The sum of the four consecutive alternate numbers is 64. The smallest number amongst them is [#1109]

The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13

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The smallest number amongst them is 13 => X + (X+2) + (X+4) + (X+6) = 64 => 4X + 12 = 64 => 4X = 64 - 12 => 4X = 52 => X = 13

43

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43

$\frac{45}{100}*X = \frac{30}{100} * Y$ = $\frac{X}{Y} = \frac{30*100}{100*45}$ = $\frac{X}{Y} = \frac{2}{3}$ = X:Y = 2:3

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$\frac{45}{100}*X = \frac{30}{100} * Y$ = $\frac{X}{Y} = \frac{30*100}{100*45}$ = $\frac{X}{Y} = \frac{2}{3}$ = X:Y = 2:3

1+3+5+7+9+11+13 = 49

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1+3+5+7+9+11+13 = 49

A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

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A starts journey before B at a speed of 1 m/s. Hence A will be ahead of B (10*60)s * 1m/s = 600m Let A covers a distance of X after starting of B, Then X + 600m = 2X => 2X - X = 600m => X = 600m Hence B will cover a distance of 2X = 2 * 600m = 1200m = 1.2 km

125

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125

42 - (4*3) = 16 - 12 = 4

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4^{2 - (4*3) = 16 - 12 = 4}

100 * 100% + 200 * 200% = $100\times \frac{100}{100} + 200 \times \frac{200}{100}$ = $\frac{10000}{100} + \frac{40000}{100}$ = 100 + 400 = 500

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100 * 100% + 200 * 200% = $100\times \frac{100}{100} + 200 \times \frac{200}{100}$ = $\frac{10000}{100} + \frac{40000}{100}$ = 100 + 400 = 500

An even number is a whole number that is divisible by 2, such as 4, 6, or 8.

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An even number is a whole number that is divisible by 2, such as 4, 6, or 8.

$\frac{3}{2}$ >$\frac{3}{2}\times \frac{4}{9}$ = $\frac{12}{18}$ = $\frac{2}{3}$

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$\frac{3}{2}$ >$\frac{3}{2}\times \frac{4}{9}$ = $\frac{12}{18}$ = $\frac{2}{3}$

6*4 = 24 8*3 = 24 12*2 = 24

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6*4 = 24 8*3 = 24 12*2 = 24