180 degrees?
(A) Acute angle
(A) Acute angle
(A) Acute angle
(B) Right angle
(B) Right angle
(B) Right angle
(C) Obtuse angle
(C) Obtuse angle
(C) Obtuse angle
(D) Straight angle
(D) Straight angle
(D) Straight angle
Answer: (C) Obtuse angle
Answer: (C) Obtuse angle
Answer: (C) Obtuse angle
An obtuse angle is an angle greater than 90 degrees but less than 180 degrees, like the angle formed by two walls that meet at a corner.
An obtuse angle is an angle greater than 90 degrees but less than 180 degrees, like the angle formed by two walls that meet at a corner.
An obtuse angle is an angle greater than 90 degrees but less than 180 degrees, like the angle formed by two walls that meet at a corner.
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Q4. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is
Q4. The difference of two numbers is 5 and the difference of their square is 135. Then the sum of the numbers is
(A) 25
(A) 25
(A) 25
(B) 45
(B) 45
(B) 45
(C) 32
(C) 32
(C) 32
(D) 27
(D) 27
(D) 27
Answer: (D) 27
Answer: (D) 27
Answer: (D) 27
27
27
27
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Q5. If REAR = 42, TEAR = 44 and DEAR = 28, then which of the following sets is incorrectly paired?
Q5. If REAR = 42, TEAR = 44 and DEAR = 28, then which of the following sets is incorrectly paired?
(A) PEAR = 40
(A) PEAR = 40
(A) PEAR = 40
(B) FEAR = 32
(B) FEAR = 32
(B) FEAR = 32
(C) BEAR = 26
(C) BEAR = 26
(C) BEAR = 26
(D) GEAR = 31
(D) GEAR = 31
(D) GEAR = 31
Answer: (B) FEAR = 32
Answer: (B) FEAR = 32
Answer: (B) FEAR = 32
FEAR = 32
REAR = 18+5+1+18 = 42
TEAR = 20+5+1+18 = 44
DEAR = 4+5+1+18 = 28
FEAR = 6+5+1+18 = 30
FEAR = 32 REAR = 18+5+1+18 = 42 TEAR = 20+5+1+18 = 44 DEAR = 4+5+1+18 = 28 FEAR = 6+5+1+18 = 30
FEAR = 32 REAR = 18+5+1+18 = 42 TEAR = 20+5+1+18 = 44 DEAR = 4+5+1+18 = 28 FEAR = 6+5+1+18 = 30
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Q6. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q6. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
(A) 1.5 km
(A) 1.5 km
(A) 1.5 km
(B) 1.75 km
(B) 1.75 km
(B) 1.75 km
(C) 1.2 km
(C) 1.2 km
(C) 1.2 km
(D) 1.25 km
(D) 1.25 km
(D) 1.25 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
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Q7. Which number will replace the blank in the following series 3, 7, 16, 35, _, 153 ?
Q7. Which number will replace the blank in the following series 3, 7, 16, 35, _, 153 ?
(A) 75
(A) 75
(A) 75
(B) 74
(B) 74
(B) 74
(C) 72
(C) 72
(C) 72
(D) 76
(D) 76
(D) 76
Answer: (B) 74
Answer: (B) 74
Answer: (B) 74
74
74
74
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Q8. In a school with 10 teachers, one retires and immediately a new teacher of age 25 years joins. As a result, the average age of the teacher reduces by 3. The age of the retired teacher is
Q8. In a school with 10 teachers, one retires and immediately a new teacher of age 25 years joins. As a result, the average age of the teacher reduces by 3. The age of the retired teacher is
(A) 55 years
(A) 55 years
(A) 55 years
(B) 65 years
(B) 65 years
(B) 65 years
(C) 58 years
(C) 58 years
(C) 58 years
(D) 60 years
(D) 60 years
(D) 60 years
Answer: (A) 55 years
Answer: (A) 55 years
Answer: (A) 55 years
25 years + (3*10) years = 55 years
25 years + (3*10) years = 55 years
25 years + (3*10) years = 55 years
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Q9. If 16℅ of 40℅ of a number is 8, then the number is
Q9. If 16℅ of 40℅ of a number is 8, then the number is
(A) 250
(A) 250
(A) 250
(B) 125
(B) 125
(B) 125
(C) 200
(C) 200
(C) 200
(D) 100
(D) 100
(D) 100
Answer: (B) 125
Answer: (B) 125
Answer: (B) 125
125
125
125
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Q10. Select the number pair in which the two numbers are related in the same way as 35 : 6.
Q10. Select the number pair in which the two numbers are related in the same way as 35 : 6.
(A) 85 : 9
(A) 85 : 9
(A) 85 : 9
(B) 64 : 8
(B) 64 : 8
(B) 64 : 8
(C) 26 : 5
(C) 26 : 5
(C) 26 : 5
(D) 120 : 11
(D) 120 : 11
(D) 120 : 11
Answer: (D) 120 : 11
Answer: (D) 120 : 11
Answer: (D) 120 : 11
62-1 : 6 = 35 : 6
112-1 : 11 = 120 : 11
62-1 : 6 = 35 : 6 112-1 : 11 = 120 : 11
62-1 : 6 = 35 : 6 112-1 : 11 = 120 : 11
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