The missing term in the sequence 7, 11, 19, 31, ______, 67 is [#1015]
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Q1. The missing term in the sequence 7, 11, 19, 31, ______, 67 is
Q1. The missing term in the sequence 7, 11, 19, 31, ______, 67 is
(A) 43
(A) 43
(A) 43
(B) 47
(B) 47
(B) 47
(C) 51
(C) 51
(C) 51
(D) 45
(D) 45
(D) 45
Answer: (B) 47
Answer: (B) 47
Answer: (B) 47
47
47
47
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Related MCQ Quizzes
Q1. The product of two consecutive odd numbers is 19043. Which is the smaller number?
Q1. The product of two consecutive odd numbers is 19043. Which is the smaller number?
(A) 133
(A) 133
(A) 133
(B) 131
(B) 131
(B) 131
(C) 137
(C) 137
(C) 137
(D) 129
(D) 129
(D) 129
Answer: (C) 137
Answer: (C) 137
Answer: (C) 137
137
137
137
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Q2. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
Q2. A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is :
(A) 60 years
(A) 60 years
(A) 60 years
(B) 51 years
(B) 51 years
(B) 51 years
(C) 48 years
(C) 48 years
(C) 48 years
(D) 45 years
(D) 45 years
(D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
Answer: (D) 45 years
The son becomes 15 years old after 3 years.
Hence son's present age = 15 years - 3 years = 12 years
Man is four times as old as his son.
Hence Man's present age = 12 years * 4 = 48 years
Man is 3 years older than his wife.
Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
The son becomes 15 years old after 3 years. Hence son's present age = 15 years - 3 years = 12 years Man is four times as old as his son. Hence Man's present age = 12 years * 4 = 48 years Man is 3 years older than his wife. Hence present age of his wife = 48 years - 3 years = 45 years.
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Q3. 4/5 of a number is 64. Then half of the number is
Q3. 4/5 of a number is 64. Then half of the number is
(A) 16
(A) 16
(A) 16
(B) 80
(B) 80
(B) 80
(C) 32
(C) 32
(C) 32
(D) 40
(D) 40
(D) 40
Answer: (D) 40
Answer: (D) 40
Answer: (D) 40
40
40
40
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Q4. Select the appropriate number to correctly continue the sequence 27, 30, 37, 50, ?, 98.
Q4. Select the appropriate number to correctly continue the sequence 27, 30, 37, 50, ?, 98.
(A) 69
(A) 69
(A) 69
(B) 73
(B) 73
(B) 73
(C) 81
(C) 81
(C) 81
(D) 91
(D) 91
(D) 91
Answer: (A) 69
Answer: (A) 69
Answer: (A) 69
69
69
69
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Q5. Five boys are sitting in a circle facing inward. Ajay is between Rohit and Doljit. Suman is at the left of Shyamal, Rohit is at the left of Suman. Who is sitting at the immediate right of Ajay?
Q5. Five boys are sitting in a circle facing inward. Ajay is between Rohit and Doljit. Suman is at the left of Shyamal, Rohit is at the left of Suman. Who is sitting at the immediate right of Ajay?
(A) Suman
(A) Suman
(A) Suman
(B) Shyamal
(B) Shyamal
(B) Shyamal
(C) Rohit
(C) Rohit
(C) Rohit
(D) Doljit
(D) Doljit
(D) Doljit
Answer: (C) Rohit
Answer: (C) Rohit
Answer: (C) Rohit
Rohit
Rohit
Rohit
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Q6. If today is Sunday, then the day after 92 days will be
Q6. If today is Sunday, then the day after 92 days will be
(A) Saturday
(A) Saturday
(A) Saturday
(B) Friday
(B) Friday
(B) Friday
(C) Sunday
(C) Sunday
(C) Sunday
(D) Monday
(D) Monday
(D) Monday
Answer: (D) Monday
Answer: (D) Monday
Answer: (D) Monday
-> Rem = 1
Sunday + 1 = Monday
-> Rem = 1 Sunday + 1 = Monday
-> Rem = 1 Sunday + 1 = Monday
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Q7. Q is the only sister of A, who is the only son of B. B’s wife is the daughter of P, who has only one son R. How is R related to Q?
Q7. Q is the only sister of A, who is the only son of B. B’s wife is the daughter of P, who has only one son R. How is R related to Q?
(A) Father-in-law
(A) Father-in-law
(A) Father-in-law
(B) Uncle
(B) Uncle
(B) Uncle
(C) Son
(C) Son
(C) Son
(D) Father
(D) Father
(D) Father
Answer: (B) Uncle
Answer: (B) Uncle
Answer: (B) Uncle
Uncle
Uncle
Uncle
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Q8. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will be
Q8. p, q, r are three numbers such that the LCM of p and q is q and the LCM of q and r is r. The LCM of p, q and r will be
(A) q
(A) q
(A) q
(B) r
(B) r
(B) r
(C) qr
(C) qr
(C) qr
(D) pqr
(D) pqr
(D) pqr
Answer: (B) r
Answer: (B) r
Answer: (B) r
LCM will be r.
px= q and qy = r, hence r = pxy.
LCM will be r. px= q and qy = r, hence r = pxy.
LCM will be r. px= q and qy = r, hence r = pxy.
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Q9. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
Q9. The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is
(A) 13
(A) 13
(A) 13
(B) 11
(B) 11
(B) 11
(C) 16
(C) 16
(C) 16
(D) 9
(D) 9
(D) 9
Answer: (A) 13
Answer: (A) 13
Answer: (A) 13
The smallest number amongst them is 13
=> X + (X+2) + (X+4) + (X+6) = 64
=> 4X + 12 = 64
=> 4X = 64 - 12
=> 4X = 52
=> X = 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13
The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13
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Q10. Shyam stored Rs 35 in the form of 1 rupee coin and 50 paise coins in the ratio 2 : 3. The number of 50 paise coins are
Q10. Shyam stored Rs 35 in the form of 1 rupee coin and 50 paise coins in the ratio 2 : 3. The number of 50 paise coins are
(A) 20
(A) 20
(A) 20
(B) 25
(B) 25
(B) 25
(C) 30
(C) 30
(C) 30
(D) 35
(D) 35
(D) 35
Answer: (C) 30
Answer: (C) 30
Answer: (C) 30
1*20 + 0.5*30 = 20+15 = 35
1*20 + 0.5*30 = 20+15 = 35
1*20 + 0.5*30 = 20+15 = 35
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Related Questions
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