If the sum of five consecutive numbers is 190, then the lowest number amongst them is [#1027]

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Q1. If the sum of five consecutive numbers is 190, then the lowest number amongst them is
Q1. If the sum of five consecutive numbers is 190, then the lowest number amongst them is

(A) 40
(A) 40

(B) 19
(B) 19

(D) 36
(D) 36

Answer: (D) 36
Answer: (D) 36

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Q1. Three fourth of a number is more than two third of the number by 5. Then the number is
Q1. Three fourth of a number is more than two third of the number by 5. Then the number is

(A) 72
(A) 72

(B) 60
(B) 60

(D) 48
(D) 48

Answer: (B) 60
Answer: (B) 60

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Q2. In a school with 10 teachers, one retires and immediately a new teacher of age 25 years joins. As a result, the average age of the teacher reduces by 3. The age of the retired teacher is
Q2. In a school with 10 teachers, one retires and immediately a new teacher of age 25 years joins. As a result, the average age of the teacher reduces by 3. The age of the retired teacher is

(A) 55 years
(A) 55 years

(B) 65 years
(B) 65 years

(D) 60 years
(D) 60 years

Answer: (A) 55 years
Answer: (A) 55 years

25 years + (3*10) years = 55 years

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Q3. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was
Q3. 98 toffees were distributed to some boys in a group. Each boy in the group got twice as many of the toffees as the number of boys. The number of boys in the group was

(A) 5
(A) 5

(B) 7
(B) 7

(D) 14
(D) 14

Answer: (B) 7
Answer: (B) 7

7 => x * 2x = 98 => x² =

\frac{98}{2}

=> x² = 49 => x = 7

7 => x * 2x = 98 => x² =

\frac{98}{2}

=> x² = 49 => x = 7

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Q4. If 2^x = 32, then the value of x is
Q4. If 2^x = 32, then the value of x is

(A) 4
(A) 4

(B) 5
(B) 5

(D) 7
(D) 7

Answer: (B) 5
Answer: (B) 5

2⁵ = 2*2*2*2*2 = 32

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2024-10-23

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Q5. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to
Q5. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to

(A) 2
(A) 2

(B) 3
(B) 3

(D) 5
(D) 5

Answer: (A) 2
Answer: (A) 2

\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}

Hence, X:Y:Z = 3:4:7

\frac{X + Y + Z}{Z}

\frac{3 + 4 + 7}{7}

\frac{14}{7}

= 2

\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}

Hence, X:Y:Z = 3:4:7

\frac{X + Y + Z}{Z}

\frac{3 + 4 + 7}{7}

\frac{14}{7}

= 2

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2024-10-23

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Q6. The smallest among $\sqrt{\frac{1}{2}}, \sqrt{\frac{1}{3}}, \sqrt{\frac{1}{4}} a n d \sqrt{\frac{2}{3}}$ is
Q6. The smallest among $\sqrt{\frac{1}{2}}, \sqrt{\frac{1}{3}}, \sqrt{\frac{1}{4}} a n d \sqrt{\frac{2}{3}}$ is

(A)

\sqrt{\frac{1}{2}}

(A)

\sqrt{\frac{1}{2}}

(B)

\sqrt{\frac{1}{3}}

(B)

\sqrt{\frac{1}{3}}

(C)

\sqrt{\frac{1}{4}}

(C)

\sqrt{\frac{1}{4}}

(D)

\sqrt{\frac{2}{3}}

(D)

\sqrt{\frac{2}{3}}

Answer: (C)

\sqrt{\frac{1}{4}}

Answer: (C)

\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}}

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Q7. When the numerator of a fraction is multiplied by 4 and the denominator by 9, the fraction reverses. The fraction is
Q7. When the numerator of a fraction is multiplied by 4 and the denominator by 9, the fraction reverses. The fraction is

(A)

\frac{4}{5}

(A)

\frac{4}{5}

(B)

\frac{2}{3}

(B)

\frac{2}{3}

(C)

\frac{5}{4}

(C)

\frac{5}{4}

(D)

\frac{3}{2}

(D)

\frac{3}{2}

Answer: (D)

\frac{3}{2}

Answer: (D)

\frac{3}{2}

\frac{3}{2}

\frac{3}{2} \times \frac{4}{9}

\frac{12}{18}

\frac{2}{3}

\frac{3}{2}

\frac{3}{2} \times \frac{4}{9}

\frac{12}{18}

\frac{2}{3}

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Q8. Find the odd number - 15, 17, 6, 12.
Q8. Find the odd number - 15, 17, 6, 12.

(A) 6
(A) 6

(B) 12
(B) 12

(D) 17
(D) 17

Answer: (D) 17
Answer: (D) 17

17 which is a Prime number.

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Q9. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is
Q9. The median of the sequence of numbers 2, – 1, 3, 1, – 2, 5, 6 is

(A) 1
(A) 1

(B) -1
(B) -1

(D) 3
(D) 3

Answer: (C) 2
Answer: (C) 2

In ascending order = -2, -1, 1, 2, 3, 5, 6 median =

\frac{7 + 1}{2}

th term = 4th term = 2

In ascending order = -2, -1, 1, 2, 3, 5, 6 median =

\frac{7 + 1}{2}

th term = 4th term = 2

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Q10. The missing term in the sequence 7, 11, 19, 31, , 67 is
Q10. The missing term in the sequence 7, 11, 19, 31, , 67 is

(A) 43
(A) 43

(B) 47
(B) 47

(D) 45
(D) 45

Answer: (B) 47
Answer: (B) 47

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If the sum of five consecutive numbers is 190, then the lowest number amongst them is [#1027]

Q1. If the sum of five consecutive numbers is 190, then the lowest number amongst them isQ1. If the sum of five consecutive numbers is 190, then the lowest number amongst them is

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Related Questions

Q1. If the sum of five consecutive numbers is 190, then the lowest number amongst them is
Q1. If the sum of five consecutive numbers is 190, then the lowest number amongst them is

Q1. Three fourth of a number is more than two third of the number by 5. Then the number is
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Q5. If $\frac{X}{3} = \frac{Y}{4} = \frac{Z}{7}, t h e n \frac{X + Y + Z}{Z}$ is equal to

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Q7. When the numerator of a fraction is multiplied by 4 and the denominator by 9, the fraction reverses. The fraction is
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