The missing term in the sequence 7, 11, 19, 31, ______, 67 is [#1015]
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Q1. The missing term in the sequence 7, 11, 19, 31, ______, 67 is
Q1. The missing term in the sequence 7, 11, 19, 31, ______, 67 is
(A) 43
(A) 43
(A) 43
(B) 47
(B) 47
(B) 47
(C) 51
(C) 51
(C) 51
(D) 45
(D) 45
(D) 45
Answer: (B) 47
Answer: (B) 47
Answer: (B) 47
47
47
47
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Related MCQ Quizzes
Q1. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
Q1. ‘A’ starts his journey at 1:00 p.m. from a location P with a speed of 1 m/sec. ‘B’ starts his journey from the same location P and along the same direction at 1:10 p.m. with a speed of 2 m/sec. If ‘B’ meets ‘A’ at the location Q, then the distance PQ is :
(A) 1.5 km
(A) 1.5 km
(A) 1.5 km
(B) 1.75 km
(B) 1.75 km
(B) 1.75 km
(C) 1.2 km
(C) 1.2 km
(C) 1.2 km
(D) 1.25 km
(D) 1.25 km
(D) 1.25 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
Answer: (C) 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B
(10*60)s * 1m/s = 600m
Let A covers a distance of X after starting of B,
Then X + 600m = 2X
=> 2X - X = 600m
=> X = 600m
Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km
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Q2. In a zoo, the lion’s cage is towards the East of tiger’s cage. At the exact South of the lion’s cage, there is bear’s cage, which is towards the West of cheetah’s cage. In which direction is the tiger’s cage from the cheetah’s cage?
Q2. In a zoo, the lion’s cage is towards the East of tiger’s cage. At the exact South of the lion’s cage, there is bear’s cage, which is towards the West of cheetah’s cage. In which direction is the tiger’s cage from the cheetah’s cage?
(A) South-East
(A) South-East
(A) South-East
(B) North-West
(B) North-West
(B) North-West
(C) South-West
(C) South-West
(C) South-West
(D) East
(D) East
(D) East
Answer: (B) North-West
Answer: (B) North-West
Answer: (B) North-West
North-West
Tiger ------> Lion
|
| ⇱
| ⇱
| ⇱
V ⇱
Bear -------> Cheetah
North-West Tiger ------> Lion | | ⇱ | ⇱ | ⇱ V ⇱ Bear -------> Cheetah
North-West Tiger ------> Lion | | ⇱ | ⇱ | ⇱ V ⇱ Bear -------> Cheetah
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Q3. Five boys are sitting in a circle facing inward. Ajay is between Rohit and Doljit. Suman is at the left of Shyamal, Rohit is at the left of Suman. Who is sitting at the immediate right of Ajay?
Q3. Five boys are sitting in a circle facing inward. Ajay is between Rohit and Doljit. Suman is at the left of Shyamal, Rohit is at the left of Suman. Who is sitting at the immediate right of Ajay?
(A) Suman
(A) Suman
(A) Suman
(B) Shyamal
(B) Shyamal
(B) Shyamal
(C) Rohit
(C) Rohit
(C) Rohit
(D) Doljit
(D) Doljit
(D) Doljit
Answer: (C) Rohit
Answer: (C) Rohit
Answer: (C) Rohit
Rohit
Rohit
Rohit
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Q4. If '÷' means ‘addition’, ‘+’ means ‘subtraction’, ‘–’ means ‘multiplication’ and ‘×’ means ‘division’, then the value of 18 ÷ 12 × 4 – 5 is
Q4. If '÷' means ‘addition’, ‘+’ means ‘subtraction’, ‘–’ means ‘multiplication’ and ‘×’ means ‘division’, then the value of 18 ÷ 12 × 4 – 5 is
(A) 25
(A) 25
(A) 25
(B) 35
(B) 35
(B) 35
(C) 40
(C) 40
(C) 40
(D) 33
(D) 33
(D) 33
Answer: (D) 33
Answer: (D) 33
Answer: (D) 33
33
33
33
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Q5. AQRD : BRSE :: LMTJ : ________
Q5. AQRD : BRSE :: LMTJ : ________
(A) MNRK
(A) MNRK
(A) MNRK
(B) MNSK
(B) MNSK
(B) MNSK
(C) MNUK
(C) MNUK
(C) MNUK
(D) MMUK
(D) MMUK
(D) MMUK
Answer: (D) MMUK
Answer: (D) MMUK
Answer: (D) MMUK
AQRD : (A+1)(Q+1)(R+1)(D+1) = AQRD : BRSE
LMTJ = (L+1)(M+1)(T+1)(J+1) = LMTJ : MMUK
AQRD : (A+1)(Q+1)(R+1)(D+1) = AQRD : BRSE LMTJ = (L+1)(M+1)(T+1)(J+1) = LMTJ : MMUK
AQRD : (A+1)(Q+1)(R+1)(D+1) = AQRD : BRSE LMTJ = (L+1)(M+1)(T+1)(J+1) = LMTJ : MMUK
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Q6. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be
Q6. When a number is divided by 893 the remainder is 193. If the same number is divided by 47, the remainder will be
(A) 3
(A) 3
(A) 3
(B) 25
(B) 25
(B) 25
(C) 5
(C) 5
(C) 5
(D) 33
(D) 33
(D) 33
Answer: (C) 5
Answer: (C) 5
Answer: (C) 5
5
5
5
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Q7. Three numbers are in the ratio 3:4:5. The sum of the largest and the smallest equals the sum of the third and 52. The smallest number is
Q7. Three numbers are in the ratio 3:4:5. The sum of the largest and the smallest equals the sum of the third and 52. The smallest number is
(A) 48
(A) 48
(A) 48
(B) 36
(B) 36
(B) 36
(C) 39
(C) 39
(C) 39
(D) 30
(D) 30
(D) 30
Answer: (C) 39
Answer: (C) 39
Answer: (C) 39
39
39
39
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Q8. What is the term for a number that has no decimal places or fractional part?
Q8. What is the term for a number that has no decimal places or fractional part?
(A) Integer
(A) Integer
(A) Integer
(B) Fraction
(B) Fraction
(B) Fraction
(C) Decimal
(C) Decimal
(C) Decimal
(D) Percentage
(D) Percentage
(D) Percentage
Answer: (A) Integer
Answer: (A) Integer
Answer: (A) Integer
An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.
An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.
An integer is a whole number, either positive, negative, or zero, without a decimal or fractional part, such as 5, -3, or 0.
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Q9. The sum of first 6 prime numbers is
Q9. The sum of first 6 prime numbers is
(A) 40
(A) 40
(A) 40
(B) 43
(B) 43
(B) 43
(C) 41
(C) 41
(C) 41
(D) 42
(D) 42
(D) 42
Answer: (C) 41
Answer: (C) 41
Answer: (C) 41
41
41
41
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Q10. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :
Q10. A lady deposits money in her savings bank in such a way that every next day her deposit amount is ₹ 12 more than her previous day deposit. If she starts her deposit with ₹ 12 on the first day, the total amount deposited by Liza at the end of 30 days will be :
(A) 5,420
(A) 5,420
(A) 5,420
(B) 5,580
(B) 5,580
(B) 5,580
(C) 5,620
(C) 5,620
(C) 5,620
(D) 5,780
(D) 5,780
(D) 5,780
Answer: (B) 5,580
Answer: (B) 5,580
Answer: (B) 5,580
The formula for the sum of the first n terms of an arithmetic progression is
= 15*(12+360)
= 15 * 372
= 5580
The formula for the sum of the first n terms of an arithmetic progression is = 15*(12+360) = 15 * 372 = 5580
The formula for the sum of the first n terms of an arithmetic progression is = 15*(12+360) = 15 * 372 = 5580
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